AES Sub-Key Generation By Muhammad Naseem. Rotate Word 09CF4F3C.

Slides:

Advertisements

Similar presentations

CS5204 – Operating Systems 1 Authentication. CS 5204 – Operating Systems2 Authentication Digital signature validation proves:  message was not altered.

Advertisements

Minimum Spanning Trees (MSTs) Prim's Algorithm For each vertex not in the tree, keep track of the lowest cost edge that would connect it to the tree This.

Formal Verification of Hardware Support For Advanced Encryption Standard Anna Slobodová Centaur Technology This work was done while at Intel.

Week 3 - Wednesday.  What did we talk about last time?  DES  Started AES.

Recitation 8 – 3/25/02 Outline Dynamic Linking Review prior test questions 213 Course Staff Office Hours: See Posting.

Minimum Spanning Tree Sarah Brubaker Tuesday 4/22/8.

Fig. 16-CO, p Fig. 16-1, p. 450 Fig. 16-2, p. 450.

Multi-Method Dispatch Using Multiple Row Displacement Candy Pang, Wade Holst, Yuri Leontiev, and Duane Szafron ECOOP’99 Presented by: Irene Cheng Date:

Introduction to Computer Engineering by Richard E. Haskell Number Systems Module M3.1 Sections

Traveling Salesman Problems Repetitive Nearest-Neighbor and Cheapest-Link Algorithms Chapter: 6.

 The factorial function (n!)  Permutations  Combinations.

Advanced Unix 25 Oct 2005 An Introduction to IPsec.

Chapter 4 sections 1 and 2.  Fig. 1  Not connected  All vertices are even.  Fig. 2  Connected  All vertices are even.

SIGNIFICANCE LEVEL FOR TWO-TAILED TEST df

A Brief Summary and Demonstration of Hash functions Collisions July

AES (Advanced Encryption Standard) By- Sharmistha Roy M.Tech, CSE 1 st semester NIT, Agartala.

CS555Spring 2012/Topic 101 Cryptography CS 555 Topic 10: Block Cipher Security & AES.

Computing the chromatic number for block intersection graphs of Latin squares Ed Sykes CS 721 project McMaster University, December 2004 Slide 1.

Phrase-structure grammar A phrase-structure grammar is a quadruple G = (V, T, P, S) where V is a finite set of symbols called nonterminals, T is a set.

Chapter 11 – Counting Methods Intro to Counting Methods Section 11.1: Counting by Systematic Listing.

A Brief Summary and Demonstration of Hash functions Collisions June

Cryptography Lecture 17: Advanced Encryption Standard (AES) Piotr Faliszewski.

POLYNOMIALS. MULTIPLYING POLYNOMIALS REVIEW Polynomials:

AES Encryption FIPS 197, November 26, Bit Block Encryption Key Lengths 128, 192, 256 Number of Rounds Key Length Rounds Block.

A horse race has the following horses running. How many different first, second and third place results are possible: Mushroom Pepper Sausage Tomato Onion.

A Valentines Day Problem Source The teachers lab Patterns in Mathematics

ECE Prof. John A. Copeland fax Office: GCATT Bldg.

OUTLINE 2 Pre-requisite Bomb! Pre-requisite Bomb! 3.

Michael Bordonaro, Christopher Chiaro, and Tobias May Experimental Design to Evaluate Directed Adaptive Mutation in Mammalian Cells.

Arcs and Chords Chapter Lesson 2 MI/Vocab central angle arc minor arc major arc semicircle Recognize major arcs, minor arcs, semicircles, and central.

Secret Key Systems (block encoding) Encrypting a small block of text (say 64 bits) General considerations for cipher design:

VideoGameAudio.com info {at} VideoGameAudio.com SIAT – Simon Fraser University Surrey, BC 1 Video Game Audio Leonard J. Paul VideoGameAudio.c om.

Sequential Pattern Mining

Chapter 9 Deductive Geometry in Circles

or call for office visit, or call Kathy Cheek,

6.2 Properties of Parallelograms

The Polar Environmental Centre

Secret Key Systems (block encoding)

2.5 Distributive Review Prize Show

Combinations COURSE 3 LESSON 11-3

Mid-point Theorem and Intercept Theorem

It’s a powerpoint! SWEET!

The Advanced Encryption Standard: Rijndael

Prepare data for Microdeletion

Make an Organized List and Simulate a Problem

Directed Graphs (Part II)

Single Source Shortest Paths Bellman-Ford Algorithm

Geometry Proofs Unit 12 AA1.CC.

Rotors and Secret-Key Encryption

ORC Is Necessary at the Interphase-to-Mitosis Transition to Recruit cdc2 Kinase and Disassemble RPA Foci Olivier Cuvier, Malik Lutzmann, Marcel Méchali

Data Warehousing Mining & BI

Geometry/Trig Name: __________________________

AB AC AD AE AF 5 ways If you used AB, then, there would be 4 remaining ODD vertices (C, D, E and F) CD CE CF 3 ways If you used CD, then, there.

Exploring Partially ordered sets

A Series of Slides in 5 Parts Movement 2. BFS

Latin Square Designs.

Do Now: If DA =7, find EA and DE If DF =28, find AB If AB= 9, find DF

Kruskal’s Algorithm AQR.

If AD = 10, DC =6, and ED = 15, find DB.

Find the value of g. Find the value of h. 105° h g 75°

刘振上海交通大学计算机科学与工程系电信群楼3-509

A Series of Slides in 5 Parts Movement 4. Best-First

A Series of Slides in 5 Parts Movement 4. Best-First

A Series of Slides in 5 Parts Movement 1. DFS

A Series of Slides in 5 Parts Movement 3. IDFS

Advanced Encryption Standard (AES)

Presentation transcript:

AES Sub-Key Generation By Muhammad Naseem

Rotate Word 09CF4F3C

Rotate Word 09CF4F3C 09CF4F3C09

Rotate Word 09CF4F3C 09CF4F3C09 CF4F3CCF09

Rotate Word 09CF4F3C 09CF4F3C09 CF4F3CCF09 CF4F3CCF4F09

Rotate Word 09CF4F3C 09CF4F3C09 CF4F3CCF09 CF4F3CCF4F09 CF4F3CCF4F3C09

Sub Word ABCDEF 0637C777BF26B6FC BFED7AB76 1CA82C97DFA5947F0ADD4A2AF9CA472C0 2B7FD FF7CC34A5E5F171D C723C A071280E2EB27B C1A1B6E5AA0523BD6B329E32F84 553D100ED20FCB15B6ACBBE394A4C58CF 6D0EFAAFB434D338545F9027F503C9FA8 751A3408F929D38F5BCB6DA2110FFF3D2 8CD0C13EC5F974417C4A77E3D645D FDC222A908846EEB814DE5E0BDB AE0323A0A CC2D3AC629195E479 BE7C8376D8DD54EA96C56F4EA657AAE08 CBA78252E1CA6B4C6E8DD741F4BBD8B8A D703EB F60E613557B986C11D9E EE1F D98E949B1E87E9CE5528DF F8CA1890DBFE D0FB054BB16 CF4F3C098A

Sub Word ABCDEF 0637C777BF26B6FC BFED7AB76 1CA82C97DFA5947F0ADD4A2AF9CA472C0 2B7FD FF7CC34A5E5F171D C723C A071280E2EB27B C1A1B6E5AA0523BD6B329E32F84 553D100ED20FCB15B6ACBBE394A4C58CF 6D0EFAAFB434D338545F9027F503C9FA8 751A3408F929D38F5BCB6DA2110FFF3D2 8CD0C13EC5F974417C4A77E3D645D FDC222A908846EEB814DE5E0BDB AE0323A0A CC2D3AC629195E479 BE7C8376D8DD54EA96C56F4EA657AAE08 CBA78252E1CA6B4C6E8DD741F4BBD8B8A D703EB F60E613557B986C11D9E EE1F D98E949B1E87E9CE5528DF F8CA1890DBFE D0FB054BB16 CF4F3C098A84

Sub Word ABCDEF 0637C777BF26B6FC BFED7AB76 1CA82C97DFA5947F0ADD4A2AF9CA472C0 2B7FD FF7CC34A5E5F171D C723C A071280E2EB27B C1A1B6E5AA0523BD6B329E32F84 553D100ED20FCB15B6ACBBE394A4C58CF 6D0EFAAFB434D338545F9027F503C9FA8 751A3408F929D38F5BCB6DA2110FFF3D2 8CD0C13EC5F974417C4A77E3D645D FDC222A908846EEB814DE5E0BDB AE0323A0A CC2D3AC629195E479 BE7C8376D8DD54EA96C56F4EA657AAE08 CBA78252E1CA6B4C6E8DD741F4BBD8B8A D703EB F60E613557B986C11D9E EE1F D98E949B1E87E9CE5528DF F8CA1890DBFE D0FB054BB16 CF4F3C098A84EB

Sub Word ABCDEF 0637C777BF26B6FC BFED7AB76 1CA82C97DFA5947F0ADD4A2AF9CA472C0 2B7FD FF7CC34A5E5F171D C723C A071280E2EB27B C1A1B6E5AA0523BD6B329E32F84 553D100ED20FCB15B6ACBBE394A4C58CF 6D0EFAAFB434D338545F9027F503C9FA8 751A3408F929D38F5BCB6DA2110FFF3D2 8CD0C13EC5F974417C4A77E3D645D FDC222A908846EEB814DE5E0BDB AE0323A0A CC2D3AC629195E479 BE7C8376D8DD54EA96C56F4EA657AAE08 CBA78252E1CA6B4C6E8DD741F4BBD8B8A D703EB F60E613557B986C11D9E EE1F D98E949B1E87E9CE5528DF F8CA1890DBFE D0FB054BB16 CF4F3C098A84EB01

Calculate Rcon value For word w 4 Rcon =0100 For word w 8 Rcon =0200 For word w 12 Rcon = For word w 16 Rcon = For word w 20 Rcon = For word w 24 Rcon = For word w 28 Rcon = For word w 32 Rcon = For word w 36 Rcon = For word w 40 Rcon = (01) 16 ( ) 2 Perform Left Shift ( ) 2 (02) 16

Calculate Rcon value For word w 4 Rcon =0100 For word w 8 Rcon =0200 For word w 12 Rcon =0400 For word w 16 Rcon = For word w 20 Rcon = For word w 24 Rcon = For word w 28 Rcon = For word w 32 Rcon = For word w 36 Rcon = For word w 40 Rcon = (02) 16 ( ) 2 Perform Left Shift ( ) 2 (04) 16

Calculate Rcon value For word w 4 Rcon =0100 For word w 8 Rcon =0200 For word w 12 Rcon =0400 For word w 16 Rcon =0800 For word w 20 Rcon = For word w 24 Rcon = For word w 28 Rcon = For word w 32 Rcon = For word w 36 Rcon = For word w 40 Rcon = (04) 16 ( ) 2 Perform Left Shift ( ) 2 (08) 16

Calculate Rcon value For word w 4 Rcon =0100 For word w 8 Rcon =0200 For word w 12 Rcon =0400 For word w 16 Rcon =0800 For word w 20 Rcon =1000 For word w 24 Rcon = For word w 28 Rcon = For word w 32 Rcon = For word w 36 Rcon = For word w 40 Rcon = (08) 16 ( ) 2 Perform Left Shift ( ) 2 (10) 16

Calculate Rcon value For word w 4 Rcon =0100 For word w 8 Rcon =0200 For word w 12 Rcon =0400 For word w 16 Rcon =0800 For word w 20 Rcon =1000 For word w 24 Rcon =2000 For word w 28 Rcon = For word w 32 Rcon = For word w 36 Rcon = For word w 40 Rcon = (10) 16 ( ) 2 Perform Left Shift ( ) 2 (20) 16

Calculate Rcon value For word w 4 Rcon =0100 For word w 8 Rcon =0200 For word w 12 Rcon =0400 For word w 16 Rcon =0800 For word w 20 Rcon =1000 For word w 24 Rcon =2000 For word w 28 Rcon =4000 For word w 32 Rcon = For word w 36 Rcon = For word w 40 Rcon = (20) 16 ( ) 2 Perform Left Shift ( ) 2 (40) 16

Calculate Rcon value For word w 4 Rcon =0100 For word w 8 Rcon =0200 For word w 12 Rcon =0400 For word w 16 Rcon =0800 For word w 20 Rcon =1000 For word w 24 Rcon =2000 For word w 28 Rcon =4000 For word w 32 Rcon =8000 For word w 36 Rcon = For word w 40 Rcon = (40) 16 ( ) 2 Perform Left Shift ( ) 2 (80) 16

Calculate Rcon value For word w 4 Rcon =0100 For word w 8 Rcon =0200 For word w 12 Rcon =0400 For word w 16 Rcon =0800 For word w 20 Rcon =1000 For word w 24 Rcon =2000 For word w 28 Rcon =4000 For word w 32 Rcon =8000 For word w 36 Rcon =1B00 For word w 40 Rcon = (80) 16 ( ) 2 Perform Left Shift ( ) 2 ( ) 2 ================= ( ) 2 (1B) 16 XOR

Calculate Rcon value For word w 4 Rcon =0100 For word w 8 Rcon =0200 For word w 12 Rcon =0400 For word w 16 Rcon =0800 For word w 20 Rcon =1000 For word w 24 Rcon =2000 For word w 28 Rcon =4000 For word w 32 Rcon =8000 For word w 36 Rcon =1B00 For word w 40 Rcon =3600 (1B) 16 ( ) 2 Perform Left Shift ( ) 2 (36) 16