Chapter 7: Work (Ewen et al. 2005) Objectives: Define power and solve power problems Define power and solve power problems.

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Presentation transcript:

Chapter 7: Work (Ewen et al. 2005) Objectives: Define power and solve power problems Define power and solve power problems

 Power is the rate of doing work; how fast work is done.  Units for work?  1 Watt (W) = 1 J/s  ft lb/s  1 horsepower (hp) = 550 ft lb/s = ft lb/mi

 A freight elevator operator weighs 5.00 E3 N. If it is raised to a height of 15.0 m in 10.0 s, how much power is developed?  Ans: 7500 Nm/s, or 7500 J/s, or 7500 W, or 7.50 kW

 The power expended in lifting an 825 lb girder to the top of a building 1.00 E2 ft high is 10.0 hp. How much time is required to raise the girder?  Ans: 15.0 s

 The mass of a large steel wrecking ball is 2.00 E3 kg. What power is used to raise it to a height of 40.0 m if the work is done in 20.0 s.  Ans: W or 39.2 kW

 A machine is designed to perform a given amount of work in a given amount of time. A second machine does the same amount of work in half the time. Find the power of the second machine compared with the first.  Ans: 2P

 A motor is capable of developing 10.0 kW of power. How large a mass can it lift 75.0 m in 20.0 s?  Ans: 272 kg

 A pump is needed to lift 1.50 E3 L of water per minute a distance of 45.0 m. What power, in KW, must the pump be able to deliver? (1 L of water = 1 kg of water)  Ans: 11.0 kW

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