STOICHIMETRY Limiting Reagents

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Presentation transcript:

STOICHIMETRY Limiting Reagents AMY MARKS

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + HCL -> MgCl2 + H2

First step? What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + HCL -> MgCl2 + H2 Balance Equation Call Mr. Kirk End it all now

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? CORRECT! The balanced equation is now Mg + 2HCl -> MgCl2 + H2

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + 2HCl -> MgCl2 + H2 You’re getting there…What to do now? Find the STP Convert grams to moles Put given over 1

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + 2HCl -> MgCl2 + H2 50.0g Mg 1 ? x 24.3g Mg 1 mol Mg 1 mol Mg 24.3g Mg 6.02x10^23 1 mol Mg

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + 2HCl -> MgCl2 + H2 50.0g Mg 1 1 mol Mg 24.3g Mg ? x x 1 mol H2 1 mol Mg 1 mol Mg 22.4 L 1 mol Mg 1 mol H2

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + 2HCl -> MgCl2 + H2 50.0g Mg 1 1 mol Mg 24.3g mg 1 mol H2 1 mol Mg x x x ? 1 mol H2 22.4 L Just stop  22.4 L 1 mol H2

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + 2HCl -> MgCl2 + H2 50.0g Mg x 1 mol Mg x 1 mol H2 x 22.4 L 1 24.3g Mg 1 mol Mg 1 mol H2 = ? 46.1 L H2 4.61 L H2 461 L H2

You’re not done.. Continue on to 2nd half of the problem.

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + 2HCl -> MgCl2 + H2 75g HCl 1 mol 1 75g HCl What is the first step? 75g HCl 1

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? 75g HCl 1 x ? 1 mol Mg 1 mol HCl 1 mol HCl 36.5g HCl 36.5g HCl 1 mol HCl

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + 2HCl -> MgCl2 + H2 75g HCl x 1 mol HCl x ? 1 36.5g HCl 2 mol HCl __________ 1 mol H2 1 mol H2 __________ 1 1 mol H2 __________ 2 mol HCl

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + 2HCl -> MgCl2 + H2 75g HCl x 1 mol HCl x 1 mol H2 x ? 1 36.5g HCl 2 mol HCl Click me 1 mol H2 22.4 L 22.4 L 1 mol H2

What volume of hydrogen at STP is produced from the reaction of 50 What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + 2HCl -> MgCl2 + H2 75g HCl x 1 mol HCl x 1 mol H2 x 22.4 L H2 = ? 1 36.5g HCl 2 mol HCl 1 mol H2 23.0 L H2 23 L H2

YEAHHHH BUDDY you’re almost done. Close enough. Let’s go. What is the excess reagent of the equation?

Which do you pick? fail 50.0g 75g 23 L

EXCESS REAGENT cool, you got it. Mg + 2HCl -> MgCl2 + H2 23 L H2 x ? 1 1 mol H2 22.4 L H2 22.4 L H2 1 mol H2 Who cares.

Excess Reagent Cont.. Mg + 2HCl -> MgCl2 + H2 23L H2 x 1 mol H2 x ? ____ 2 mol 1 mol H2 ____ 1 mol Mg 1 mol Mg ____ 1 mol H2

WOOO. Got it right… Mg + 2HCl -> MgCl2 + H2 23L H2 x 1 mol H2 x 1 mol Mg x ? 1 22.4L H2 1 mol H2 24.3 g 1 mol Mg 1 mol Mg 24.3 g 2 mol Mg 44.6 g

Almost finished! Excess Reagent cont.. Mg + 2HCl -> MgCl2 + H2 23L H2 x 1 mol H2 x 1 mol Mg x 24.3Mg = ? 1 22.4L H2 1 mol H2 1 mol Mg 24 g 25 g 25.0 g

In order to find the excess reagent you must now subtract the previous total from the amount that was not the limited reagent. What volume of hydrogen at STP is produced from the reaction of 50.0g of Mg and the equivalent of 75g of HCl according to the following equation? Mg + 2HCl -> MgCl2 + H2 Limited reagent : HCl Previous total : 25g Non limited : Mg 75-25=50 50.0-25 = 25.0

FINALLY DONE The excess reagent is 25.0

How Depressing..

So close 

YEAHHH..no.

Sorry, but..no.

U mad? Back to start.  Stay mad.