2. What is the coefficient of static friction if it takes 34 N of force to move a box that weighs 67 N? .51.

Slides:



Advertisements
Similar presentations
Newton’s Laws of Motion and Free Body Analysis
Advertisements

Topics: Forces, Apparent Weight, & Friction
Practice Problem #1 A weightlifter bench presses 80kg (approx. 175lbs.) 0.75m straight up. a. How much work does she do, assuming constant velocity, in.
Friction. Friction - the force needed to drag one object across another. (at a constant velocity) Depends on: How hard the surfaces are held together.
Chapter Assessment Questions 3
Sliding Friction A force that opposes motion Acts parallel to the
As the ball revolves faster, the angle increases
Copyright © 2007, Pearson Education, Inc., Publishing as Pearson Addison-Wesley. Equilibrium Using Newton’s second law Mass, weight, and apparent weight.
Friction.
Chapter Assessment Questions
Physics 151 Week 10 Day 2 Topics: Apparent Weight & Conservation of Energy  Apparent Weight  More Friction.
C H A P T E R 5 Dynamics of Uniform Circular Motion
Newton’s Laws of Motion Problems MC Questions
Do Now: A 40 N chair is pushed across a room with an acceleration of 2 m/s 2. Steven pushes with a force of 15N. What is the force of friction acting on.
+ Make a Prediction!!! “Two objects of the exact same material are placed on a ramp. Object B is heavier than object A. Which object will slide down a.
Friction is a force that opposes the motion between two surfaces that are in contact  is a force that opposes the motion between two surfaces that are.
Friction There are many forms of friction. This lesson introduces the force laws for static friction, kinetic friction, and rolling friction. Students.
A 6. 0-kg object undergoes an acceleration of 2. 0 m/s2
NEWTON’S SECOND LAW.
Frictional Forces. Question: how does a highway patrol officer use skid marks to recreate an accident?
Quiz 4.
Week.  Student will:  Incorporate Force of Friction into calculation  Static Friction  Kinetic Friction.
Friction. Friction - the force needed to drag one object across another. (at a constant velocity) Depends on: How hard the surfaces are held together.
Friction. Friction - the force needed to drag one object across another. (at a constant velocity) Depends on: How hard the surfaces are held together.
Lecture 9: Forces & Laws of Motion. Questions of Yesterday You must apply a force F to push your physics book across your desk at a constant velocity.
Physics Vectors and Forces in Two Dimensions. Problem #1 A plane is flying at a velocity of 95 m/s west and encounters a wind of 25 m/s to the south.
Review Force, Friction, Motion, Power and Work.  In science, a force is a push or a pull.  All forces have two properties:  Direction and Size  A.
PHYS 101 Newton’s second law. Example 1 A sled with a mass of 20kg slides along frictionless ice at 4.5 m/s. It then crosses a rough patch of snow that.
Physics 151 Week 11 Day 3 Topics: Newton’s 2nd Law and Applications  Applying Newton’s 2nd Law  Apparent Weight  Free Fall  Terminal Velocity  Friction.
Chapter 5 - Force and Motion II Friction –Static –Kinetic Incline/Horizontal Plane with friction Drag Forces –Terminal Velocity Uniform Circular Motion.
SECTION 5.2 FRICTION Define the friction force.
Work and Energy x Work and Energy 06.
Newton’s Second Law Examined
Friction is a type of force between two touching surfaces.
A 4.25 kg block of wood has a kinetic coefficient of friction of and a static of between it and the level floor. 0. Calculate the kinetic friction.
Friction and Forces on Inclined Planes. The Normal Force The normal force is the supporting force that acts on the object perpendicular to the surface.
An 7.3-kg object rests on the floor of an elevator which is accelerating downward at a rate of 1.0 m/s 2. What is the magnitude of the force the object.
Friction Dynamics Physics. #1) Friction of a car A car has a mass of 1700 kg and is located on a level road. Some friction exists in the wheel bearings.
Friction. I. Friction A. Background 1. A force that acts opposite the direction of movement 2. Friction slows you down and causes heat.
Problems – 1 A ball of mass ____ grams is tossed straight up in the air. Assuming air resistance can be ignored, draw an FBD for the ball on its way up.
-A force that opposes motion -Acts parallel to the surfaces in contact.
Example Problems for Newton’s Second Law Answers
Frictional Force A force that opposes motion Acts parallel to the
Friction Coefficient.
Intro problem (p.145 #1-2, p.147 #1-4)
Friction is a type of force between two touching surfaces.
Static and Kinetic Frictional Forces Read 5.1 OpenStax
The force of Friction Chapter 4.4.
Do Now: A 40 N chair is pushed across a room with an acceleration of 2 m/s2. Steven pushes with a force of 15N. What is the force of friction acting.
Module 4, Recitation 3 Concept Problems, Friction.
2. What happens if the force is increased?
Newton’s Laws Acceleration
Friction Newton’s 2nd Law with Friction Examples Outline.
Aim: How do we explain the force of friction?
Friction.
Contact Friction Forces:
A fridge resting on a cement garage floor has a static coefficient of friction of 0.52 and a kinetic coefficient of friction of The fridge has a.
Newton’s 2nd law Problems
Ch. 6 slides.ppt Forces2.ppt.
Involving Friction and the coefficients of friction
Example Problems for Newton’s Second Law Answers
Aim: How do we explain the force of friction?
Aim: How do we explain the force of friction?
Involving Friction and the coefficients of friction
Applying Newton’s Laws
Consider an object on an inclined plane:
Textbook: 5.5 Homework: WS - Friction
Contact Friction Forces:
Friction.
Presentation transcript:

1. What is the force of friction between a block of ice that weighs 930 N and the ground if μ= .12?

2. What is the coefficient of static friction if it takes 34 N of force to move a box that weighs 67 N? .51

3. A box takes 350 N to start moving when the coefficient of static friction is .35. What is the weight of the box? 1000 N

4. A car has a mass of 1020 Kg and has a coefficient of friction between the ground and its tires of .85. What force of friction can it exert on the ground? What is the maximum acceleration of this car? In what minimum distance could it stop from 27 m/s? 8500 N 8.3 m/s/s 43.8 m

5. Clarice moves an 800. gram set of weights by applying a force of 1 5. Clarice moves an 800. gram set of weights by applying a force of 1.2 N. What is the coefficient of friction? .15

6. A car has a coefficient of friction between the ground and its tires of .85. What is the mass of the car if it takes 9620 N of force to make it slide along the ground? 1155 kg

7. A 5. 00 Kg block has a coefficient of friction of 7. A 5.00 Kg block has a coefficient of friction of .150 on a flat surface. What is its acceleration if you exert a force of 21.0 N sideways on it when it is at rest? (Find the friction force first) 2.73 m/s/s

8. A 10. Kg block is at rest on a level surface 8. A 10. Kg block is at rest on a level surface. It accelerates from rest to +51.2 m/s in 8.0 seconds when you exert a force of +115 N on it sideways. What is the acceleration of the block? What is the force of friction between the surface and the block, and what is the coefficient of friction? 6.4 m/s/s 51 N .51

9. A 120. Kg log sled accelerates at 1 9. A 120. Kg log sled accelerates at 1.40 m/s/s when a horse pulls on it. What force must the horse exert if the coefficient of friction between the ground and the sled is .28? 497 N

10. You exert a force of +24 N sideways on an object and it accelerates from 0 - 12 m/s over a distance of +5.2 m. You know that the coefficient of friction between the object and the ground is .58, so what is its mass? 1.2 kg

11. A 15. 0 kg block of wood with a kinetic coefficient of 11. A 15.0 kg block of wood with a kinetic coefficient of .370 is sliding to the right at 4.45 m/s is stopped by friction and a force of 25.0 N to the left. What is its deceleration? In what distance does it stop? -5.29 m/s/s 1.87 m

12. The 1835 kg Batmobile needs to stop from a speed of 48. 2 m/s 12. The 1835 kg Batmobile needs to stop from a speed of 48.2 m/s. Its tires have a coefficient of friction of .93 with the road, and Batman goes to full reverse thrusters on his jet engines. What would be his acceleration if he stopped in a distance of 50.0 m? What additional stopping force does he need to do this? -23.2 m/s/s -25,900 N

13. An 89,320 kg airplane landing at 83 13. An 89,320 kg airplane landing at 83.5 m/s must stop in a distance of 415 m. The engines can generate 313 kN of reverse thrust. What must be the deceleration of the airplane? What additional force of friction from the tires does the plane need to stop? What is the minimum coefficient of friction that must exist between the tires of the plane and the runway? -8.40 m/s/s -437 kN .500

14. An 18.5 kg block of orthoclase chondritic basalt has a coefficient of .350 between it and the floor. It is sliding to the right at 6.72 m/s and stops in a distance of 3.93 m under the influence of friction, and another force. What is its deceleration? What is the magnitude and direction of this other force? -5.75 m/s/s -42.8 N (left)

4.9 m -3.2 m/s/s -9.4 N (to the left) 15. An 8.12 kg block of wood is moving to the right with at 4.5 m/s. There is a coefficient of kinetic friction of .21 between the wood and the floor. If no other force acts along the ground, in what distance will the block stop? If the block stops sliding in 3.15 m. What is the acceleration of the block? What other force besides friction must be applied to the block? 4.9 m -3.2 m/s/s -9.4 N (to the left)

16. Kate exerts a force to the right on a 24 16. Kate exerts a force to the right on a 24.5 kg box that accelerates at 2.31 m/s/s in the direction he pushes. What force is she pushing with if the coefficient of kinetic friction is 0.32 between the box and the floor? 134 N

17. Ferdinand exerts a force of 283 N to the right on a 27 17. Ferdinand exerts a force of 283 N to the right on a 27.3 kg box where there is a coefficient of kinetic friction of 0.48 between the box and the floor. What is the acceleration of the box assuming it is already sliding to the right? 5.66 m/s/s

18. James pushes a box with a mass of 45 kg along the floor 18. James pushes a box with a mass of 45 kg along the floor. He exerts a force of 258 N to the right and the box accelerates at 2.1 m/s/s to the right. What must be the coefficient of friction between the box and the floor? 0.37

19. Kelsey pushes a box with a mass of 35 kg along the floor 19. Kelsey pushes a box with a mass of 35 kg along the floor. She exerts a force of 213 N to the right and the box accelerates at 2.4 m/s/s to the right. What must be the coefficient of friction between the box and the floor? 0.38

20. What is the acceleration if you exert 27 N of force to the right on a 4.0 kg object on a level surface where the coefficient of kinetic friction is 0.13? (Assume it is already sliding to the right) 5.5 m/s/s