2x² – 2x – 4 = 0 a = b = c = 2 – 2 – 4 Calcul du discriminant :  = 36  > 0, donc l’équation admet deux solutions x 1 = – 1 x 2 = 2.

Slides:



Advertisements
Similar presentations
Indefinite Articles Plural of Nouns
Advertisements

ACTIVITES MENTALES Collège Jean Monnet Préparez-vous !
ACTIVITES MENTALES Collège Jean Monnet Préparez-vous !
1 te 2 1 te 2 1 te-- 1 te-- 1 te 2 1 te 2 1 te 2 te ta 2-- ta 1 te-- 1 te-- 1 te ta 2-- ta 1 te-- 1 te 2 te 1-2.
Neither here nor there With Mr. Angry Cloud-Ghost.
To ask about someone’s family, p. 93
LA QUANTITE. THE QUANTITY To express an indeterminate quantity (some), we use: De la (féminin) ex: de la viande De l (in front of mute « h » or a vowel)
The pronouns Y and EN Y is used to replace places and location expressions! EN is used for the partitif and un or une!
Nombres de solutions d’une équation. 1.Résoudre graphiquement : a. f (x) = –3 b. f (x) = –5 c. f (x) = 0 d. f (x) = 3.
Partitive Articles When you’re talking about a whole item, use un, une or des before the noun: Je veux un croissant. I want a croissant. But, when you’re.
J’ai….. un chien J’ai ….. une tortue J’ai ….. un hamster.
Cours 9 Les protocoles de niveau trame. La trame LAP-B Le protocole LAP-B (Link Access Protocol - channel B) est une trame qui a été normalisée pour transporter.
United nations /MAP/ TS 18-19/12/2003 Distribution du N-NO 3 [Fleuve Loire (1971 to 1997)]
1/03/09 De 89 à 98. 1/03/09 De 89 à 98 1/03/09 De 89 à 98.
Given Connections Solution
Calcul mental. Calcul n°1 2 x 7 = Calcul n°2 3x 7 =
FR 2 U3 L10b. What are articles? What is a definite article? What is an indefinite article? Can you leave out articles in French? In English?
Simplify Simplify (-8) 0 1 If arc BC = 84°, then m ∠ BAC = 42° A B C.
Dépenses communautaires agricoles : part des différents types de mesures UE-10UE-12UE-15UE-25UE-27 Source: European Commission – DG Agriculture and Rural.
The Quadratic Formula and the Discriminant
Warm up – Solve by Taking Roots. Solving by the Quadratic Formula.
Solving Quadratic Equations – The Discriminant The Discriminant is the expression found under the radical symbol in the quadratic formula. Discriminant.

Notes Over 9.7 Using the Discriminant The discriminant is the expression under the radical: If it is Positive: Then there are Two Solutions If it is Zero:
Notes Over 6.7 Finding the Number of Solutions or Zeros
5.6 Quadratic Formula & Discriminant
©NicoleRichelle article some masculinefeminine plural.
Essential Question: How do you use the quadratic formula and the discriminant? Students will write a summary including the steps for using the quadratic.
3.8 Warm Up Write the function in vertex form (by completing the square) and identify the vertex. a. y = x² + 14x + 11 b. y = 2x² + 4x – 5 c. y = x² -
The Quadratic Formula & Discriminant Essential question – How do you solve a quadratic equation using the Quadratic Formula?
Section 1.4 – Quadratic Equations
What you will learn How to solve a quadratic equation using the quadratic formula How to classify the solutions of a quadratic equation based on the.
The Quadratic Formula Students will be able to solve quadratic equations by using the quadratic formula.
Quadratic Functions (4) What is the discriminant What is the discriminant Using the discriminant Using the discriminant.
Getting Started The objective is to be able to solve any quadratic equation by using the quadratic formula. Quadratic Equation - An equation in x that.
Table of Contents Solving Quadratic Equations – The Discriminant The Discriminant is the expression found under the radical symbol in the quadratic formula.
Section 1.4 Day 1 – Quadratic Equations No Calculator After this section you should be able to: Solve quadratic equations by FACTORING.
Section )by graphing (using the calculator to identify the roots (x-intercepts)) 2)by factoring 3)by “completing the square” 4)by Quadratic Formula:
Lesson 4 Contents 11-3 Solving Quadratic Equations by Using the Quadratic Formula Objectives 1. Solve quadratic equations by using the Quadratic Formula.
ANSWERS!. Completing the Square Level 1 Answers Completing the Square Level 2 Answers.
10.6 Whiteboard Review Solving Quadratic Practice FACTOR or use the QUAD FORM?!
TEST QUIZ Grammaire Conjugaisons & Les groupes des verbes À quel groupe appartient le verbe: aimer ? Premier groupe Premier groupeaimer Deuxième groupe.
Réalisé par : Sébastien Lachance MATHS 3 E SECONDAIRE Les figures SEMBLABLES.
AMPERES Enseigner de façon dynamique le produit scalaire en 1re S ?
。 33 投资环境 3 开阔视野 提升竞争力 。 3 嘉峪关市概况 。 3 。 3 嘉峪关是一座新兴的工业旅游城市,因关得名,因企设市,是长城文化与丝路文化交 汇点,是全国唯一一座以长城关隘命名的城市。嘉峪关关城位于祁连山、黑山之间。 1965 年建市,下辖雄关区、镜铁区、长城区, 全市总面积 2935.
MATÉRIEL ET MÉTHODES. Extraction de l’ADN  L’isolation de l’ADN à été effectué par deux méthodes différentes : Ils utilisent différents protocoles mais.
The Quadratic Formula and the Discriminant
Lesson 5.6: The Quadratic Formula & the Discriminant
Warm up – Solve by Taking Roots
Notes Over 9.6 Using the Discriminant
Find the number of real solutions for x2 +8x
Sullivan Algebra and Trigonometry: Section 1.3
BACK SOLUTION:
5-Minute Check Lesson 4-2 Answer: 2
Solving Quadratic Equations by Graphing
Warm-up Solve using the quadratic formula: 2x2 + x – 5 =0
Unit 7 Day 4 the Quadratic Formula.
Warm up – Solve by Completing the Square
Solving Quadratic Equations by Factoring
The Discriminant   Determine the number of real solutions for a quadratic equation including using the discriminant and its graph.
A graphing calculator is required for some problems or parts of problems 2000.
5.6 Quadratic Formula & Discriminant
Unit 3 Review (Calculator)
3.4 – The Quadratic Formula
Questions over HW?. Skills Check Radical Operations and Solving by Square Roots after HW Check.
Section 4.7 – Quadratic Formula
  Warm Up:.
Calculate 9 x 81 = x 3 3 x 3 x 3 x 3 3 x 3 x 3 x 3 x 3 x 3 x =
Warm Up Using the quadratic formula find the zeros of the following:
Substitution 3..
Presentation transcript:

2x² – 2x – 4 = 0 a = b = c = 2 – 2 – 4 Calcul du discriminant :  = 36  > 0, donc l’équation admet deux solutions x 1 = – 1 x 2 = 2

x² + 4x + 3 = 0 a = b = c = Calcul du discriminant :  = 4  > 0, donc l’équation admet deux solutions x 1 = – 3 x 2 = – 1

6x² + 6x – 12 = 0 a = b = c = 6 –12 Calcul du discriminant :  = 324  > 0, donc l’équation admet deux solutions x 1 = – 2 x 2 = 1

x² + 8x + 16 = 0 a = b = c = Calcul du discriminant :  = 0  = 0, donc l’équation admet une solution x = – 4

x² – 6x + 7 = –2 a = b = c = 1 – 6 9 Calcul du discriminant :  = 0  = 0, donc l’équation admet une solution x = 3 x² – 6x + 9 = 0 différent de zéro !!!

– 2x² +3x – 4 = 0 a = b = c = – 2 3 – 4 Calcul du discriminant :  = – 23  < 0, donc l’équation n’admet pas de solution

4x² – x + 1 = 0 a = b = c = 4 – 1 1 Calcul du discriminant :  = – 15  < 0, donc l’équation n’admet pas de solution