2D Deformation and Creep Response of Articular Cartilage

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Presentation transcript:

2D Deformation and Creep Response of Articular Cartilage By: Mikhail Yakhnis & Robert Zhang

Motivation Articular cartilage transfers load between bones enables smooth motion along joints Cartilage has limited capacity for self repair Applications: biomaterials, prosthetics, biomedical devices http://nigelhartnett.onlinemedical.com.au/images/articular%20knee%20injury.jpg

Problem Description Consider cartilage in an unconfined compression under constant load F Analyze the 2D elastic deformation over time Articular Cartilage F Compression plate Frictionless Supports

Material Background Cartilage often modeled as a viscoelastic material Viscous and elastic by superposition Elasticity and viscosity can be linear or nonlinear Established models: Kelvin-Voigt, Maxwell, Standard-Linear Solid http://www.allsealsinc.com/allseals/Orings/maxwell.gif

Mathematical Model for Cartilage We chose the Kelvin-Voigt model to focus on the creep response The constitutive equation is 𝜎=𝐷𝜀+𝜂 𝑑𝜀 𝑑𝑡 Mechanical Analogue of Kelvin-Voigt Model http://en.wikipedia.org/wiki/File:Kelvin_Voigt_diagram.svg

Assumptions for Model Conditions Properties F L c B3 B4 B2 B1 Constant force F normal to boundary B3 No gravity (body force) 2D, plane stress* Confined in y-direction along B1 and B3 Confined in x-direction along B4 Properties c = 0.1m; L = 0.125m Constant cross-sectional area A Isotropic elasticity* * 𝐷= 𝐸 1−𝜈 2 1 𝜈 0 𝜈 1 0 0 0 1−𝜈 2 B3 B2 B1 B4 x y

Experimental Data 𝐻 𝐴 =7𝑒5 𝑃𝑎 (Aggregate Modulus) 𝐸=3.37𝑒5 𝑃𝑎 𝜈=0.396 Data Book on Mechanical Properties of Living Cells, Tissues, and Organs /. Tokyo ; New York : Springer, 1996. Print.

Derivation of Weak Form By definition, stress 𝜎= 𝐹 𝐴 Strain can be rewritten as gradient of displacement u 𝜀=𝛻𝑢= 𝜀 𝑥𝑥 𝜀 𝑦𝑦 𝜀 𝑥𝑦 Our constitutive equation (in strong form) becomes 𝐹=𝐴 𝐷 𝛻𝑢+𝜂 𝑑 𝑑𝑡 𝛻𝑢

Derivation of Weak Form (1) Take the gradient of the force equation (which equals zero) (2) Multiply by an arbitrary displacement 𝑤 𝐴 𝐷( 𝛻 2 𝑢)+𝜂 𝑑 𝛻 2 𝑢 𝑑𝑡 𝑤 𝑑Ω =0 (3) Integrate by parts to induce symmetry of 𝑢 and 𝑤 𝐹 𝑜 𝑤+𝜂𝐴 𝑑 𝛻𝑢 𝑑𝑡 𝑤 Γ −𝐴 𝐷𝛻𝑢 𝛻𝑤+𝜂 𝑑𝛻𝑢 𝑑𝑡 𝛻𝑤 𝑑Ω =0

Decoupling a Transient Problem We can decouple the formulation and assume the time and spatial variations are separate 𝑢 𝑥,𝑡 ≈ 𝑢 𝑛 𝑒 𝑥,𝑡 = 𝑗=1 𝑛 𝑢 𝑗 𝑒 (𝑡) 𝑁 𝑗 𝑒 (𝑥) where 𝑢 is a function of time only and basis function N is function of space The weak differential equation rewritten in matrix form is 𝐹 𝑜 [𝑁] 𝑇 +𝜂𝐴 𝑢 𝑛−1 − 𝑢 𝑛−2 ∆𝑡 𝐵 𝑇 (𝑥𝑥,𝑦𝑦) 𝑁 𝑇 Γ =𝐴∫ 𝐷 𝐵 𝑇 𝐸 𝐵 𝑢 𝑛 +𝜂 𝐵 𝑇 𝐵 𝑢 𝑛−1 − 𝑢 𝑛−2 ∆𝑡 𝑑Ω Reddy, J. N.. "Time-Dependent Problems." An introduction to nonlinear finite element analysis. Oxford: Oxford University Press, 2004. . Print.

Displacement Equation for Creep Response 𝐾 = 𝐵 𝑇 𝐷 𝐵 𝐶 =𝜂 𝐵 𝑇 𝐵 At each time step n 𝐹 𝑜 [𝑁] 𝑇 +𝜂𝐴 𝑢 𝑛−1 − 𝑢 𝑛−2 ∆𝑡 𝐵 𝑇 𝑁 𝑇 =𝐴∫ 𝐵 𝑇 𝐷 𝐵 𝑢 𝑛 +𝜂 𝐵 𝑇 𝐵 𝑢 𝑛−1 − 𝑢 𝑛−2 ∆𝑡 𝑑Ω The equation for 𝑢 𝑛 becomes 𝑢 𝑛 = [𝐶] −1 𝐾 𝑢 𝑛−1 − 𝐹 𝑜 𝐴 𝑁 𝑇 +𝜂 𝑢 𝑛−1 − 𝑢 𝑛−2 ∆𝑡 𝐵 𝑇 𝑁 𝑇 Γ

Modeling Creep in MATLAB Changes in Preprocessor.m Provide initial displacement Define time step Adjust boundary conditions Changes in Assemble.m Assemble the damping matrix [C] Changes in NodalSoln.m Add initial condition, damping, time inputs Modify reaction force and displacement equations

Modeling Creep in MATLAB Discussion: MATLAB result converges toward experimental data farther away from initial time 10% error at 6 seconds MATLAB model reaches equilibrium faster than experimental data

Modeling Creep in MATLAB

Modeling Creep in ANSYS A variety of models are available Differences include suitability for primary and secondary creep Usually of the form 𝜀 𝑐𝑟 = 𝑓 1 𝜎 𝑓 2 𝜀 𝑓 3 𝑡 𝑓 4 (𝑇) Examples Strain Hardening: 𝜀 𝑐𝑟 = 𝐶 1 𝜎 𝐶 2 𝜀 𝐶 3 𝑒 − 𝐶 4 /𝑇 Time Hardening: 𝜀 𝑐𝑟 = 𝐶 1 𝜎 𝐶 2 𝑡 𝐶 3 𝑒 − 𝐶 4 /𝑇 ANSYS Advanced Nonlinear Materials: Lecture 3 – Rate Dependent Creep http://www.ansys-blog.com/wp-content/uploads/2012/06/Three-Types-of-Creep.png

Considerations for ANSYS Model What experimental data is available to us? Can we fit the experimental data to the model? Can we use the built-in Mechanical APDL curve fitting procedure? Is there more emphasis on primary creep or secondary creep? Does the model satisfy our constitutive equation?

Parameters in the ANSYS Model Experimental data provides aggregate modulus and Poisson’s ratio Young’s Modulus can be derived from 𝐻 𝐴 = 𝐸 1−𝜈 1+𝜈 1−2𝜈 The solution for time-dependent strain in the K-V model is 𝜀 𝑡 = 𝜎 𝑜 𝐸 (1− 𝑒 −𝜆𝑡 ) We can use the Modified Exponential Function in ANSYS 𝜀 𝑐𝑟 = 𝐶 1 𝜎 𝐶 2 𝑟 𝑒 −𝑟𝑡 𝑟= 𝐶 5 𝜎 𝐶 3 𝑒 − 𝐶 4 /𝑇 where 𝐶 2 =1, 𝐶 3 = 𝐶 4 =0; we can solve for 𝐶 1 and 𝐶 5 ANSYS Advanced Nonlinear Materials: Lecture 3 – Rate Dependent Creep

ANSYS Results – Creep Response Short Term Response – 30 Seconds Long Term Response – 3000 Seconds

Animation of Deformation in ANSYS

Comparison of ANSYS and Experiment Result: Theoretical Model-Based ANSYS data tends to overshoot experimental data Error is between 30% to 40% per data point Experimental-based model performs better Discussion: Results demonstrate the limitations of ANSYS models A combined primary-secondary model is ideal Long term response in ANSYS is not accurate Function models primary response Primary + Secondary Time Hardening 𝜖 𝑐𝑟 = 𝐶 1 𝜎 𝐶 2 𝑡 𝐶 3 +1 𝑒 − 𝐶 4 𝑇 𝐶 3 +1 + 𝐶 5 𝜎 𝐶 6 𝑡 𝑒 − 𝐶 7 𝑇

ANSYS Model: Mesh and Time Refinement Mesh [Nodes] Time [s] Base Case 805 Between 0.1 and 900 Refinement 15747 Between 1e-4 and 1e-2 Time % Difference w.r.t. Base Case - Mesh Mesh and Time 1 -0.459 0.000 -0.470 2 -0.367 0.025 -0.202 4 -0.294 1.447 1.145 6 -0.267 2.008 1.733 8 -0.255 2.261 2.001 10 2.732 2.384 2.136

Sensitivity Analysis Recall the creep model: 𝜀 𝑐𝑟 = 𝐶 1 𝜎 𝐶 2 𝑟 𝑒 −𝑟𝑡 𝜀 𝑐𝑟 = 𝐶 1 𝜎 𝐶 2 𝑟 𝑒 −𝑟𝑡 𝑟= 𝐶 5 𝜎 𝐶 3 𝑒 − 𝐶 4 /𝑇 We varied each non-zero model constant by 50%* to perform a rudimentary sensitivity analysis: Time Base Case Case C1 Difference % Case C2 Case C5 1 3.60E-03 6.64E-03 84.59 7.70E-03 114.09 6.53E-03 81.49 2 4.36E-03 7.69E-03 76.20 9.53E-03 118.54 7.39E-03 69.36 4 5.23E-03 8.92E-03 70.51 1.18E-02 124.92 8.23E-03 57.35 6 5.68E-03 9.56E-03 68.20 1.29E-02 127.25 8.55E-03 50.43 8 5.92E-03 9.89E-03 67.13 1.35E-02 128.25 8.67E-03 46.46 10 6.04E-03 1.01E-02 66.61 1.38E-02 128.74 8.71E-03 44.23 *The simulation did not converge at C2 +50% so C2 +10% was used instead

2D Deformation and Creep Response of Articular Cartilage By: DJ Mikey Mike & Big Rob Zhang Thank you for listening. Questions?