CHAPTER 9 Thermal & Moisture Protection CON 4003 Construction Estimating Prof R. V. Locurcio

Presentations Today… CH 9 – Thermal & Moisture Protection Thursday… HW#5 – Jose Vega Thursday… China Presentation

Waterproofing & Dampproofing Consists of a water resistent coat that is sprayed or brushed onto the exterior of the foundation to prevent moisture intrusion into the building

Waterproofing Sprayed or rolled-on waterproofing …bid by the square ft. Waterproof membranes and building paper …bid as a sheet or roll good

Building Paper and Vapor Barriers A vapor barrier is often used to refer to any material for damp proofing, typically a plastic or foil sheet, that resists penetration of moisture through the wall, ceiling or floor assemblies of buildings

Moisture & Vapor Barriers

Building Paper and Vapor Barriers Where: Behind masonry or siding Under shingles Between insulation and inside finish of exterior walls Must be lapped to be effective

Waterproof membrain or building paper used to establish the waterproofing system Drain board: added to minimize the chance of water penetration of the waterproof membrane There must be a drain system at the bottom of the drain board to prevent the accumulation of water Building paper Fiberglass Drain board Drain system

The area of waterproofing = 148 ft x 8.33ft = 1232.84 SF Problem 9-1 How much waterproofing is needed to cover the foundation walls of a 24-foot by 50-foot basement? The wall is 8 feet high. The wall sits on a footing that is 12 inches high and extends 16 inches beyond the wall on the exterior side. Assume that the waterproofing starts 12 inches below the top of the foundation wall and covers the top surface of the footings. If one gallon of waterproofing material covers 75 square feet, how many gallons of waterproofing material are needed ? Solution: L= 50ft, W= 24ft, Perimeter = (50+24+50+24) = 148 LF The height of the waterproofing = 8ft -1ft+ (16in)/(12 in/ft) = 8.33 LF Water proofing The area of waterproofing = 148 ft x 8.33ft = 1232.84 SF Add four 16in by 16in corners on the top of the footing Total area = 1232.84 + 4 x((16/12) x(16/12)) = 1240 SF 1240 SF Quantity = = 16.6 gallons A-A Cross section of foundation 75 gal/SF

Insulation Fiberglass Batt Insulation paperbacked so to be installed with the paper on the interior side of wall Blown Insulation fiberglass shredded newspaper spun rock Exterior Insulation Finish System Consists of a rigid insulation layer covered with a synthetic stucco system. The stucco system includes a base coat a reinforcing layer, a brown coat, and a colored finish coat.

Insulation Fiberglass Batt insulation Paperbacked or Unfaced Common size precut 15” & 23” Blown Insulation Made from Fiberglass shredded newspaper, and blown rock. Spray Foam Insulation Made from Isocyanate & Polyol Resin

The length of wall = 25ft, height = 8ft Problem 9-6 How many rolls of insulation are needed for Problem 5 if the insulation comes in rolls 15 inches wide and 32 feet long? Don’t include the waste factor. Solution: The length of wall = 25ft, height = 8ft The number of rows is one row 8 feet high. The number of columns is calculated using Eq. (4-17) as follows: The stud spacing is 16” Number columns = (25 ft) (12 in/ft) =18.75 Columns (15in + 1in) 19 number of sheets of 8-foot by 15 in-wide insulation. The length of roll is 32ft, so 4 sheets from each roll: No. of rolls = 19 = 4.75 ~ 5 rolls 4

25LF 16” 8LF 16” 16” 16” 25LF X 12”/LF = 300 inches Panels = 300/16 = 18.75 or 19 panels Roll = 32 LF / 8 = 4 panels /roll Rolls = 19 / 4 = 4.75 = 5 rolls

Exterior Insulation Finish System “Consists of a rigid insulation layer covered with a synthetic stucco system.” “The stucco system includes a base coat a reinforcing layer, a brown coat, and a colored finish coat.”

Shingle Roofs Asphalt Shingles specified by expected life 20, 25, 30- year three tab or architectural Flashing required at all penetrations vent pipes intersections with wall or chimney Drip Edge required at all edges including gable end Starter Shingles required for all roof edges that are parallel to the rows of shingles. placed on the roof edges then completely covered up by first layer of shingles

Shingle Installation

Hip and Valley Roof Hip Roof is a type of roof where all sides slope downwards to the walls, usually with a fairly gentle slope

Asphalt Impregnated Felt on Roofs Slope greater then 2:12 and less than 4:12  The felt must be lapped 19 in Slope greater than or equal to 4:12  The felt must be lapped 2 in Length sloped = Lenght plan view (1+ Slope^2)^0.5 Area surface = Area plan view (1+ Slope^2)^0.5 Hips and Valleys increase the waste To do a proper takeoff for a roof, each roof surface must be taken off individually

Area of Triangular Roof Section ***Length of Slope*** = same length from trapezoidal section Bilding Paper Building Paper Building Paper Average Length of a row for triangle areas is the average of the length of the ridge and the eave plus the width of the felt plus the end lap. ( (Ridge + Eave) / 2 ) + felt width + end lap Area of Triangular Section = (Average Length) x (no. Rows) x (felt width)

Roof Drip Edge

Siding Soffit and Fascia - 1

Siding, Soffit, and Fascia -2 Vinyl Soffit Aluminum Fascia

Siding Soffit and Fascia - 3

Problem 9-12: Determine the quantity of insulation , mesh reinforcement , and stucco needed to cover the end of the building in Fig 9-14. the insulation comes in 4ft by 8ft sheets. The reinforcement comes in rolls 100 ft long by 3ft wide and needed to be lapped 3 inches. One cubic foot of base or brown coat will cover 60 square feet of wall, and one bucket of finish coat will cover 120 square feet of wall. Solution:

4.67’ 12 4 Part B 8’ W 4’X4’ D 6’X6’ 8” 4’

Stucco Wall Assembly

EIFS Wall Assembly

Roof Assembly

Roof Coverings

The End