Gravity and free fall Pg. 10

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Presentation transcript:

Gravity and free fall Pg. 10

Objectives Physics terms Define the conditions for free fall. Describe and analyze the motion of objects in free fall using the equations for constant acceleration. acceleration quadratic equation free fall

Equations V (or Vf)  final velocity V0 (or Vi ) initial velocity a acceleration t time x (or xf) final position x0 (or xi) initial position V0 (or Vi ) initial velocity t time a acceleration

What is free fall? An object is in free fall whenever it moves solely under the influence of gravity, regardless of its direction. A ball thrown up, with negligible air resistance A ball launched at ANY angle, as long as there is negligible air resistance A ball falling down, with negligible air resistance

Gravity and free fall Near Earth’s surface, free-falling objects have a downward acceleration of -9.8 m/s2. If an object is dropped from rest, then . . . after 1 second its velocity is: -9.8 m/s. after 2 seconds its velocity is: -19.6 m/s. after 3 seconds its velocity is: __?___ after 10 seconds its velocity is: __?___

Gravity and free fall Near Earth’s surface, free-falling objects have a downward acceleration of -9.8 m/s2. If an object is dropped from rest, then . . . after 1 second its velocity is: -9.8 m/s. after 2 seconds its velocity is: -19.6 m/s. after 3 seconds its velocity is: -29.4 m/s after 10 seconds its velocity is: -98 m/s

Describe free fall with equations The free fall equations are identical to the equations for motion with constant acceleration: 𝒗= 𝒗 𝟎 + −𝟗.𝟖 𝒕 𝒙= 𝒙 𝟎 + 𝒗 𝟎 𝒕+ 𝟏 𝟐 (−𝟗.𝟖) 𝒕 𝟐 The only difference is that you already know the acceleration because it is always -9.8 m/s2. Point out that the value of g actually depends on location, and will be different on the Moon, for example. It is 9.8 m/s/s for events close to the Earth’s surface.

Find your reaction time Use this equation for free fall to find your own reaction time—the time to catch a falling ruler. Make a prediction first: Will your reaction time be in seconds? Tenths of a second? Hundredths of a second? 𝑡= − 2𝑎𝑥 −2𝑎 𝑥 𝑖 + 𝑉 𝑖 2 − 𝑉 𝑖 𝑎 𝑎=−9.8 𝑚/ 𝑠 2 Students should complete the student assignment sheet while doing this experiment.

Find your reaction time Rest your hand off the edge of the desk. Your partner will hold a ruler vertically, with the 0 cm end even with your thumb. The teacher will need to demonstrate this. It is important that the students anchor their hand and do not grab down after the ruler. if possible, prompt the students to realize and explain this possible source of “operator error”.

Find your reaction time Your partner will release the ruler. Catch it with your thumb and finger. The teacher will need to demonstrate this. It is important that the students anchor their hand and do not grab down after the ruler.

Find your reaction time Record the free fall distance x, from the 0 cm end of the ruler to where your fingers catch it. x

Find your reaction time, treaction Solve for treaction. What is x0? What is v0? What is a? 𝑡= − 2𝑎𝑥 −2𝑎 𝑥 𝑖 + 𝑉 𝑖 2 − 𝑉 𝑖 𝑎 Use the interactive calculator on page 117 to check your work. Be aware that many if not most students will forget to convert the free fall distance x from centimeters into meters, and will be baffled at the answers they get. This activity is very good for reinforcing the importance of using proper SI units. It is good to let the students make this mistake. Help them recognize it and correct it.

Gravity and free fall REALLY? If an object is dropped from rest then . . . after 1 second its velocity is -9.8 m/s. after 2 seconds its velocity is -19.6 m/s. after 3 seconds its velocity is -29.4 m/s. after 4 seconds its velocity is -39.2 m/s. . . . . and so on . . . . REALLY? Do falling objects REALLY keep moving faster and faster?

Gravity and free fall Do falling objects REALLY keep moving faster and faster? No! In real life there is air resistance. As falling objects speed up, the force of air resistance increases. When the air resistance gets as strong as the force of gravity, the falling object stops accelerating. After showing this slide, ask the students “if the acceleration becomes zero, does that mean the velocity is zero also?”

Terminal velocity Most objects reach this terminal velocity within a few seconds of being dropped. Terminal velocity is the final maximum velocity an object reaches because of air resistance. A falling human has a terminal velocity of about 140 miles per hour (or about 60 m/s).

Terminal velocity Parachutes increase air resistance. Opening a parachute changes the terminal velocity from a fast, deadly speed to a low, safe speed.

A skydiving trip When did the parachute open? When did the parachuter reach terminal velocity? Ask the students when the parachuter is at terminal velocity (at both C and E).

When can motion be treated as free fall? Free fall is NOT a good approximation for light objects, or an object with a large surface area compared to its weight (like a parachute).

When can motion be treated as free fall? Free fall is a very good approximation for solid, dense objects dropped from ten meters or so. For these situations, air resistance can be ignored. The symbol g is often used when the acceleration of an object is due only to gravity. 𝒂=𝒈=−𝟗.𝟖 𝒎/ 𝒔 𝟐

Solving free fall problems Be sure to GUESS Write the equations of motion, substituting g for a. 3) Eliminate any terms that are zero. 4)Work out a solution strategy.

Example 1 From what height should you drop a ball if you want it to hit the ground in exactly 1.0 second? Given: Unknown: Equation: Substitution: Solution:

Example 1 From what height should you drop a ball if you want it to hit the ground in exactly 1.0 second? Given: Unknown: Equation: Substitution: Solution: x = -4.9m

Example 2 Toughie! How far does an object have to fall to reach a speed of 10 m/s (neglecting friction)? Given: Unknown: Equation: Substitution: Solution:

Example 2 Toughie! How far does an object have to fall to reach a speed of 10 m/s (neglecting friction)? Given: Unknown: Equation: Substitution: Solution: x = -5.1m

This makes sense. The ball must lose 9.8 m/s each second! An object thrown upward This ball thrown upward is in free fall as soon as the person is no longer touching it. If the ball leaves the boy’s hand with an upward velocity of 15 m/s, how fast is it moving one second later? Think: What is the sign of v0? What is the sign of a? Ask the students to make a prediction. Make sure that they recognize that the ball should slow down. This makes sense. The ball must lose 9.8 m/s each second!

An object thrown upward Here is the position-time graph for the ball thrown up at +15 m/s. What is the highest height the ball reaches? About 11.2 meters How do you know? This is the farthest point from it’s origin (0m)

Assessment 1 A pitcher on a baseball team throws a high lob across home plate. For each part of this event described below, is the ball in free fall with a constant acceleration of 1 g? The outfielder is winding up to throw the ball. The ball is in the air, rising to the top of its arc. The ball is in the air, descending toward the plate. The bat is connecting with the ball.

Assessment 1 Answer A pitcher on a baseball team throws a high lob across home plate. For each part of this event described below, is the ball in free fall with a constant acceleration of 1 g? The outfielder is winding up to throw the ball. No The ball is in the air, rising to the top of its arc. Yes c) The ball is in the air, descending toward the plate. d) The bat is connecting with the ball.

Assessment 2 A ball is thrown straight upward at 18 m/s. How long does it take to reach its highest point? b) What height does it reach, assuming it started at zero height?

Assessment 2 Answer part a A ball is thrown straight upward at 15 m/s. How long does it take to reach its highest point? asked: time given: v0 = 15 m/s, v = 0 m/s, a = g = -9.8 m/s2 relationship: solution:

Assessment 2 Answer part b A ball is thrown straight upward at 15 m/s. What height does it reach, assuming it started at zero height? asked: the height, which is x. given: t = 1.5 s, v0 = 15 m/s, v = 0 m/s, a = g = -9.8 m/s2 relationship: solution: Point out to the students that the time t was found in part a, so it is now a “given”.