Physics 7C lecture 15 Quilibrium

Slides:



Advertisements
Similar presentations
Physics 111: Mechanics Lecture 12
Advertisements

Copyright © 2012 Pearson Education Inc. Application of Newton’s laws: free body diagram Physics 7C lecture 03 Thursday October 3, 8:00 AM – 9:20 AM Engineering.
Q12. Static Equilibrium.
Torque and Equilibrium
C. a thrown baseball that does not rotate as it sails through the air
Stress, Strain, and elastic moduli
Physics 7C lecture 13 Rigid body rotation
Learning Goals 1.The conditions that must be satisfied for a body or structure to be in equilibrium. 2.What is meant by the center of gravity of a body,
Equilibrium and Elasticity
PHYS16 – Lecture 26 Ch. 12 Static Equilibrium. Static Equil. Pre-question If ball 2 has twice the mass of ball 1 and the system is in static equilibrium.
Torque Again.
PHYSICS 50: Lecture 11.1 RICHARD CRAIG.
Physics for Scientists and Engineers, 6e
College Physics, 7th Edition
Chapter 12: Static Equilibrium Conditions for equilibrium  First condition for equilibrium When a particle is in equilibrium (no acceleration), in an.
Chapter 12: Static Equilibrium and Elasticity
Reading Quiz 1. Viscous friction is
Physics 106: Mechanics Lecture 07
Physics 106: Mechanics Lecture 08
Equilibrium of Particles Free-body Diagram Equilibrium of Rigid Bodies
Statics. Static Equilibrium  There are three conditions for static equilibrium. 1.The object is at rest 2.There is no net force 3.There is no net torque.
Physics 218, Lecture XX1 Physics 218 Lecture 20 Dr. David Toback.
Copyright © 2012 Pearson Education Inc. 2D collision, center of mass Physics 7C lecture 09 Tuesday October 29, 8:00 AM – 9:20 AM Engineering Hall 1200.
Chapter 8: Torque and Angular Momentum
Objects in static equilibrium don’t move, F net = 0,  net = 0 Important for posture of human body, biomechanics. Important civil and mechanical engineers.
Chapter 9 Torque.
Equilibrium of a Rigid Body
Chapter 7 Rotational Motion.
Dynamics: Circular Motion
Equilibrium and Elasticity
Wednesday, Nov. 12, 2003PHYS , Fall 2003 Dr. Jaehoon Yu 1 PHYS 1443 – Section 003 Lecture #19 Wednesday, Nov. 12, 2003 Dr. Jaehoon Yu 1.Conditions.
Static Equilibrium (Serway ) Physics 1D03.
Formative Assessment. 1. A 130. gram uniform meter stick has a 22.0 g clamp on the 23.0 cm mark, where would you clamp a 35.0 g clamp to make the meter.
Chapter 12 Equilibrium and elasticity. Equilibrium We already introduced the concept of equilibrium in Chapter 8: dU(x)/dx = 0 More general definition.
Copyright © 2009 Pearson Education, Inc. An object with forces acting on it, but with zero net force, is said to be in equilibrium. The Conditions for.
Q11.1 Which of the following situations satisfy both the first condition for equilibrium (net force = 0) and the second condition for equilibrium (net.
Copyright © 2012 Pearson Education Inc. PowerPoint ® Lectures for University Physics, Thirteenth Edition – Hugh D. Young and Roger A. Freedman Lectures.
Lecture 17: Torque & Rotational Equilibrium. Questions of Yesterday You are riding on a Ferris wheel moving at constant speed. 1a) At what point is the.
Rotational Motion 1. Translational Motion vs. Rotational Motion Translational motion ___________ ______________________________ Example: motion of a bullet.
Spring 2002 Lecture #17 Dr. Jaehoon Yu 1.Conditions for Equilibrium 2.Center of Gravity 3.Elastic Properties of Solids Young’s Modulus Shear Modulus.
Rotational Equilibrium and Rotational Dynamics Rotational Motion 1 of 25 Physics 2053 Lecture Notes.
The centre of gravity is that point at which the sum of the gravitational forces due to all individual masses comprising the system appears to act. The.
Equilibrium. The First Condition of Equilibrium In a situation involving equilibrium, there is no acceleration (no change in velocity). Thus the net force.
PHY 151: Lecture Forces of Friction 5.9 Newton’s Second Law.
Chapter 12 Lecture 21: Static Equilibrium and Elasticity: I HW8 (problems):11.7, 11.25, 11.39, 11.58, 12.5, 12.24, 12.35, Due on Friday, April 1.
Copyright Sautter The next slide is a quick promo for my books after which the presentation will begin Thanks for your patience! Walt S.
Copyright © 2010 Pearson Education, Inc. Lecture Outline Chapter 11 Physics, 4 th Edition James S. Walker.
Chapter 8 Lecture Pearson Physics Rotational Motion and Equilibrium Prepared by Chris Chiaverina © 2014 Pearson Education, Inc.
Chapter 8 Lecture Pearson Physics Rotational Motion and Equilibrium Prepared by Chris Chiaverina © 2014 Pearson Education, Inc.
Wednesday, Nov. 13, 2002PHYS , Fall 2002 Dr. Jaehoon Yu 1 PHYS 1443 – Section 003 Lecture #17 Wednesday, Nov. 13, 2002 Dr. Jaehoon Yu 1.Conditions.
Two-Dimensional Rotational Dynamics 8.01 W09D2
1 Rotational Dynamics The Action of Forces and Torques on Rigid Objects Chapter 9 Lesson 2 (a) Translation (b) Combined translation and rotation.
© 2010 Pearson Education, Inc. PowerPoint ® Lectures for College Physics: A Strategic Approach, Second Edition Chapter 7 Rotational Motion.
Mechanics Lecture 17, Slide 1 Physics 211 Lecture 17 Today’s Concepts: a) Torque Due to Gravity b) Static Equilibrium Next Monday 1:30-2:20pm, here: Hour.
PHYS 1443 – Section 003 Lecture #19
Chapter 9 Rotational Dynamics.
Static Equilibrium and Torque
Which object will win? All moments of inertia in the previous table can be expressed as;
Torque at 90o This has NOTHING to do with torque but it comes up when you google images…go figure.
Torque and Equilibrium
Torque.
PHYS 1443 – Section 003 Lecture #17
Rigid Body in Equilibrium
Equilibrium and Elasticity
Physics 101: Lecture 14 Torque and Equilibrium
Figure 12.1  A single force F acts on a rigid object at the point P.
Chapter 9 Torque.
Rotational Statics i.e. “Torque”
College Physics, 7th Edition
Rigid Body in Equilibrium
Presentation transcript:

Physics 7C lecture 15 Quilibrium Thursday November 19, 8:00 AM – 9:20 AM Engineering Hall 1200

Introduction Many bodies, such as bridges, aqueducts, and ladders, are designed so they do not accelerate. Real materials are not truly rigid. They are elastic and do deform to some extent. We shall introduce concepts such as stress and strain to understand the deformation of real bodies.

Conditions for equilibrium First condition: The sum of all the forces is equal to zero: Fx = 0 Fy = 0 Fz = 0 Second condition: The sum of all torques about any given point is equal to zero.

Conditions for equilibrium First condition: The sum of all the forces is equal to zero: Fx = 0 Fy = 0 Fz = 0 Second condition: The sum of all torques about any given point is equal to zero.

Conditions for equilibrium First condition: The sum of all the forces is equal to zero: Fx = 0 Fy = 0 Fz = 0 Second condition: The sum of all torques about any given point is equal to zero.

Conditions for equilibrium First condition: The sum of all the forces is equal to zero: Fx = 0 Fy = 0 Fz = 0 Second condition: The sum of all torques about any given point is equal to zero.

C. a thrown baseball that does not rotate as it sails through the air Q11.1 Which of the following situations satisfies both the first condition for equilibrium (net force = 0) and the second condition for equilibrium (net torque = 0)? A. an automobile crankshaft turning at an increasing angular speed in the engine of a parked car B. a seagull gliding at a constant angle below the horizontal and at a constant speed C. a thrown baseball that does not rotate as it sails through the air D. more than one of the above E. none of the above Answer: B

A11.1 Which of the following situations satisfies both the first condition for equilibrium (net force = 0) and the second condition for equilibrium (net torque = 0)? A. an automobile crankshaft turning at an increasing angular speed in the engine of a parked car B. a seagull gliding at a constant angle below the horizontal and at a constant speed C. a thrown baseball that does not rotate as it sails through the air D. more than one of the above E. none of the above

Center of gravity We can treat a body’s weight as though it all acts at a single point— the center of gravity. If we can ignore the variation of gravity with altitude, the center of gravity is the same as the center of mass.

Walking the plank find the stable positions

Walking the plank find the stable positions

Q11.2 A rock is attached to the left end of a uniform meter stick that has the same mass as the rock. How far from the left end of the stick should the triangular object be placed so that the combination of meter stick and rock is in balance? less than 0.25 m 0.25 m C. between 0.25 m and 0.50 m D. 0.50 m E. more than 0.50 m Answer: B

A11.2 A rock is attached to the left end of a uniform meter stick that has the same mass as the rock. How far from the left end of the stick should the triangular object be placed so that the combination of meter stick and rock is in balance? less than 0.25 m 0.25 m C. between 0.25 m and 0.50 m D. 0.50 m E. more than 0.50 m

Will the ladder slip? find the tilt angles for stable conditions

Will the ladder slip? find the tilt angles for stable conditions

What is the tension in the cable? Q11.3 A metal advertising sign (weight w) is suspended from the end of a massless rod of length L. The rod is supported at one end by a hinge at point P and at the other end by a cable at an angle q from the horizontal. What is the tension in the cable? T = w sin q T = w cos q C. T = w/(sin q) D. T = w/(cos q) E. none of the above Answer: C

A11.3 A metal advertising sign (weight w) is suspended from the end of a massless rod of length L. The rod is supported at one end by a hinge at point P and at the other end by a cable at an angle q from the horizontal. What is the tension in the cable? T = w sin q T = w cos q C. T = w/(sin q) D. T = w/(cos q) E. none of the above

Which of these forces is least? A metal advertising sign (weight w) is suspended from the end of a massless rod of length L. The rod is supported at one end by a hinge at point P and at the other end by a cable at an angle q from the horizontal. Which of these forces is least? the weight of the sign the tension in the cable C. the vertical force component exerted on the rod by hinge P D. two or more of these are tied for least Answer: C

A11.4 A metal advertising sign (weight w) is suspended from the end of a massless rod of length L. The rod is supported at one end by a hinge at point P and at the other end by a cable at an angle q from the horizontal. Which of these forces is least? the weight of the sign the tension in the cable C. the vertical force component exerted on the rod by hinge P D. two or more of these are tied for least

Equilibrium and pumping iron Follow Example 11.4 using Figure 11.10 below.