M 112 Short Course in Calculus Chapter 5 – Accumulated Change: The Definite Integral Sections 5.1 – Distance and Accumulated Change V. J. Motto.

Slides:



Advertisements
Similar presentations
Section 8.5 Riemann Sums and the Definite Integral.
Advertisements

2.1 Derivatives and Rates of Change. The slope of a line is given by: The slope of the tangent to f(x)=x 2 at (1,1) can be approximated by the slope of.
LIMITS 2. In this section, we will learn: How limits arise when we attempt to find the tangent to a curve or the velocity of an object. 2.1 The Tangent.
Applied Calculus, 3/E by Deborah Hughes-Hallet Copyright 2006 by John Wiley & Sons. All rights reserved. Section 5.1: Distance and Accumulated Change Section.
Homework Homework Assignment #47 Read Section 7.1 Page 398, Exercises: 23 – 51(Odd) Rogawski Calculus Copyright © 2008 W. H. Freeman and Company.
Homework Homework Assignment #13 Read Section 3.5 Page 158, Exercises: 1 – 45 (EOO) Rogawski Calculus Copyright © 2008 W. H. Freeman and Company.
Homework Homework Assignment #4 Read Section 5.5
Copyright © Cengage Learning. All rights reserved. 5 Integrals.
M 112 Short Course in Calculus Chapter 2 – Rate of Change: The Derivative Sections 2.1 – Instantaneous Rate of Change V. J. Motto.
Chapter 5 Key Concept: The Definite Integral
Chapter 5 Integral. Estimating with Finite Sums Approach.
“Teach A Level Maths” Vol. 1: AS Core Modules
M 112 Short Course in Calculus Chapter 5 – Accumulated Change: The Definite Integral Sections 5.2 – The Definite Integral V. J. Motto.
M 112 Short Course in Calculus Chapter 2 – Rate of Change: The Derivative Sections 2.2 – The Derivative Function V. J. Motto.
If the integral cannot be evaluated, we can use an approximate method.
Copyright © Cengage Learning. All rights reserved. 4 Integrals.
Chapter 6 The Definite Integral.  Antidifferentiation  Areas and Riemann Sums  Definite Integrals and the Fundamental Theorem  Areas in the xy-Plane.
M 112 Short Course in Calculus Chapter 1 – Functions and Change Sections 1.5 Exponential Functions V. J. Motto.
CHAPTER 4 SECTION 4.4 THE FUNDAMENTAL THEOREM OF CALCULUS.
Chapter Four: Motion  4.1 Position, Speed and Velocity  4.2 Graphs of Motion  4.3 Acceleration.
Physics 1201W Lecture 2 Wednesday, September 10.
1 Motion along a straight line: Position, Displacement and Velocity Lecture 03 General Physics (PHYS101)
Warm-Up: (let h be measured in feet) h(t) = -5t2 + 20t + 15
I was on the second day of a road trip when I decided to keep a record of how far I had traveled from home. The table below shows how many hours I drove.
Chapter 5: Matter in Motion
SECTION 5.1: ESTIMATING WITH FINITE SUMS Objectives: Students will be able to… Find distance traveled Estimate using Rectangular Approximation Method Estimate.
Section 6.1 Antiderivatives Graphically and Numerically.
Review Problems Integration 1. Find the instantaneous rate of change of the function at x = -2 _ 1.
Velocity-time graphs. Edexcel Statements Velocity-time graph What story does the graph tell?
1/12/2016HL Math - Santowski1 Lesson 50 – Area Between Curves HL Math- Santowski.
Section 7.6 – Numerical Integration. represents the area between the curve 3/x and the x-axis from x = 4 to x = 8.
Rogawski Calculus Copyright © 2008 W. H. Freeman and Company Chapter 5: The Integral Section 5.1: Approximating and Computing Area Jon Rogawski Calculus,
Discuss how you would find the area under this curve!
In Chapters 6 and 8, we will see how to use the integral to solve problems concerning:  Volumes  Lengths of curves  Population predictions  Cardiac.
Tangents, Velocities, and Other Rates of Change Definition The tangent line to the curve y = f(x) at the point P(a, f(a)) is the line through P with slope.
Section 7.6 – Numerical Integration. represents the area between the curve 3/x and the x-axis from x = 4 to x = 8.
Resolve the vector into x & y components 40.0 m/s at 45 o SoW.
AP CALC: CHAPTER 5 THE BEGINNING OF INTEGRAL FUN….
Riemann Sums and the Definite Integral. represents the area between the curve 3/x and the x-axis from x = 4 to x = 8.
MAT 213 Brief Calculus Section 5.1 Results of Change and Area Approximation.
5.3 Definite Integrals and Riemann Sums. I. Rules for Definite Integrals.
DO NOW: v(t) = e sint cost, 0 ≤t≤2∏ (a) Determine when the particle is moving to the right, to the left, and stopped. (b) Find the particles displacement.
C.1.5 – WORKING WITH DEFINITE INTEGRALS & FTC (PART 1) Calculus - Santowski 6/30/ Calculus - Santowski.
Acceleration. Definition Any change in velocity is acceleration What are the possible causes of acceleration? Speeding up Slowing down Changing direction.
Section 5.1 Distance and Accumulated Change
Average Value Theorem.
Riemann Sums as Estimates for Definite Integrals
Review Practice problems
Chap. 2: Kinematics in one Dimension
Chapter Four: Motion 4.1 Position, Speed and Velocity
MOTION.
Accumulation AP Calculus AB Day 10
Speed and Velocity.
Unit 6 – Fundamentals of Calculus Section 6
Lecture 2 Chapter ( 2 ).
Physics: Principles with Applications, 6th edition
1. Integral as Net Change.
Copyright © 2014, 2010, 2007 Pearson Education, Inc.
Accumulation AP Calculus AB Day 13
Estimating with Finite Sums
Section Net Change in Position/Distance Traveled
Chapter Four: Motion 4.1 Position, Speed and Velocity
2.9 Linear Approximation.
Find the general indefinite integral. {image}
Estimating with Finite Sums
Section Net Change in Position/Distance Traveled
§ 6.4 Areas in the xy-Plane.
Riemann Sums as Estimates for Definite Integrals
Velocity-Time Graphs – Higher – GCSE Questions
Presentation transcript:

M 112 Short Course in Calculus Chapter 5 – Accumulated Change: The Definite Integral Sections 5.1 – Distance and Accumulated Change V. J. Motto

Suppose a car is moving with increasing velocity and suppose we measure the car's velocity every two seconds, obtaining the data in Table 5.1: At most how far has the car traveled? At least how far has the car traveled? the data in Table 5.1: 5/8/20152

Figure 5.2: Shaded area estimates distance traveled. Velocity measured every 2 seconds 5/8/20153

How do we improve our estimate? 5/8/20154

Figure 5.3: Shaded area estimates distance traveled. Velocity measured every 2 seconds 5/8/20155

Figure 5.4: Velocity measured every ½ second If the velocity is positive, the total distance traveled is the area under the velocity curve. Figure 5.5: Velocity measured every ¼ second Figure 5.6: Distance traveled is area under curve 5/8/20156

Problem 10 The rate of change of the world’s population, in millions of people per year, is given in the following table. (a)Use this data to estimate the total change in the world’s population between 1950 and (b)The world population was 2555 million people in 1950 and 6085 million people in Calculate the true value of the total change in the population. How does this compare with your estimate in part (a)? Year Rate of Change /8/20157

Based on the data, we will calculate the underestimate and the overestimate of the total change. A good estimate will be the average of both results. Underestimate of total change = 37 · · · · · 10 = was considered twice since we needed to calculate the area under the graph. Overestimate of total change = 41 · · · · · 10 = and 86 were considered twice since we needed to calculate the area over the graph. The average is: ( )/2 = 3400 million people. 5/8/20158 Solution to 10-a:

5/8/20159 The total change in the world’s population between 1950 and 2000 is given by the difference between the populations in those two years. That is, the change in population equals 6085 (population in 2000) − 2555 (population in 1950) = 3530 million people. Our estimate of 3400 million people and the actual difference of 3530 million people are close to each other, suggesting our estimate was a good one. Solution 10-b:

Problem 15 Two cars start at the same time and travel in the same direction along a straight road. Figure 5.11 gives the velocity, v, of each car as a function of time, t. Which car: (a)Attains the larger maximum velocity? (b)Stops first? (c)Travels farther? Figure /8/201510

5/8/ Part a Car A has the largest maximum velocity because the peak of car A’s velocity curve is higher than the peak of B’s. Part b Car A stops first because the curve representing its velocity hits zero (on the t-axis) first. Part c. Car B travels farther because the area under car B’s velocity curve is the larger. Solution to 15: