2.810 Car Suspensions James Penn 10/25/2010. Video 2008 2.810 Contest Second Round.

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Presentation transcript:

2.810 Car Suspensions James Penn 10/25/2010

Video Contest Second Round

Video Contest Final

Video 2008 Team C vs Speed Bump

Bump

No Suspension

Quarter Car Suspension Model

2 nd Order Frequency Response

Quarter Car Suspension Model

Car and Unsprung Responses

Quarter Car Suspension Design Unsprung mass should be much less than sprung mass. Suspension should be just stiff enough to keep the unsprung response faster than the input.

m c =0.5kg, m us =0.02kg, k s =150N/m, v=3m/s

Adding Damping to damp oscillation of sprung mass by order of magnitude in one period logarithmic decrement

m c =0.5kg, m us =0.02kg, k s =150N/m, c s =5.9Ns/m, v=3m/s

Half Car Suspension Model

2008 Team C, v=3.5m/s

2008 Team C, v=4m/s

2008 Team C

2008 Team C Halfcar Model UnitValue mcmc kg1.3 IcIc kg.m lflf m0.102 lrlr m0.127 k sf N/m2000 c sf N.s/m4 k sr N/m1600 c sr N.s/m2 m usf kg0.044 m usr kg0.6 k tf N/m6000 c tf N.s/m3.2 k tr N/m20000 c tr N.s/m6.4

Natural Frequencies Want low Want high

2008 Team C Redesign UnitValue mcmc kg1.3 IcIc kg.m lflf m0.102→0.127 lrlr m0.127→0.102 k sf N/m2000→800 c sf N.s/m4 k sr N/m1600→800 c sr N.s/m2 m usf kg0.044 m usr kg0.6→0.1 k tf N/m6000 c tf N.s/m3.2 k tr N/m20000 c tr N.s/m6.4

Natural Frequencies Want low Want high

2008 Team C Redesign, v=3.5m/s

2002 Team C (Record Holder)

2002 Team C Halfcar Model UnitValue mcmc kg2.25 IcIc kg.m lflf m.102 lrlr m k sf N/m∞ c sf N.s/mN/A k sr N/m∞ c sr N.s/mN/A m usf kgN/A m usr kgN/A k tf N/m6000 c tf N.s/m8 k tr N/m1200 c tr N.s/m10

2002 Team C, v=3.5m/s

Concluding Thoughts Minimize unsprung mass –If rear suspension is pivoting, move motor forward. Avoid placing center of mass far forward. Avoid making suspensions too stiff. –Thin, long sheets (k~(t/L) 3 ) –k parallelogram =2*E*b*(t/L) 3 ω n,c ≈30rad/s, ω n,us ≈100rad/s –