4.1 Exam Date – Wed 2/9 Topics Covered Listed on Class Website Sample Exam from a few years back is also on the web. Today Start Unit 5: Electric Potential.

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Presentation transcript:

4.1

Exam Date – Wed 2/9 Topics Covered Listed on Class Website Sample Exam from a few years back is also on the web. Today Start Unit 5: Electric Potential (Energy Methods) Wednesday  Monday More of the same Friday: Surprise – Quiz #2 (for real!)

Spring Break is just a few weeks away – (5ish)

The figure shows the electric field lines in the vicinity of two point charges. Which one of the following statements concerning this situation is true? A) q 1 is negative and q 2 is positive. B) The magnitude of the ratio (q 2 / q 1 ) is less than one. C) Both q 1 and q 2 have the same sign of charge. D) The magnitude of the electric field is the same everywhere. E) The electric field is strongest midway between the charges.

A cubical Gaussian surface is placed in a uniform electric field as shown in the figure. The length of each edge of the cube is 1.0 m. The uniform electric field has a magnitude of 5.0 × 10 8 N/C and passes through the left and right sides of the cube perpendicular to the surface. What is the total electric flux leaving the cubical Gaussian surface? A) 5.0 × 10 8 m 2 /C B) 3.0 × 10 9 N × m 2 /C C) 2.5 × 10 6 N × m 2 /C D) 1.5 × 10 7 N × m 2 /C E) zero N × m 2 /C

What is the electric flux passing leaving a Gaussian surface that surrounds a C point charge? A) 8.5 × 10 9 N × m 2 /C B) 6.8 × 10 8 N × m 2 /C C) 1.3 × 10 7 N × m 2 /C D) 4.9 × 10 6 N × m 2 /C E) 7.2 × 10 5 N × m 2 /C  0 = 8.85×10 −12 SI Units

A solid, conducting sphere of radius a carries an excess charge of +6 µ C. This sphere is located at the center of a hollow, conducting sphere with an inner radius of b and an outer radius of c as shown. The hollow sphere also carries a total excess charge of +6 µ C. Determine the excess charge on the outer surface of the outer sphere (a distance c from the center of the system). A) zero coulombs B) – 6  C C) +6  C D) +12  C E) – 12  C

+ Mrs. Field Mr. External

Mrs. Field Mr. External

E + charge Mr. ExternalMrs. Fields That was HARD WORK Mr. External Sure Was Mrs. Field Each does the negative amount of work that the other one does. Constant Speed

The net work done by a conservative (field) force on a particle moving around a closed path is ZERO!

The work necessary for an external agent to move a charge from an initial point to a final point is INDEPENDENT OF THE PATH CHOSEN!

A conservative force is NOT a Republican. An External Agent is NOT 007.