Are you using the right CT's and PT's for your application Are you using the right CT's and PT's for your application? John Levine, P.E. Levine Lectronics and Lectric E-mail: John@L-3.com GE Multilin / Instrument Transformers, Inc.

Alternate Title of Presentation Now I know what I do not know about CT’s and PT’s. As engineers we do not need to know all the answers just where to get them.

Current & Voltage Transformer Basics (IEEE Standards)

Agenda Current Transformers Voltage Transformers Required Information for Specifying CTs & VTs Take Home Rules” for CTs & VTs Applications where used

Why use Instrument Transformers? Circuit Isolation Reduce voltage and currents to reasonable working levels. Phasor combinations for summing and measuring power

TYPES OF C.T. CONSTRUCTION CURRENT TRANSFORMERS   TYPES OF C.T. CONSTRUCTION The most common type of C.T. construction is the “DOUGHNUT” type. It is constructed of an iron toroid, which forms the core of the transformer, and is wound with secondary turns.   Secondary Winding Primary Conductor Iron Core The `doughnut' fits over the primary conductor, which constitutes one primary turn. If the toroid is wound with 240 secondary turns, then the ratio of the C.T. is 240 : 1 or 1200 : 5A The continuous rating of the secondary winding is normally 5 AMPS in North America, and 1 AMP or 0.5 AMP in many other parts of the world. This type of `doughnut' C.T. is most commonly used in circuit breakers and transformers. The C.T. fits into the bushing `turret', and the porcelain bushing fits through the centre of the `doughnut'. Up to four C.T.'s of this type can be installed around each bushing of an oil circuit breaker. This arrangement is shown in the following diagram.

_____________________ Transformer ratio (TR) Primary Current Secondary Current Transformer Ratio = _____________________ Primary Current (100 amps) Secondary Current (5 amps) 100 5 ___ = 100:5 or 20:1

Polarity Remember: Primary current into “polarity” = Direction of Secondary Current Direction of Primary Current Secondary Polarity Marks IEEE X1 S1 IEC Primary Polarity Marks IEEE H1 IEC P1 Remember: Primary current into “polarity” = Secondary current out of “polarity”

Polarity Remember: Primary current into “non-polarity” = Direction of Secondary Current Secondary Polarity Marks IEEE X1 S1 IEC Primary Polarity Marks IEEE H1 IEC P1 Direction of Primary Current Remember: Primary current into “non-polarity” = Secondary current out of “non-polarity”

Generator typical wiring

What is your application? If your application is metering , how high do I need to go in current? 2 times ? If your application is protective relaying, how high do I need to go in current? 20 times ? 40 times ? 400 amps times 20 = 8,000 amps, 400 amps times 40 = 16,000 amps

CT Rating Factor (RF) -- IEEE Rated current x (RF) = Maximum continuous current carrying capability: Without exceeding temperature limits Without loss of published accuracy class Typical rating factors for Metering CTs are: 1.0, 1.33, 1.5, 2.0, 3.0, 4.0

CT Rating Factor (RF) -- IEEE IEEE C57.13 Accuracy 0.3% @ BX.X RF 4.0 0.60 0.6% Accuracy Region 0.30 0.3% Accuracy Region Accuracy Class - % 10% 100% 200% 300% 400% 0.30 If I want better accuracy, I could use a 25 to 5 CT instead of a 50 to 5 CT and let it operate between 100% and 200% if I do not exceed the rating factor. 0.60 1.0 2.0 3.0 4.0 Rating Factor

Short-Time Thermal Current Rating One (1) – second thermal rating Expressed as value of RMS primary current Main influencing factor: CT primary & secondary wire size Can be converted to thermal rating for any time period (t) up to five (5) seconds: (New RF at new Ambient/Stated RF at 30 degrees C)2= 85-New Ambient/New Ambient Example: CT with rating factor of 4 at 30 degrees = rating factor of 2.95 at 55 degrees X2/42=85-55/55 X=2.95

Difference in % is known as the “Accuracy” CT Metering Accuracy = Actual secondary current Rated secondary current Difference in % is known as the “Accuracy” of the CT

IEEE CT Metering Accuracy Class ( * ) Application 0.15 High Accuracy Metering 0.15S “Special” High Accuracy Metering 0.3 Revenue Metering 0.6 Indicating Instruments 1.2 Indicating Instruments * All accuracy classes defined by IEEE C57.13 or C57.13.6 * Accuracy classes include both ratio & phase angle error

IEEE CT Metering Accuracy Burden Load connected to CT secondary Includes devices & connecting leads Expressed in ohms Standard values = B0.1, B0.2, B0.5, B0.9, B1.8 E0.04, E0.2 All burdens defined by IEEE C57.13 or C57.13.6 for 60 Hz only

IEEE CT Metering Accuracy Standard IEEE CT Burdens (5 Amp) (Per IEEE Std. C57.13-1993 & C57.13.6) E0.2 E0.04 0.2 0.04 5 1 1.0

CT CLASSIFICATION for Metering A current transformer for metering purposes may typically have an accuracy of 0.3%. The C.T. must maintain this accuracy for normal load currents, provided the rated burden on the C.T. is not exceeded. It is quite acceptable, and in fact desirable, for the C.T. to saturate when fault current flows. The accuracy for a typical metering C.T. is specified as:   0.3 M 0.9 O.3% METERING O.9 OHMS BURDEN This metering C.T. has an accuracy of 0.3% when the connected burden does not exceed 0.9 OHMS.

IEEE CT Metering Accuracy “Accuracy” expressed as: Typical Examples + = Accuracy Class (0.3, 0.6, 1.2) (*) Burden (Ohms) (B0.1, B0.2, B0.5, B0.9, B1.8) 0.3B0.2 0.6B0.9 1.2B1.8 0.15E0.2 (0.15*, 0.15S^) E0.2, E0.04) * Accuracy class is stated at 100% rated current * At 10% rated current, twice the error is allowed (5% for 0.15 class) ^ Accuracy class is stated at 100% to 5% rated current

IEEE CT Metering Accuracy IEEE C57.13 Accuracy 0.3 @ BX.X; RF 4.0 0.60 0.6% AccuracyRegion 0.30 0.3% Accuracy Region Accuracy Class - % 10% 100% 200% 300% 400% 0.30 If I want better accuracy, I could use a 25 to 5 CT instead of a 50 to 5 CT and let it operate between 100% and 200% if I do not exceed the rating factor. No accuracy guaranteed at current levels less than 10% 0.60 1.0 2.0 3.0 4.0 Rating Factor

IEEE CT Metering Accuracy CT Parallelogram – IEEE C57.13 0.3 class parallelogram 10% 100% 0.6 class parallelogram Note: Burden must be specified Horizontal line shows the phase angle. Out of 0.3% Class

IEEE CT Metering Accuracy CT Parallelogram – IEEE C57.13 0.3 class parallelogram 10% 100% 0.6 class parallelogram Note: Burden must be specified Horizontal line shows the phase angle. Corrected to 0.3% Class

IEEE CT Metering Accuracy IEEE C57.13.6 Accuracy 0.15 @ E0.04, E0.20; 0.15 @ BX.X; RF4.0 0.60 0.30 0.15% Accuracy Region 0.15 0.3% AccuracyRegion Accuracy Class - % 5% 100% 200% 300% 400% 0.15 0.30 No accuracy guaranteed at current levels less than 5% 0.60 1.0 2.0 3.0 4.0 Rating Factor

IEEE CT Metering Accuracy IEEE C57.13.6 Accuracy 0.15S @ E0.04, E0.20; 0.15S @ BX.X, RF4.0 0.60 0.30 0.15% Accuracy Region 0.15 Accuracy Class - % 5% 100% 200% 300% 400% 0.15 0.30 S means stepless No accuracy guaranteed at current levels less than 5% 0.60 1.0 2.0 3.0 4.0 Rating Factor

Standard Relay Accuracy Classes IEEE CT Relay Accuracy Protection CT Standard Relay Accuracy Classes C or T100 C or T200 C or T400 C or T800 What do these mean?

IEEE CT Relay Accuracy Relay class (C or T___ ) designates minimum secondary terminal volts… At 20 times rated current Without exceeding 10% ratio error Into a maximum specified burden Now that everyone is totally confused let’s look at some simple examples …

CT CLASSIFICATION for RELAYING Protection Class CT’s - Must supply 20 times rated current 10 C 400 Format Accuracy Voltage at 20 times CT Letter CT Classification for relaying Over the years many standards for CT classification have been developed in North America and Europe. Protection class CT’s are assumed to be able to supply 20 times its rated secondary current to the relay. That means for a 5 amp rated secondary the CT must be able to supply 100 Amps of current, and for a 1 amp rated secondary the CT must be able to supply 20 Amps of current. The operating principals of CT’s are specified in a format such as this. The first number represents the maximum amount of error, listed in as a percentage, that this CT will produce. Therefore, the 10 in our example stands for no more then 10 percent error. The second item, which is always a letter, can either be a T, C, K, L, or H. If the letter is a T which stands for “test”, it means that the CT accuracy can only be determined by testing the CT. Current transformers with non-distributed windings fit in this category. If the letter is a C or a K which stands for “Calculated”, it means the CT accuracy can be determined by performing calculation using given excitation characteristics. CTs with fully distributed windings, (bushing CT’s for instance) fit in this category. If the letter is an L, this indicates that the CT has a “Low internal secondary impedance,” If the letter is an H, this indicates that the CT has a “high internal secondary impedance,” T = Determined by test C = Calculated K = Calculated L = Low internal secondary impedance H = High internal secondary impedance

IEEE CT Relay Accuracy C or T100 example Secondary current 100 amps (20 x 5) X1 X2 Burden of Devices () Primary current 24,000 amps (20 x 1200) Total Ext Burden 1.0  Terminal Volts = 100 CT 1200:5 C or T100 Burden of Leads () Terminal Volts = (20 times rated) (Total external burden) 100 Volts = (100 amps) (1.0  )

IEEE CT Relay Accuracy C or T200 example Secondary current 100 amps (20 x 5) X1 X2 Burden of Devices () Primary current 24,000 amps (20 x 1200) Total Ext Burden 2.0  Terminal Volts = 200 CT 1200:5 C or T200 Burden of Leads () Terminal volts = (20 times rated) (Total external burden) 200 Volts = (100 amps) (2.0  )

IEEE CT Relay Accuracy Standard IEEE CT Burdens (5 Amp) (Per IEEE Std. C57.13-1993)

IEEE CT Relay Accuracy Excitation curve includes voltage required to overcome internal resistance (DCR) of CT. Approximately 32 volts. 10% ratio error = (20 x 5) (10%) = (100) (0.10) = 10 amps This Ct is not a C200. Since you can only produce 209 volts, when you take the 32 volts from internal resistance you only have 177 Volts so you can only rate it at C100 How many terminal volts would you estimate this CT can produce?

With 10% error, IB is anywhere from 4.5 to 5.5 amps 1000:5 CT IB >4.5 amps 1000 Amps 5amps IE<0.5amps With 10% error, IB is anywhere from 4.5 to 5.5 amps Most Protection CT’s also have a Metering CT accuracy so you could use this value for calculating the error at lower currents

CT Burden Calculation How do we calculate this? Secondary current X1 X2 Primary Current Burden of Devices () Total Burden ZT CT Burden of Leads ()

CT Burden Calculation ZT = RCT + RL + ZB ZT = Total burden in ohms (vector summation of resistance and inductance components) RCT = CT secondary resistance in ohms @75 deg C (DCR) RL = Resistance of leads in ohms (Total loop distance) ZB = Device impedance in ohms Assumption: 3 phase CTs are “Y” connected

GE Multilin Electronic Relay Burden VA = VI. V= IR, So 0.2 = I*I*R. .2/25 = .008 ohms

100:5 C.T. Secondary Winding Resistance (DCR) = .062 ohm Resistance of Cable from C.T. to Relay and back = .1 ohms Resistance of Relay Coil = .02 ohms Total Resistance = .182 ohms .062 .02 .1 If we have a fault of 2,000 amps and the C.T. ratio is 100:5 then the C.T. secondary current is 100 amps. Therefore we will produce a voltage of 100 amps x .182 ohms = 18.2 Volts. To prevent CT saturation, select a CT with a knee point above 18.2 Volts. In this example the resistance of the C.T. secondary circuit, or C.T. burden is: C.T. Secondary Winding Resistance = 1 OHM Resistance of Cable from C.T. to Relay = 2 OHMS Resistance of Relay Coil = 2 OHMS Total Resistance of C.T. Secondary Circuit = 5 OHMS   If the fault current is 12,000 Amps, and the C.T. ratio is 1200 : 5A, then the C.T. secondary current is 50 Amps. At this secondary current and the above C.T. burden of 5 OHMS, the C.T. must produce a terminal voltage of 250 volts. For the C.T. to operate with good accuracy, without saturating for the maximum fault current, the knee point must be well above 250 volts.

1000:5 C.T. Secondary Winding Resistance (DCR) = .32 ohm 780-102 is a 1000 to 5 CT, Class C100 1000:5 C.T. Secondary Winding Resistance (DCR) = .32 ohm Resistance of Cable from C.T. to Relay and back = .1 ohms Resistance of Relay Coil = .008 ohms Total Resistance = .428 ohms .32 .008 .1 If we have a fault of 20,000 amps and the C.T. ratio is 1000:5 then the C.T. secondary current is 100 amps. Therefore we will produce a voltage of 100 amps x .428 ohms = 42.8 Volts. To prevent CT saturation, select a CT with a knee point above 42.8 Volts. What happens if the fault current is 40,000 amps? Here is another exampe with very high resistance in the circuit. In this example the resistance of the C.T. secondary circuit, or C.T. burden is: C.T. Secondary Winding Resistance = 1 OHM Resistance of Cable from C.T. to Relay = 2 OHMS Resistance of Relay Coil = 2 OHMS Total Resistance of C.T. Secondary Circuit = 5 OHMS   If the fault current is 12,000 Amps, and the C.T. ratio is 1200 : 5A, then the C.T. secondary current is 50 Amps. At this secondary current and the above C.T. burden of 5 OHMS, the C.T. must produce a terminal voltage of 250 volts. For the C.T. to operate with good accuracy, without saturating for the maximum fault current, the knee point must be well above 250 volts.

Factors Influencing CT Accuracy Frequency “Low frequency” and “High accuracy” are not friends!! Current Ratio “Low ratio” and “high accuracy” are not friends!! Burden “High burden” and “High Accuracy” are not friends!!

CT Saturation What is CT Saturation?

Power Systems Relay Committee (PSRC) Saturation Calculator Note in the first cycle the secondary current does not saturate as quickly as in the second cycle. This is called time to saturate.

Factors Affecting Degree of Saturation and Time to Saturation DC Offset Fault Magnitude (symmetrical current) 100 to 5 CT@20 times= 2000 amps, at 20,000 amps we have 200 times CT CT Turns Ratio Secondary Burden CT Accuracy Remanence Flux Can occur if current interrupted when core is saturated If DC flows in windings during testing Need a voltage above 60% of knee point to reduce the remanence to less than 10% of saturation flux density.

Tips for Avoiding CT Saturation Use higher ratio CTs Use separate set of high ratio CTs for high fault current tripping Reduce secondary burden Select low burden relays & meters Distribute single phase burdens among phases Increase size of secondary leads Reduce length of secondary leads Use “step down” auxiliary CTs

Potential Transformers

Definitions Voltage Transformer (VT) An instrument transformer used to reflect a primary voltage into a secondary voltage through a magnetic medium. Always connected in parallel with primary conductor across a circuit load. Secondary (measuring) voltage is usually 115 or 120 volts nominally. The secondary voltage level is selected for ease of measurement and safety. Control Power Transformer (CPT) Designed to provide power for contractors, relays and devices with high inrush currents, Regulation is not as critical.

POTENTIAL TRANSFORMERS VP 14,400/120 = 120/1 4200/120 = 35/1 2400/120 = 20/1 Potential Transformers Potential transformers are used to isolate and step down and accurately reproduce the scaled voltage for the relay. The primary side of a PT needs to have the System voltage, symbolized as Vp, applied across the input terminals as shown here. The Secondary side of the PT will then accurately replicates a scaled down version the primary voltage over a defined voltage range . The secondary voltage is symbolized as Vs. There are two types of potential transformers: Electromagnetic voltage transformer and the capacitive voltage transformers. Vs Relay

IEEE VT Accuracy Class Metering Accuracy Classes (% error) 0.3 0.6 1.2 0.15 Defined by IEEE C57.13 Applicable from 90% to 110% rated voltage Defined by IEEE C57.13.6

IEEE VT Accuracy Class Metering Accuracy Class Burdens These standard burden designations have no significance at frequencies other than 60 Hz.

IEEE VT Accuracy Class Expressed as: Accuracy Class + Burden Code 0.3 W,X,Y 0.6 Z 1.2 ZZ These standard designations have no significance at frequencies other than 60 Hz.

VT Installation Guidelines Caution: Rated voltage: Do not operate above 110% Line to ground rated: Do not connect line to line Do not use on ungrounded systems w/o consulting factory Rated Frequency: Do not operate below rated frequency w/o consulting factory

IEEE VT Groups VT Group No. of Bushing Connection Method Neutral Grounding Notes 1 2 open  Y-Y possible Any Withstand 25% over rated voltage on an emergency basis Withstand 10% over rated voltage continuously. Primary rated for line to line voltage. 3 Y-Y-Y Outdoor, two secondary windings. Withstand 10% over rated voltage continuously. 4A Y-Y Effectively Withstand 10% over rated voltage continuously & 25% on an emergency basis. For operation at 100% rated voltage. 4B Y-Broken Corner  Non-effectively Withstand 10% overvoltage continuously. For operation at 58% rated voltage. 5 Outdoor. Withstand 40% over rated voltage for 1 minute and 10% over rated voltage continuously

VT Typical Connections Open Delta Connection (2) Double Bushing VTs Y – Y Connection (3) Single Bushing VTs

Ferroresonance Possible with Y connected grounded VTs on ungrounded power systems A VT is an inductive component Capacitance to ground exists in the system When they match ferroresonance may occur May cause higher VT voltages & saturation Possible results -- High VT currents Overheating VT failure

Ferroresonance Recommended reading: “Ferroresonance of Grounded Potential Transformers on Ungrounded Power Systems” AIEE Power Apparatus & Systems, Aug 1959, pg 607-618, by Karlicek and Taylor

Ferroresonance Damping Preferred method Non effectively grounded system Y – Broken Corner  VT connection Voltage relay to detect ground fault 0 volts @ normal condition 3 times normal L-N phase voltage @ ground fault Ferroresonance damping resistor RFR

Ferroresonance Damping Preferred method Y-Y/Broken Corner  Connection Double secondary VT (1) Relaying / Metering (1) Ground fault detection and ferroresonance damping

Ferroresonance Damping Ferroresonance damping resistor RFR value Based on 2 variables: Air core inductance of primary winding (La) VT ratio (N) RFR = 100 La / N2 Power rating (watts) of the resistor is a system related problem. General recommendation is 50% of VA rating of a single VT.

for Specifying CTs & VTs Required Information for Specifying CTs & VTs

Current Transformer (CT) RFQ Specification Environment: ___Indoor ___Outdoor System Voltage (kV) 0.6 0.72 3.6 5.0 7.2 8.7 12 15 24 25 34.5 Power Frequency (kV) 4 3 10 19 20 26 28 34 50 40 70 BIL (kV) 10 40 60 75 110 125 150 200 Standard (Check one) IEEE __ IEC __ IEC __ IEEE __ CT Application: ___Metering ___Protection Dimensions: ___ Inches ___ mm Max. Outside: L ______ x W ______ x D ______ CT Window: Round: ______ Diameter; Rectangular: L ______ x W ______ ; Primary Bar: _____ Current Ratio: _______ : 5 _______ : 1 Continued next slide

Current Transformer (CT) RFQ Specification (Continued) Accuracy: Indication Only: _____ %, _____VA (Skip metering & protection selections) Metering Class: IEEE: ___0.3 ___0.6 ___1.2 ___2.4 ________Other IEC: ___0.2 ___0.5 ___1.0 ________Other Metering Burden: IEEE (Ohms): ___B0.1 ___B0.2 ___B0.5 ___B0.9 ___B1.8 ______Other IEC (VA): ___2.5 ___5.0 ___10 ___15 ___30 ______Other Protection Class: C______(IEEE) ___VA, ___P___(IEC) Operating Frequency: ___60HZ ___50HZ Rating Factor: ___1.0 ___1.33 ___1.5 ___2.0 ______Other Secondary Connections: ___Terminals ___24 inch leads Outer Insulation: ___Standard ___Cotton tape & varnish ___Polyester tape Insulation Class: ___105 0C (Standard) _____Other Other Special Requirements (dimensional constraints, mounting requirements, …etc): ______________________________________________________________________________

Voltage Transformer (VT) RFQ Specification Environment: ___Indoor ___Outdoor System Voltage (kV) 0.6 0.72 3.6 5.0 7.2 8.7 12 15 24 25 34.5 Power Frequency (kV) 4 3 10 19 20 26 28 34 50 40 70 BIL (kV) 10 40 60 75 110 125 150 200 Standard (Check one) IEEE __ IEC __ IEC __ Operating Frequency: ___60HZ ___50HZ Accuracy: IEEE: ___W ___X ___M ___Y ___Z ___ZZ ________Other (Enter 0.3, 0.6, 1.2, or leave blank) IEC: ___10VA ___25VA ___50VA ___100VA ___200VA ___500VA ______Other (Enter 0.2, 0.5, 1.0, or leave blank) Continued next slide

Voltage Transformer (VT) RFQ Specification (Continued) Thermal Rating: _______VA (Optional) Primary Voltage: ___1 bushing _________VAC - Phase to neutral ___2 bushing _________VAC - Phase to phase Secondary Voltage: ___120V ___115V ___110V ___100V ___120/3 ___115/3 ___110/3 ___100/3 ___Other _________________ Rated Voltage Factor (RVF) (1 bushing only): ___1.9 for 30s ___1.9 for 8 hours ___Other____________ Fuses: ___Primary ___Secondary ___None (600 – 720 V) ___Primary ___Live parts only ___Switchgear Style ___Unfused (2.5kV – 15kV) Note integral fusing not available above 15kV

Take Home Rule # 1 Never open circuit a current transformer secondary while the primary is energized CTs are intended to be proportional current devices. Very high voltages can result from open circuiting the secondary circuit of an energized CT. Even very small primary currents can cause damage… Consult the factory if you have questions.

Take Home Rule # 2 Never short circuit the secondary of an energized VT VTs are intended to be used as proportional voltage devices. Damaging current will result from short circuiting the secondary circuit of an energized VT.

Take Home Rule # 3 Metering applications do not require a “C” class CT “C” class ratings are specified for protection purposes only. With some exceptions metering class CTs are typically smaller and less expensive.

Take Home Rule # 4 CT secondary leads must be added to the CT burden Electronic relays usually represent very little burden to the CT secondary circuit. In many cases the major burden is caused by the CT secondary leads.

Take Home Rule # 5 Never use a 60 Hz rated VT on a 50 Hz System 60 Hz VTs may saturate at lower frequencies and exceed temperature limitations. VT failure is likely…severe equipment damage is possible.

Take Home Rule # 6 Exercise caution when connecting grounded VTs to ungrounded systems Line to ground voltage on any VT may exceed the primary voltage rating during a fault condition… VT must be designed for application.

Take Home Rule # 7 It is common practice to apply 600 Volt CT to systems with higher voltages. This practice is done by passing fully insulated conductors through the Window.

QUESTIONS?

LV Switchboards LV Panelboards Typical CT Models 5 Series 19RT 8SHT

LV Switchboards LV Panelboards Typical VT Models 460, 467, 475, 2VT460, 3VT460

L.V. MCC’s Typical CT Models 5 Series 19RT 8SHT 3P85

L.V. MCC’s Typical VT Models 460, 467, 475, 2VT460, 3VT460

L.V. Switchgear

L.V. Switchgear Current Transformers GE 2000 amp frame Model 560 Metering Model 561 Protection

L.V. Switchgear Current Transformers GE 4000 amp frame Model 562 Metering Model 563 Protection

L.V. Switchgear No more room in the front? We can recommend a different model CT for the rear bus area.

L.V. Switchgear Typical 3 Phase VT Installation 3VTL460 3 Phase VT

M.V. Switchgear Typical Line Up Where are the CTs, VTs, and CPTs?

M.V. Switchgear Current Transformers 778 / 779 680 /780 Series Typical IEEE Metering & Protection

M.V. Switchgear Current Transformers Metering & Protection Model 780, 778 Model 785

M.V. Switchgear Model 203 CTs mounted in rear bus compartment

Is this better than a Residual Connection? M.V. Switchgear Zero Sequence CT Model 593, 594 Is this better than a Residual Connection?

M.V. Switchgear Typical VT Rollout Drawer Installed in enclosure (2) PTG5’s in open delta configuration Withdrawn from enclosure

M.V. Switchgear Typical CPT Rollout Drawer CPT 5 & 15 kV 5 to 15 kVA Withdrawn from enclosure Installed in enclosure

MV MCC’s Let’s open a door and see what’s inside

MV MCC’s Typical CT Models 112 113 114 115 117

Generators Board Mounted Generator CT

Station Class Circuit Breakers Polyester Taped Bushing CT on Outdoor Circuit Breaker

Station Class Circuit Breakers Ground Shield Outdoor BO7 - Replaces BCT’s in shielded aluminum housing

Power Transformers Slip over current transformer for installation over exterior of outdoor bushing Outdoor Type BO7 for Retrofit

Power Transformers Metering applications for indoor instrument transformers on outdoor power transformers Air terminal chamber Indoor PT and Bar type CT

Questions?