Distance Formula Vicente Rosalia Alcantara NIE/CTP- Math.

Slides:



Advertisements
Similar presentations
Proving the Distance Formula
Advertisements

Sec 1-3 Concept: Use Midpoint and Distance Formulas
1.3 What you should learn Why you should learn it
The Distance Formula The distance formula is used to find the Length of the segment.
Objective: Determine if triangles in a coordinate plane are similar. What do we know about similar figures? (1)Angles are congruent (2)Sides are proportional.
EXAMPLE 1 Classify triangles by sides and by angles SOLUTION The triangle has a pair of congruent sides, so it is isosceles. By measuring, the angles are.
4.1 – Classifying Triangles. Triangles A polygon with three sides. The corners are called vertices A triangle with vertices A, B, and C is called “triangle.
1. Show geometrically that given any two points in the hyperbolic plane there is always a unique line passing through them. § 23.1 Given point A(x1, y1)
Slide The Pythagorean Theorem and the Distance Formula  Special Right Triangles  Converse of the Pythagorean Theorem  The Distance Formula: An.
THE DISTANCE FORMULA ALGEBRA 1 CP. WARM UP Can the set of numbers represent the lengths of the sides of a right triangle? 4, 5, 6.
1-2 Measuring Segments Objectives
EXAMPLE 1 Classify triangles by sides and by angles Support Beams
(x 1, y 1 ) (x 2, y 2 (x 1, y 1 ) (x 2, y 2 ) |x 1 – x 2 | |y 1 – y 2 | d.
1-3 The Distance and Midpoint Formulas
The Distance and Midpoint Formulas
Lesson 1-3 Distance and Midpoint.
1-6 Midpoint and Distance in the Coordinate Plane Warm Up
1-8 The Coordinate Plane SWBAT: Find the Distance between two points in the Coordinate Plane. Find the Coordinates of a Midpoint of a segment.
Midpoint and Distance Formulas Goal 1 Find the Midpoint of a Segment Goal 2 Find the Distance Between Two Points on a Coordinate Plane 12.6.
8-1, 1-8 Pythagorean Theorem, Distance Formula, Midpoint Formula
 Congruent Segments – › Line segments that have the same length.  Midpoint – › The point that divides a segment into two congruent segments.  Segment.
The Distance and Midpoint Formulas
4-9 Isosceles and Equilateral Triangles
Aim: Distance Formula Course: Applied Geometry Do Now: Aim: How do we use the Pythagorean Theorem to find the distance between two points? In inches,
Distance.
The Coordinate Plane Section 1.6. Goal - After today, you will be able to:  Find the distance between any two points in the coordinate plane.  Find.
Presented by: LEUNG Suk Yee LEUNG Wing Yan HUI Hon Yin LED 3120B PowerPoint Presentation.
Lesson 5.2 Perimeter / area. Obj: to calculate Perimeter + area on a coordinate plane Rectangle P = 2L + 2W A = L x W Square P = 4 x S A = S 2.
The Distance Formula (and mid point). What is to be learned? How to calculate the distance between two points.
1-6 Midpoint and distance in the coordinate plane
1.7: Midpoint and Distance in the Coordinate Plane Part II.
Goal 1: Use segments postulates Goal 2: Use the distance Formula to measure distances. CAS 1,15,17.
Geometry: Points, Lines, Planes, and Angles
1.8 Midpoint & Distance Formula in the Coordinate Plane Objective: Develop and apply the formula for midpoint. Use the Distance Formula and the Pythagorean.
APRIL 30 TH, 2014 Midpoint & Distance. Get notes out! Write this down Vocabulary Midpoint: divides a segment into two congruent pieces Segment Bisector:
1 Then the lengths of the legs of ABC are: AC = |4 – (–3)| = |7| = 7 BC = |6 – 2| = |4| = 4 To find the distance between points A and B, draw a right triangle.
Integrated Math II Lesson 22 Special Segments in Triangles.
Warm Up.
Right Triangle The sides that form the right angle are called the legs. The side opposite the right angle is called the hypotenuse.
1.3 Segments & Their Measures.
Rectangular Coordinates
Sect. 5.4 Midsegment Theorem
5.1: Midsegments of Triangles
Practice Test Unit 3 Geometry
Midpoint and Distance in the Coordinate Plane
1. Find the distance between HINT FOR MULTIPLE CHOICE!
Length of a Segment Let A and B be points on a number line, with coordinates a and b. Then the measure of segment AB is.
4.9: Isosceles & equilateral triangles
Drawing Triangles.
Linear Measure Line Segment - A measurable part of a line that consists of two points, called the endpoints, and all the points between them. A segment.
1-6 Midpoint & Distance in the Coordinate Plane
Notes #3 (1.3) 1-3 Distance and Midpoints
P.5 The Cartesian Plane Our goals are to learn
Distance Distance – The length of a segment, found by using the coordinates of the endpoints. If the segment is part of a number line (either horizontal.
Math Humor Q: What keeps a square from moving?.
In the diagram at the left, AB is a horizontal line segment.
The Distance Formula     Understand horizontal/vertical distance in a coordinate system as absolute value of the difference between coordinates;
Distance between Any Two Points on a Plane
In the diagram at the left, AB is a horizontal line segment.
Warm Up Solve each equation. 1. 2x – 6 = 7x – /4 x – 6 = 220
Perimeter and Area of Similar Figures
1. Find the distance between HINT FOR MULTIPLE CHOICE!
Objectives Develop and apply the formula for midpoint.
By Angle Measures By Side Lengths
Question 10.
1. Find the distance between HINT FOR MULTIPLE CHOICE!
Recall Retrieved from:
1-6: Midpoint and Distance
Unit 2.
The Distance Formula     Understand horizontal/vertical distance in a coordinate system as absolute value of the difference between coordinates;
Presentation transcript:

Distance Formula Vicente Rosalia Alcantara NIE/CTP- Math

Direction: Read carefully the following five multiple choice questions. Choose the correct answer for each number by clicking the triangle beside each option.

1. Points A and B are on the same line. If A(x 1, y 1 ) and B(x 2, y 2 ), find the length of line segment AB ? a. AB = √ (x 2 + x 1 ) 2 - ( y 2 + y 1 ) 2 b. AB = √ (x 2 - x 1 ) 2 + ( y 2 - y 1 ) 2 c. AB = √(x 1 + y 1 ) 2 - ( x 2 + y 2 ) 2 d. AB = √(x 1 - y 1 ) 2 + ( x 2 - y 2 ) 2

CORRECT In Cartesian Coordinate Plane, a line can be presented by defining the coordinates of its two endpoints, i.e. for line AB,pt. A(x 1, y 1 ) and B(x 2, y 2 ). By knowing the two endpoints of a line, we can find the length of the line segment or the distance between two points. B (x 2, y 2 ) CA(x 1,y 1 ) y x 0 By Pythagorean Theorem AB 2 = AC 2 + BC 2 = ( x 2 -x 1 ) 2 + ( y 2,y 1 ) 2 = √( x 2 -x 1 ) 2 + ( y 2,y 1 ) 2 Note: When we calculate the length of a line AB, we can interchange the coordinate values of A and B, and we still get the same value for length AB.

WRONG Sorry, you did not get the correct answer! Go back and try again.

2. If A and B has a coordinates (1,1) and (4,5) respectively, find the distance between the two given points. a. √ 61 units b. 25 units c. 5 units d. 1 unit

CORRECT Solution: If A (1,1) and B (4,5), then x 1 =1 ; y 1 =1 and x 2 =4 ; y 2 =5 By Pythagorean Theorem AB 2 = AC 2 + BC 2 = √( x 2 - x 1 ) 2 + ( y 2,y 1 ) 2 = √ (4 – 1) 2 + (5 - 1) 2 = √ (3) 2 +(4) 2 = √ = √ 25 = 5 Note: When we calculate the length of a line AB, we can interchange the coordinate values of A and B, and we still get the same value for length AB.

WRONG Sorry, you did not get the correct answer! Go back and try again.

3. If points A(-2,8), B(0,y) and C( 2,0) lie on the same straight line, find the value of y if AB = BC. a. 4 b. √8 c. 16 d. √20

CORRECT Solution: a. First, find the length of AB and BC in terms of y; Length of AB 2 = [0-(-2)] 2 + (y-8) 2 Length of BC 2 = (2-0) 2 +(0-y) 2 AB 2 = (y-8) BC 2 = y AB = √(y – 8) BC = √ y b. Then solve for y; √(y – 8) = √ y y 2 – 16y + 64 = y 2 16y = 64 ; y = 4 c. Therefore; AB = √(y – 8) BC =√ y AB = √(4 -8) BC = √ AB = √20 BC =√ 20

WRONG Sorry, you did not get the correct answer! Go back and try again.

4. Points X,Y and Z are the vertices of Isosceles Triangle XYZ. If the coordinates of X, Y and Z are (2,3),(-6,3) and(-2,0) respectively, which of its sides are congruent to each other? a. XZ and XY b. XY and YZ c. YZ and XZ d. none of the above

CORRECT Solution: a.To determine which of the three sides are congruent, find the length of each sides by using distance formula. XY=√[(-6)-2] 2 +(3-3) 2 YZ=√[(-2)-(-6)] 2 +(0-3) 2 XZ=√[(-2)-2] 2 +(0-3) 2 XY=√(-8) 2 +(0) 2 YZ=√(4) 2 +(-3) 2 XZ=√(-4) 2 +(-3) 2 XY=√64 YZ=√16+9 XZ=√16+9 XY= 8 YZ= 5 XZ= 5 b. Therefore, the sides of Isosceles Triangle XYZ that are congruent to each other are: YZ and XZ

WRONG Sorry, you did not get the correct answer! Go back and try again.

5. Find the perimeter of the triangle XYZ, given that its vertices X,Y and Z are ( 1,4), (2,0) and (-1,4) respectively. a. 2 b. 5 c. 7 √17 d. 17 √7

CORRECT Solution: a.To get the perimeter of Triangle XYZ, find the length of the three sides of triangle XYZ by distance formula. XY =√(1-2) 2 +(4-0) 2 YZ = √[2-(-1)] 2 +(0-4) 2 XZ = √[1-(-1)] 2 +(4-4) 2 XY =√(-1) 2 +(4) 2 YZ = √(3) 2 +(-4) 2 XZ = √(2) 2 +(0) 2 XY = √ YZ = √ XZ = √ 4 XY = √ 17 YZ = 5 XZ = 2 b. Therefore; the Perimeter of Triangle XYZ = XY + YZ + XZ = √ = 7 √ 17

WRONG Sorry, you did not get the correct answer! Go back and try again.

The End Hope you enjoy and learn from this. If you wish to do the excercises again, just click the icon Start again.Start again. Thank you!