As the ball revolves faster, the angle increases

Slides:



Advertisements
Similar presentations
CHAPTER-6 Force and Motion-II.
Advertisements

Physics 111: Mechanics Lecture 5
Circular Motion and Gravitation
Uniform Circular Motion
Centripetal Acceleration and Centripetal Force
Circular Motion; Gravitation
Dynamics of Circular Motion
Motion in a Plane Chapter 8. Centripetal Acceleration Centripetal Acceleration – acceleration that points towards the center of a circle. – Also called.
General Physics 1, Lec 8 By/ T.A. Eleyan 1 Lecture 8 Circular Motion & Relative Velocity.
Circular Motion and Other Applications of Newton’s Laws
CIRCULAR MOTION We will be looking at a special case of kinematics and dynamics of objects in uniform circular motion (constant speed) Cars on a circular.
Circular Motion Lecturer: Professor Stephen T. Thornton
5.2 Uniform Circular motion 5.3 Dynamic of Uniform Circular Motion
5.4 highway curves 5.5 Non-uniform circular motion 5.6 Drag Velocity
C H A P T E R 5 Dynamics of Uniform Circular Motion
T101Q7. A spring is compressed a distance of h = 9.80 cm from its relaxed position and a 2.00 kg block is put on top of it (Figure 3). What is the maximum.
Centripetal Acceleration 13 Examples with full solutions.
as the force required before you changed the crate’s orientation.
Circular Motion and Other Applications of Newton’s Laws
Using Newton’s Laws: Friction, Circular Motion, Drag Forces
Newton’s Laws of Motion
Circular Motion.
Uniform Circular Motion
Friction is a force that opposes the motion between two surfaces that are in contact  is a force that opposes the motion between two surfaces that are.
Physics. Session Particle Dynamics - 5 Session Objective 1.Circular motion 2.Angular variables 3.Unit vector along radius and tangent 4.Radial and tangential.
Copyright © 2009 Pearson Education, Inc. © 2009 Pearson Education, Inc. This work is protected by United States copyright laws and is provided solely for.
1/23 Quiz today over SHM and Reading Get a calculator an AP Formula Chart You will have 12 minutes FP = mgsin(Θ)
Chapter Opener. Caption: Newton’s laws are fundamental in physics
Dynamics II Motion in a Plane
Example 1: A 3-kg rock swings in a circle of radius 5 m
Centripetal Force and Acceleration
CIRCULAR MOTION.
Forces of Friction When an object is in motion on a surface or through a viscous medium, there will be a resistance to the motion This is due to the interactions.
1 Chapter (6) Circular Motion. 2 Consider an object moving at constant speed in a circle. The direction of motion is changing, so the velocity is changing.
CHAPTER 6 : CIRCULAR MOTION AND OTHER APPLICATIONS OF NEWTON’S LAWS
Motion, Forces and Energy Lecture 5: Circles and Resistance m FrFr FrFr m FrFr A particle moving with uniform speed v in a circular path of radius r experiences.
Lecture 10 Employ Newton’s Laws in 2D problems with circular motion 1.
 Extension of Circular Motion & Newton’s Laws Chapter 6 Mrs. Warren Kings High School.
Physics 203 – College Physics I Department of Physics – The Citadel Physics 203 College Physics I Fall 2012 S. A. Yost Chapter 5 Circular Motion, Universal.
6-4 Connected Object The several objects tied together motion Separate these objects draw free body diagram: (1)Isolate the object (2)Draw the all external.
Uniform Circular Motion Centripetal forces keep these children moving in a circular path.
Physics 207: Lecture 11, Pg 1 Lecture 11 l Goals:  Employ Newton’s Laws in 2D problems with circular motion  Relate Forces with acceleration Assignment:
Physics 207: Lecture 10, Pg 1 Lecture 10 l Goals:  Exploit Newton’s 3 rd Law in problems with friction  Employ Newton’s Laws in 2D problems with circular.
Copyright © 2009 Pearson Education, Inc. Chapter 5 Using Newton’s Laws: Friction, Circular Motion, Drag Forces.
Circular Motion and Gravitation
1) component of the gravity force parallel to the plane increased 2) coeff. of static friction decreased 3) normal force exerted by the board decreased.
Circular Motion r v F c, a c. Centripetal acceleration – acceleration of an object in circular motion. It is directed toward the center of the circular.
Uniform Circular Motion is the motion of an object traveling at a constant (uniform) speed on a circular path.
R. Field 2/5/2013 University of Florida PHY 2053Page 1 Circular Motion: Angular Variables The arc length s is related to the angle  (in radians = rad)
5.5 Non-uniform circular motion 5.6 Drag Velocity
PHY 151: Lecture 6B 6.3 Extending Particle in Uniform Circular Motion Model (Continued)
Chapter 5 Circular Motion © 2014 Pearson Education, Inc.
Centripetal Force Copyright Sautter 2003.
SACE Stage 2 Physics Circular Motion.
Newton’s Laws.
Chapter 6 Force and Motion II. Forces of Friction When an object is in motion on a surface or through a viscous medium, there will be a resistance to.
Centripetal Acceleration and Centripetal Force
Vertical Circular Motion
Circular Motion and Other Applications of Newton’s Laws
Aim: How do we explain centripetal motion?
Halliday/Resnick/Walker Fundamentals of Physics 8th edition
Vertical Circular Motion
5-2 Uniform Circular Motion—Kinematics
What do we want to do today?! Thursday:
Aim: How do we explain centripetal motion?
Pendulum A string is attached to mass m and swung in a horizontal circle of radius r. There is tension T in the string. The angle θ is measured from the.
Ch Help-Session.
Centripetal Force and Banked Curves Chapter 5 Lesson 2
Uniform Circular Motion
Presentation transcript:

As the ball revolves faster, the angle increases Example: The Conical Pendulum As the ball revolves faster, the angle increases If the radius is 0.02 m and the angle equal 30° What’s the speed for a given angle?

A worker drags(يجر) a crate along a rough, horizontal surface by pulling on a rope tied ربط) ) to the crate. the worker exerts a force of 300 N on the rope that is inclined 37° to the horizontal .If the mass of the crate is 60 kg , and the coefficient of kinetic friction is 0.3 , find the acceleration of the crate .

A 2-kg block is placed on top of a 5 – kg A 2-kg block is placed on top of a 5 – kg . A horizontal force of 40 N is applied to the 5- kg block.If the coefficient of kinetic friction between the 5-Kg and the surface is 0.2 , and assuming that the 2 –Kg block is in the verge of slipping , a): What is the acceleration of the system . What is the coefficient of static friction is

A 3kg block starts from rest at the top of 30º incline and slides a distance of 2m down the incline in 1.5s. Find (a) the acceleration of the block, (b) the coefficient of kinetic friction between the block and the plane, (c) the friction force acting on the block, (d) the speed of the block after it has slid 2m.

Given m = 3kg,     θ = 30o,    x =2m,     t = 1.5s             Xo=0 then x = 1/2at 2     2 = 1/2a (1.5)2        a = 1.78 m/s2       

       mg sin30 - f = ma        f = m (g sin30 -a) f = 9.37N            N - mg cos30 = 0        N = mg cos30         f = 9.37N       µk = f / N = 0.368 V2=v02+2a(x-x0) v2 = 0 + 2(1.78)(2) = 7.11 then        v = 2.67m/s

Problem: Forces are being applied to a box sitting on a surface with friction. Will the box move horizontally (along the surface)? F1=50N, F2=50N, Mass of the block 10kg, and µs=0.4. Find The Fn and Acceleration Hint: must be greater or equal to

Problem:  A 20 kg sled is being pulled across a horizontal surface at a constant velocity.  The pulling force has a magnitude of 80.0 N and is directed at an angle or 30.0° above the horizontal.  Determine the coefficient of kinetic friction.

Centripetal Force If there is a centripetal acceleration, then the net force must also be a centripetal force:

Tangential and Radial acceleration

Example: A car exhibits a constant acceleration of 0 Example: A car exhibits a constant acceleration of 0.300 m/s2 parallel to the roadway. The car passes over a rise in the roadway such that the top of the rise is shaped like a circle of radius 500 m. At the moment the car is at the top of the rise, its velocity vector is horizontal and has a magnitude of 6.00 m/s. What is the direction of the total acceleration vector for the car at this instant?

If the angle between

EX 3 A ball tied the end of string 0 EX 3 A ball tied the end of string 0.5 m in length swings in a vertical circle under the influence of gravity . When the string makes an angle θ= 20 degre with the vertical , the ball has a speed of 1.5 m/s . (a) Find the magnitude of the radial component of acceleration at this instant. (b) what is the magnitude of the tangential acceleration when θ= 20 degre. (c) find the magnitude and direction of the total acceleration a at θ= 20 degre.

NOTE

EX 1 :A Circular curve a road is designed for traffic moving at 60 km/hr without depending on the friction . If the radius of the curve is 80 m , what is the correct angle of the banking on the road . SOL Θ=19.136°

The moon revolves about earth in an orbit of radius and makes on revolution in 27.3 days .Find the acceleration of the moon toward the earth

Example (a) Calculate the centripetal force exert on a 1000 kg car that negotiates a 600 m radius curve at 20.0 m/s. (b) Assuming an unbanked curve, find the minimum static coefficient of friction between the tires and the road.

A flat (unbanked ) curve on a highway has a radius of 100 m A flat (unbanked ) curve on a highway has a radius of 100 m .if the coefficient of static –friction between the tries (اطار العجلة) and the road is 0.2 . What is the maximum speed with which the car will have in order to round the curve successfully

Problem: A particle moves in a circular path 0 Problem: A particle moves in a circular path 0.4m in radius with constant speed.  If the particle makes five revolution in each second of its motion, find (a) the speed of the particle and (b) its acceleration.

Since r=0.4m, t=0.4 s

Problem: A train slows down as it rounds a sharp horizontal turn, slowing from 90km/h to 50km/h in the 15s that it takes to round the bend.  The radius of the curve is 150m.  Compute the acceleration at the train.

Problem: I rotate a ball at an angle of 30o Problem: I rotate a ball at an angle of 30o.  What is the centripetal acceleration?  If the string is 1 meter long, how fast is it rotating?

Problem Driving in your car with a constant speed of 12 m/s, you encounter a bump in the road that has a circular cross section, as indicated in the Figure. If the radius of curvature of the bump is 35 m, find the apparent weight of a 67-kg person in your car as you pass over the top of the bump. N mg a=v2/r