Mechanics Lecture 3, Slide 1 Classical Mechanics Lecture 3 Today’s Concepts: a) Relative motion b) Centripetal acceleration.

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Presentation transcript:

Mechanics Lecture 3, Slide 1 Classical Mechanics Lecture 3 Today’s Concepts: a) Relative motion b) Centripetal acceleration

Mechanics Lecture 3, Slide 2 Prelecture 3, Question 1

Mechanics Lecture 3, Slide 3 v belt,ground = 2 m/s v dog,belt = 8 m/s A) 6 m/s B) 8 m/s C) 10 m/s CheckPoint A girl stands on a moving sidewalk that moves to the right at 2 m/s relative to the ground. A dog runs toward the girl in the opposite direction along the sidewalk at a speed of 8 m/s relative to the sidewalk. What is the speed of the dog relative to the ground?

Mechanics Lecture 3, Slide 4 v dog, ground = v dog, belt + v belt, ground = (  8 m/s) + (2 m/s) =  6 m/s +x+x v belt,ground = 2 m/s v dog,belt = 8 m/s What is the speed of the dog relative to the ground? A) 6 m/s B) 8 m/s C) 10 m/s

Mechanics Lecture 3, Slide 5 About 55% of you got this right – lets try it again. CheckPoint A girl stands on a moving sidewalk that moves to the right at 2 m/s relative to the ground. A dog runs toward the girl in the opposite direction along the sidewalk at a speed of 8 m/s relative to the sidewalk. What is the speed of the dog relative to the girl? v belt,ground = 2 m/s v dog,belt = 8 m/s A) 6 m/s B) 8 m/s C) 10 m/s

Mechanics Lecture 3, Slide 6 A) Because the girl is actually moving and the two vectors are opposite, so together they make 6 m/s B) Because the girl is not moving relative to the belt, and the dog is going 8 m/s relative to the belt, the dog is also moving 8 m/s relative to the girl.. C) The dog and girl are running towards each other so when you add the two velocities together it would be 8+2. What is the speed of the dog relative to the girl? v belt,ground = 2 m/s v dog,belt = 8 m/s A) 6 m/s B) 8 m/s C) 10 m/s A) Because the girl is actually moving and the two vectors are opposite, so together they make 6 m/s B) Because the girl is not moving relative to the belt, and the dog is going 8 m/s relative to the belt, the dog is also moving 8 m/s relative to the girl..

Mechanics Lecture 3, Slide 7 B) Because the girl is not moving relative to the belt, and the dog is going 8 m/s relative to the belt, the dog is also moving 8 m/s relative to the girl. Using the velocity formula: v dog, girl = v dog, belt + v belt, girl =  8 m/s + 0 m/s =  8 m/s What is the speed of the dog relative to the girl? v belt,ground = 2 m/s v dog,belt = 8 m/s A) 6 m/s B) 8 m/s C) 10 m/s

Mechanics Lecture 3, Slide 8 Tractor Demo (moving cardboard) Which direction should I point the toy bulldozer to get it across the cardboard fastest? A) To the left B) Straight across C) To the right A B C

Mechanics Lecture 3, Slide 9 Clicker Question Moving sidewalk 2 m/s 1 m/s 4 m A man starts to walk along the dotted line painted on a moving sidewalk toward a fire hydrant that is directly across from him. The width of the walkway is 4 m, and it is moving at 2 m/s relative to the fire- hydrant. If his walking speed is 1 m/s, how far away will he be from the hydrant when he reaches the other side? A)2 m B)4 m C)6 m D)8 m

Mechanics Lecture 3, Slide 10 Time to get across:  t = distance / speed = 4m / 1m/s = 4 s 1 m/s 4 m If the sidewalk wasn’t moving:

Mechanics Lecture 3, Slide 11 4 m 2 m/s Just the sidewalk:

Mechanics Lecture 3, Slide 12 1 m/s 4 m 2 m/s Combination of motions:

Mechanics Lecture 3, Slide 13 D = (speed of sidewalk) ∙ (time to get across) = (2 m/s) ∙ (4 s) = 8 m 1 m/s 4 m 2 m/s D

Mechanics Lecture 3, Slide 14 Three swimmers can swim equally fast relative to the water. They have a race to see who can swim across a river in the least time. Relative to the water, Beth swims perpendicular to the flow, Ann swims upstream at 30 degrees, and Carly swims downstream at 30 degrees. Who gets across the river first? A) Ann B) Beth C) Carly x y Ann Beth Carly Clicker Question

Mechanics Lecture 3, Slide 15 A B C V y,Beth = V o 30 o V y,Ann = V o cos(30 o ) V y,Carly = V o cos(30 o ) Time to get across = D / V y D Look at just water & swimmers x y

Mechanics Lecture 3, Slide 16 x y Clicker Question Three swimmers can swim equally fast relative to the water. They have a race to see who can swim across a river in the least time. Relative to the water, Beth swims perpendicular to the flow, Ann swims upstream at 30 degrees, and Carly swims downstream at 30 degrees. Who gets across the river second? A) Ann B) Carly C) Both same AnnCarly