EXAMPLE 1 Construct a probability distribution

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Presentation transcript:

EXAMPLE 1 Construct a probability distribution Let X be a random variable that represents the sum when two six-sided dice are rolled. Make a table and a histogram showing the probability distribution for X. SOLUTION The possible values of X are the integers from 2 to 12. The table shows how many outcomes of rolling two dice produce each value of X. Divide the number of outcomes for X by 36 to find P(X).

EXAMPLE 1 Construct a probability distribution

EXAMPLE 2 Interpret a probability distribution Use the probability distribution in Example 1 to answer each question. What is the most likely sum when rolling two six-sided dice? What is the probability that the sum of the two dice is at least 10? SOLUTION The most likely sum when rolling two six-sided dice is the value of X for which P(X) is greatest. This probability is greatest for X = 7. So, the most likely sum when rolling the two dice is 7.

EXAMPLE 2 Interpret a probability distribution The probability that the sum of the two dice is at least 10 is: P(X > 10 ) = P(X = 10) + P(X = 11) + P(X = 12) = 3 36 + 2 1 = 6 36 = 1 6 0.167

GUIDED PRACTICE for Examples 1 and 2 A tetrahedral die has four sides numbered 1 through 4. Let X be a random variable that represents the sum when two such dice are rolled. Make a table and a histogram showing the probability distribution for X.

GUIDED PRACTICE for Examples 1 and 2 A tetrahedral die has four sides numbered 1 through 4. Let X be a random variable that represents the sum when two such dice are rolled. What is the most likely sum when rolling the two dice? What is the probability that the sum of the two dice is at most 3? SOLUTION The most likely sum when rolling two four-sided dice is the value of X for which P(X) is greatest. This probability is greatest for X = 5. So, the most likely sum when rolling the two dice is 5.

GUIDED PRACTICE for Examples 1 and 2 P(X ≤ 3 ) = P(X = 2) + P(X =3) = 1 16 + 8 = 3 16 sum of 5; 3 16 ANSWER