HOW DOES THE LATITUDE OF

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Presentation transcript:

HOW DOES THE LATITUDE OF A LOCATION IMPACT THE INSOLATION THAT IT RECEIVES?

LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN N Equator Center of Earth S

LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN North Pole Latitude = 90°N Lat. = 90° Equator South Pole Latitude = 90°S

LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Z = 90° North Pole Latitude = 90°N Lat. = 90° Equator South Pole Latitude = 90°S Z = 90°

LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Southampton, UK Latitude = 52°N Equator Punta Arenas, Chile Latitude = 52°S

LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Southampton, UK Latitude = 52°N Z = 52° Equator Lat = 52° Punta Arenas, Chile Latitude = 52°S

LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Z = 52° Equator Lat = 52° Geometry:- “Transversal Postulate.” Angle of Latitude = Noontime Zenith Angle

LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Gainesville Latitude = 29.5°N Z = 29.5° Lat = 29.5° Equator Durban, SA. Latitude = 29.5°S

LATITUDE AND ZENITH ANGLE AT NOON ON MARCH AND SEPTEMBER 21. SUN Quito, Ecuador Latitude = 0° Equator Lat = 0° Z = 0°

CAN WE QUANTIFY THIS EFFECT OF ZENITH ANGLE AT NOON AND LATITUDE? SUN N Imaginary solar collector of 1 m2 S

Ten parallel rays representing the solar constant (345Wm-2) SUN

SUN North and South Poles (90°) Z = 90°: 0/10 Rays intercepted = 0/10*345 = 0Wm-2

SUN Southampton and Punta Arenas (52°) Z = 52°: 6/10 Rays intercepted = 6/10*345 = 207 Wm-2

SUN Gainesville and Durban (29.5°) Z = 29.5°: 9/10 Rays intercepted = 9/10*345 = 310.5 Wm-2

Quito (0°) SUN Z = 0°: 10/10 Rays intercepted = 10/10*345 = 345 Wm-2

SUN Cos (90) = 0 0 * 345 = 0 North and South Poles (90°) Z = 90°: 0/10 Rays intercepted = 0/10*345 = 0Wm-2

SUN Southampton and Punta Arenas (52°) Cos (52) = 0.62 0.62 * 345 = 210 Z = 52°: 6/10 Rays intercepted = 6/10*345 = 207 Wm-2

SUN Gainesville and Durban (29.5°) Cos (29.5) = 0.87 0.87 * 345 = 310 Z = 29.5°: 9/10 Rays intercepted = 9/10*345 = 310.5 Wm-2

Quito (0°) SUN Cos (0) = 1.00 1.00 * 345 = 345 Z = 0°: 10/10 Rays intercepted = 10/10*345 = 345 Wm-2

ANSWER Q = Cos(Z) * S Where Q = Quantity of insolation (Wm-2) Z = Zenith angle (noontime value controlled by latitude) S = Solar constant (345 Wm-2)