Reflexive property. <1 <2 <3 <4 A B C D Given:AB = AD BC = DC Prove:∆ABC = ∆ADC StatementReason AB = ADgiven BC = DCgiven.

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Presentation transcript:

reflexive property

<1 <2 <3 <4 A B C D Given:AB = AD BC = DC Prove:∆ABC = ∆ADC StatementReason AB = ADgiven BC = DCgiven

<1 <2 <3 <4 A B C D Given:AB = AD BC = DC Prove:∆ABC = ∆ADC StatementReason AB = ADgiven BC = DCgiven AC = ACreflexive property ∆ABC = ∆ADCSSS

<1 <2 <3 <4 A B C D Given:AC bisects <A AC bisects <C Prove:∆ABC = ∆ADC StatementReason AC bisects <A given AC bisects <C given

<1 <2 <3 <4 A B C D Given:AC bisects <A AC bisects <C Prove:∆ABC = ∆ADC StatementReason AC bisects <A given AC bisects <C given <1 = <2definition of an angle bisector <3 = <4definition of an angle bisector AC = ACreflexive property ∆ABC = ∆ADCASA

<1 <2 <3 <4 A B C D Given:AB = AD AC bisects <A Prove:∆ABC = ∆ADC StatementReason AB = AD given AC bisects <A given

<1 <2 <3 <4 A B C D Given:AB = AD AC bisects <A Prove:∆ABC = ∆ADC StatementReason AB = AD given AC bisects <A given <1 = <2definition of an angle bisector AC = ACreflexive property ∆ABC = ∆ADCSAS

A B C D <1<2 <3<4 Given:D is the midpoint of AC AB = CB Prove:∆ABD = ∆CBD StatementReason D is the midpoint of ACgiven AB = CBgiven

A B C D <1<2 <3<4 Given:D is the midpoint of AC AB = CB Prove:∆ABD = ∆CBD StatementReason D is the midpoint of ACgiven AB = CBgiven AD = CDdefinition of a midpoint BD = BDreflexive property ∆ABD = ∆CBD SSS

A B C D <1<2 <3<4 Given:BD bisects <ABC AB = CB Prove:∆ABD = ∆CBD StatementReason BD bisects <ABC given AB = CBgiven

A B C D <1<2 <3<4 Given:BD bisects <ABC AB = CB Prove:∆ABD = ∆CBD StatementReason BD bisects <ABC given AB = CBgiven <1 = <2definition of an angle bisector BD = BDreflexive property ∆ABD = ∆CBD SAS

A B C D <1<2 <3<4 Given:<4 = 90° D is the midpoint of AC Prove:∆ABD = ∆CBD StatementReason <4 = 90° given D is the midpoint of ACgiven

A B C D <1<2 <3<4 Given:<4 = 90° D is the midpoint of AC Prove:∆ABD = ∆CBD StatementReason <4 = 90° given D is the midpoint of ACgiven <3 + <4 = 180linear pair postulate < = 180substitution <3 = 90subtraction <3 = <4substitution AD = CDdefinition of a midpoint BD = BDreflexive property ∆ABD = ∆CBD SAS