A piston moves a distance of 12cm from top to bottom (starts at top) One complete piston movement takes 0.04 seconds. Piston Problem The equation for the.

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Presentation transcript:

A piston moves a distance of 12cm from top to bottom (starts at top) One complete piston movement takes 0.04 seconds. Piston Problem The equation for the distance d = 6Cos(50πt) where t = time in seconds And d is the vertical distance from point ‘P’ (cm) During the first cycle when is the piston 1cm above point ‘P’? (Where point ‘P’ is the central position of the vertical movement) Distance ‘d’ Point P Method A Method B Notes Review

A piston moves a distance of 12cm from top to bottom (starts at top) Piston Problem Method A One complete piston movement takes 0.04 seconds. The equation for the distance d = 6Cos(50πt) where t = time in seconds And d is the vertical distance from point ‘P’ (cm) During the first cycle when is the piston 1cm above point ‘P’? (Where point ‘P’ is the central position of the vertical movement) Distance ‘d’ Point P Solve 1 = 6Cos(50πt) = Cos(A) A = t = sec (5dp) A = Cos Let A = 50πt Solve 1 = 6Cos(A) And t = A ÷ 50π t = ÷ 50π Home

A piston moves a distance of 12cm from top to bottom (starts at top) Piston Problem Method B One complete piston movement takes 0.04 seconds. The equation for the distance d = 6Cos(50πt) where t = time in seconds And d is the vertical distance from point ‘P’ (cm) During the first cycle when is the piston 1cm above point ‘P’? (Where point ‘P’ is the central position of the vertical movement) Distance ‘d’ Point P Solve 1 = 6Cos(50πt) = Cos(50πt) 50πt = t = sec (5dp) (50πt) = Cos Home

A piston moves a distance of 12cm from top to bottom (starts at top) Piston Problem Notes One complete piston movement takes 0.04 seconds. The equation for the distance d = 6Cos(50πt) where t = time in seconds And d is the vertical distance from point ‘P’ (cm) During the first cycle when is the piston 1cm above point ‘P’? (Where point ‘P’ is the central position of the vertical movement) Distance ‘d’ Point P Solve 1 = 6Cos(50πt) = Cos(A) A = t = sec (5dp) A = Cos Let A = 50πt Solve 1 = 6Cos(A) And t = A ÷ 50π t = ÷ 50π Home

Piston Problem: Review The equation for the distance d = 6Cos(50πt) where t = time in seconds And d is the vertical distance from point ‘P’ (cm) During the first cycle when is the piston 1cm above point ‘P’? Solve 1 = 6Cos(50πt) = Cos(A) A = t = sec (5dp) A = Cos Let A = 50πt Solve 1 = 6Cos(A) And t = A ÷ 50π t = ÷ 50π Solve 1 = 6Cos(50πt) Rearrange to give ? = Cos(A) Simplify the equation 1 = 6Cos(A) Solve ? = Cos(A) Use the ‘A’ solution to find t = ? Home