 First, Lets Visualize parallel lines  What do they have in common?  Slope!  What is different?  x- and y-ints!

 The same slope! Slope = 1

 Step 1: Find the Slope (m)  Step 2: write another equation with that same slope.  Step 3: Bob is your uncle! You’ve done it.  Now You Try!

 Y = 7x – 12 Stumped? There are tons!! Check it out. Y = 7x + 4 Y = 7x + 1/9 Y = 7x + 2 Y = 7x - 2 Y = 7x Y = 7x – 1.44 Y = 7x

 y = 5x + 3  Now since it’s through a point, then it will have a specific y-int (b). We know m=5, so lets solve for b.  y = 5x + b  -1 = 5(6) + b  -1 = 30 + b  -31 = b  So our equation would be: Y = 5x - 30

 x = 5  This line is horizontal, a horizontal line going though point (3,-2) will be parallel.  What would that line be?  x = 3!

 First, Lets Visualize perpendicular lines  This isn’t so straight forward.  Looking at the blue line, what is it’s slope? 22  How about the red line?  -1/2

 It is a number you multiply by that gets you to 1. For example  5.  What times 5 will equal 1?  1/5  Don’t believe me? Try it  5(1/5) = 1

 If Slope = m, Then the opposite reciprocal would be…

 So, to find a perpendicular line to another line, the slope is opposite and reciprocal.  What is the Opposite Reciprocal of 4?  -1/4  How about 1/3?  -3  How about -1/8? 88

 Step 1: Find the Slope (m)  Step 2: Find the opposite reciprocal = - 1/m  Step 3: Bob is your uncle! You’ve done it.  Now You Try!

 Y = 7x – 12 Stumped? There are tons!! Check it out. Y = (-1/7)x + 4 Y = (-1/7)x + 1/3 Y = (-1/7)x + 5 Y = (-1/7)x - 8 Y = (-1/7)x Y = (-1/7)x – 1.44 Y = (-1/7)x + 10,000

 y = 5x + 3  opposite reciprocal = -1/m  -1/5, Now lets find b.  y = (-1/5)x + b  -2 = (-1/5)(5) + b  -2 = -1 + b  -1 = b  So our perpendicular equation would be: Y = (-1/5)x - 1