1 3.4 Basic Propagation Mechanisms & Transmission Impairments (1) Reflection: propagating wave impinges on object with size >> examples include ground, buildings, walls (2) Diffraction: transmission path obstructed by objects with edges 2 nd ry waves are present throughout space (even behind object) gives rise to bending around obstacle (NLOS transmission path) (3) Scattering propagating wave impinges on object with size < number of obstacles per unit volume is large (dense) examples include rough surfaces, foliage, street signs, lamp posts
2 Models are used to predict received power or path loss (reciprocal) based on refraction, reflection, scattering Large Scale Models Fading Models at high frequencies diffraction & reflections depend on geometry of objects EM wave’s, amplitude, phase, & polarization at point of intersection
3 3.5 Reflection: EM wave in 1 st medium impinges on 2 nd medium part of the wave is transmitted part of the wave is reflected (1) plane-wave incident on a perfect dielectric (non-conductor) part of energy is transmitted (refracted) into 2 nd medium part of energy is transmitted (reflected) back into 1 st medium assumes no loss of energy from absorption (not practically) (2) plane-wave incident on a perfect conductor all energy is reflected back into the medium assumes no loss of energy from absorption (not practically)
4 (3) = Fersnel reflection coefficient relates Electric Field intensity of reflected & refracted waves to incident wave as a function of: material properties, polarization of wave angle of incidence signal frequency boundary between dielectrics (reflecting surface) reflected wave refracted wave incident wave
5 (4) Polarization: EM waves are generally polarized instantaneous electric field components are in orthogonal directions in space represented as either: (i) sum of 2 spatially orthogonal components (e.g. vertical & horizontal) (ii) left-handed or right handed circularly polarized components reflected fields from a reflecting surface can be computed using superposition for any arbitrary polarization E || EE
Reflection from Dielectrics assume no loss of energy from absorption EM wave with E-field incident at i with boundary between 2 dielectric media some energy is reflected into 1 st media at r remaining energy is refracted into 2 nd media at t reflections vary with the polarization of the E-field plane of incidence reflecting surface= boundary between dielectrics ii rr tt plane of incidence = plane containing incident, reflected, & refracted rays
7 Two distinct cases are used to study arbitrary directions of polarization (1) Vertical Polarization: (E vi ) E-field polarization is parallel to the plane of incidence normal component to reflecting surface (2) Horizontal Polarization: (E hi ) E-field polarization is perpendicular to the plane of incidence parallel component to reflecting surface plane of incidence ii rr tt E vi E hi boundary between dielectrics (reflecting surface)
8 E i & H i = Incident electric and magnetic fields E r & H r = Reflected electric and magnetic fields E t = Transmitted (penetrating) electric field HiHi HrHr EiEi ErEr ii rr tt 1, 1, 1 2, 2, 2 EtEt Vertical Polarization: E-field in the plane of incidence HiHi HrHr EiEi ErEr ii rr tt 1, 1, 1 2, 2, 2 EtEt Horizontal Polarization: E-field normal to plane of incidence
9 (1) EM Parameters of Materials = permittivity (dielectric constant): measure of a materials ability to resist current flow = permeability: ratio of magnetic induction to magnetic field intensity = conductance: ability of a material to conduct electricity, measured in Ω -1 dielectric constant for perfect dielectric (e.g. perfect reflector of lossless material) given by 0 = 8.85 F/m
10 often permittivity of a material, is related to relative permittivity r = 0 r lossy dielectric materials will absorb power permittivity described with complex dielectric constant (3.18) where ’ = (3.17) = 0 r -j ’ highly conductive materials r & are generally insensitive to operating frequency 0 and r are generally constant may be sensitive to operating frequency
11 Material rr /r0/r0 f (Hz) Poor Ground Typical Ground Good Ground Sea Water Fresh Water Brick 1094109 Limestone 1094109 Glass, Corning Glass, Corning Glass, Corning
12 because of superposition – only 2 orthogonal polarizations need be considered to solve general reflection problem Maxwell’s Equation boundary conditions used to derive ( ) Fresnel reflection coefficients for E-field polarization at reflecting surface boundary || represents coefficient for || E-field polarization represents coefficient for E-field polarization (2) Reflections, Polarized Components & Fresnel Reflection Coefficients
13 Fersnel reflection coefficients given by (i) E-field in plane of incidence (vertical polarization) || = (3.19) (ii) E-field not in plane of incidence (horizontal polarization) = (3.20) i = intrinsic impedance of the i th medium ratio of electric field to magnetic field for uniform plane wave in i th medium given by i =
14 velocity of an EM wave given by boundary conditions at surface of incidence obey Snell’s Law (3.21) i = r (3.22) E r = E i (3.23a) E t = (1 + )E i (3.23b) is either || or depending on polarization | | 1 for a perfect conductor, wave is fully reflected | | 0 for a lossy material, wave is fully refracted
15 radio wave propagating in free space (1 st medium is free space) 1 = 2 || = (3.24) = (3.25) Simplification of reflection coefficients for vertical and horizontal polarization assuming: Elliptically Polarized Waves have both vertical & horizontal components waves can be depolarized (broken down) into vertical & horizontal E-field components superposition can be used to determine transmitted & reflected waves
16 (3) General Case of reflection or transmission horizontal & vertical axes of spatial coordinates may not coincide with || & axes of propagating waves for wave propagating out of the page define angle measured counter clock-wise from horizontal axes spatial horizontal axis spatial vertical axis || orthogonal components of propagating wave
17 vertical & horizontal polarized components components perpendicular & parallel to plane of incidence E i H, E i V E d H, E d V E d H, E d V = depolarized field components along the horizontal & vertical axes E i H, E i V = horizontal & vertical polarized components of incident wave relationship of vertical & horizontal field components at the dielectric boundary E d H, E d V E i H, E i V = Time Varying Components of E-field (3.26) - E-field components may be represented by phasors
18 for case of reflection: D = D || || = || for case of refraction (transmission): D = 1+ D || || = 1+ || R =, = angle between two sets of axes DC =DC = R = transformation matrix that maps E-field components D C = depolarization matrix
| || | r =12 r =4 angle of incidence ( i ) Brewster Angle ( B ) for r =12 vertical polarization (E-field in plane of incidence) for i < B : a larger dielectric constant smaller || & smaller E r for i > B : a larger dielectric constant larger || & larger E r Plot of Reflection Coefficients for Parallel Polarization for r = 12, 4
20 r =12 r =4 |||| angle of incidence ( i ) horizontal polarization (E-field not in plane of incidence) for given i : larger dielectric constant larger and larger E r Plot of Reflection Coefficients for Perpendicular Polarization for r = 12, 4
21 e.g. let medium 1 = free space & medium 2 = dielectric if i 0 o (wave is parallel to ground) then independent of r, coefficients | | 1 and | || | 1 || = = thus, if incident wave grazes the earth ground may be modeled as a perfect reflector with | | = 1 regardless of polarization or ground dielectric properties horizontal polarization results in 180 phase shift
Brewster Angle = B Brewster angle only occurs for vertical (parallel) polarization angle at which no reflection occurs in medium of origin occurs when incident angle i is such that || = 0 i = B if 1 st medium = free space & 2 nd medium has relative permittivity r then (3.27) can be expressed as sin( B ) = (3.28) sin( B ) = (3.27) B satisfies
23 e.g. 1 st medium = free space Let r = 4 sin( B ) = = 0.44 B = sin -1 (0.44) = 26.6 o Let r = 15 sin( B ) = = 0.25 B = sin -1 (0.25) = 14.5 o
Ground Reflection – 2 Ray Model Free Space Propagation model is inaccurate for most mobile RF channels 2 Ray Ground Reflection model considers both LOS path & ground reflected path based on geometric optics reasonably accurate for predicting large scale signal strength for distances of several km useful for - mobile RF systems which use tall towers (> 50m) - LOS microcell channels in urban environments Assume maximum LOS distances d 10km earth is flat
25 Let E 0 = free space E-field (V/m) at distance d 0 Propagating Free Space E-field at distance d > d 0 is given by E(d,t) =(3.33) E-field’s envelope at distance d from transmitter given by |E(d,t)| = E 0 d 0 /d (1) Determine Total Received E-field (in V/m) E TOT E LOS EiEi E r = E g ii 00 d E TOT is combination of E LOS & E g E LOS = E-field of LOS component E g = E-field of ground reflected component θ i = θ r
26 d’ d” E LOS EiEi EgEg ii 00 d htht h r E-field for LOS and reflected wave relative to E 0 given by: and E TOT = E LOS + E g E LOS (d’,t) =(3.34) E g (d”,t) =(3.35) assumes LOS & reflected waves arrive at the receiver with - d’ = distance of LOS wave - d” = distance of reflected wave
27 From laws of reflection in dielectrics (section 3.5.1) i = 0 (3.36) E g = E i (3.37a) E t = (1+ ) E i (3.37b) = reflection coefficient for ground E g d’ d” E LOS EiEi ii 00 EtEt
28 resultant E-field is vector sum of E LOS and E g total E-field Envelope is given by |E TOT | = |E LOS + E g | (3.38) total electric field given by (3.39)E TOT (d,t) = Assume i. perfect horizontal E-field Polarization ii. perfect ground reflection iii. small i (grazing incidence) ≈ -1 & E t ≈ 0 reflected wave & incident wave have equal magnitude reflected wave is 180 o out of phase with incident wave transmitted wave ≈ 0
29 path difference = d” – d’ determined from method of images = (3-40) if d >> h r + h t Taylor series approximations yields (from 3-40) (3-41) (2) Compute Phase Difference & Delay Between Two Components E LOS d d’ d” ii 00 h t h r h h h t +h r EiEi EgEg
30 once is known we can compute phase difference = = (3-42) time delay d = (3-43) As d becomes large = d”-d’ becomes small amplitudes of E LOS & E g are nearly identical & differ only in phase (3.44) if Δ = /n = 2π/n 0 π 2π Δ
31 (3) Evaluate E-field when reflected path arrives at receiver (3.45)E TOT (d,t)| t=d”/c = t = d”/creflected path arrives at receiver at = =
32 (3.46) = |E TOT (d)|= = =(3.47) (3.48) E TOT Use phasor diagram to find resultant E-field from combined direct & ground reflected rays: (4) Determine exact E-field for 2-ray ground model at distance d
33 As d increases E TOT (d) decreases in oscillatory manner local maxima 6dB > free space value local minima ≈ - dB (cancellation) once d is large enough θ Δ < π & E TOT (d) falls off asymtotically with increasing d m f c = 3GHz f c = 7GHz f c = 11GHz Propagation Loss h t = h r = 1, G t = G r = 0dB
34 if d satisfies 3.50 total E-field can be approximated as: k is a constant related to E 0 h t,h r, and (3.49) d > (3.50)this implies For phase difference, < 0.6 radians (34 o ) sin(0.5 ) |E TOT (d)| e.g. at 900MHz if < 0.03m total E-field decays with d 2 (3.51) E TOT (d) V/m
35 Received Power at d is related to square of E-field by 3.2, 3.15, & 3.51 P r (d) =(3.52b) P r (d) =(3.52a) received power falls off at 40dB/decade receive power & path loss become independent of frequency if d >>
36 Path Loss for 2-ray model with antenna gains is expressed as: for short Tx-Rx distances use (3.39) to compute total E field evaluate (3.42) for = (180 o ) d = 4h t h r / is where the ground appears in 1 st Fresnel Zone between Tx & Rx - 1 st Fresnel distance zone is useful parameter in microcell path loss models PL(dB) = 40log d - (10logG t + 10logG r + 20log h t + 20 log h r )(3.53) PL = 3.50 must hold