CHAPTER 8: Sampling Distributions

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CHAPTER 8: Sampling Distributions to accompany Introduction to Business Statistics fourth edition, by Ronald M. Weiers Presentation by Priscilla Chaffe-Stengel Donald N. Stengel © 2002 The Wadsworth Group

Chapter 8 - Learning Objectives Determine the sampling distributions of: Means Proportions Explain the Central Limit Theorem

Sampling Distribution of the Mean When the population is normally distributed Shape: Regardless of sample size, the distribution of sample means will be normally distributed. Center: The mean of the distribution of sample means is the mean of the population. Sample size does not affect the center of the distribution. Spread: The standard deviation of the distribution of sample means, or the standard error, is . n x s = © 2002 The Wadsworth Group

Standardizing a Sample Mean on a Normal Curve The standardized z-score is how far above or below the sample mean is compared to the population mean in units of standard error. “How far above or below” = sample mean minus µ “In units of standard error” = divide by Standardized sample mean n s n x z s m = - – error standard mean sample © 2002 The Wadsworth Group

Central Limit Theorem According to the Central Limit Theorem (CLT), the larger the sample size, the more normal the distribution of sample means becomes. The CLT is central to the concept of statistical inference because it permits us to draw conclusions about the population based strictly on sample data without having knowledge about the distribution of the underlying population. © 2002 The Wadsworth Group

Sampling Distribution of the Mean When the population is not normally distributed Shape: When the sample size taken from such a population is sufficiently large, the distribution of its sample means will be approximately normally distributed regardless of the shape of the underlying population those samples are taken from. According to the Central Limit Theorem, the larger the sample size, the more normal the distribution of sample means becomes. © 2002 The Wadsworth Group

Sampling Distribution of the Mean When the population is not normally distributed Center: The mean of the distribution of sample means is the mean of the population, µ. Sample size does not affect the center of the distribution. Spread: The standard deviation of the distribution of sample means, or the standard error, is . n x s = © 2002 The Wadsworth Group

Example: Standardizing a Mean Problem 8.45: When a production machine is properly calibrated, it requires an average of 25 seconds per unit produced, with a standard deviation of 3 seconds. For a simple random sample of n = 36 units, the sample mean is found to be 26.2 seconds per unit. When the machine is properly calibrated, what is the probability that the mean for a simple random sample of this size will be at least 26.2 seconds? Standardized sample mean: © 2002 The Wadsworth Group

Sampling Distribution of the Proportion When the sample statistic is generated by a count not a measurement, the proportion of successes in a sample of n trials is p, where Shape: Whenever both n p and n(1 – p) are greater than or equal to 5, the distribution of sample proportions will be approximately normally distributed. © 2002 The Wadsworth Group

Sampling Distribution of the Proportion When the sample proportion of successes in a sample of n trials is p, Center: The center of the distribution of sample proportions is the center of the population, p. Spread: The standard deviation of the distribution of sample proportions, or the standard error, is s p = × ( 1 – ) n . © 2002 The Wadsworth Group

Standardizing a Sample Proportion on a Normal Curve The standardized z-score is how far above or below the sample proportion is compared to the population proportion in units of standard error. “How far above or below” = sample p – p “In units of standard error” = divide by Standardized sample proportion n p ) – 1 ( × = s n p z ) – 1 ( error standard proportion sample × = - © 2002 The Wadsworth Group

Example: Standardizing a Proportion Problem 8.40: The campaign manager for a political candidate claims that 55% of registered voters favor the candidate over her strongest opponent. Assuming that this claim is true, what is the probability that in a simple random sample of 300 voters, at least 60% would favor the candidate over her strongest opponent? p = 0.55, p = 0.60, n = 300 Standardized sample proportion: © 2002 The Wadsworth Group