Copyright © 2007 Pearson Education, Inc. Slide 6-2 Chapter 6: Analytic Geometry 6.1Circles and Parabolas 6.2Ellipses and Hyperbolas 6.3Summary of the Conic Sections 6.4Parametric Equations

Copyright © 2007 Pearson Education, Inc. Slide Circles and Parabolas Conic Sections –Parabolas, circles, ellipses, hyperbolas

Copyright © 2007 Pearson Education, Inc. Slide 6-4 A circle with center (h, k) and radius r has length to some point (x, y) on the circle. Squaring both sides yields the center-radius form of the equation of a circle. 6.1 Circles A circle is a set of points in a plane that are equidistant from a fixed point. The distance is called the radius of the circle, and the fixed point is called the center.

Copyright © 2007 Pearson Education, Inc. Slide Finding the Equation of a Circle ExampleFind the center-radius form of the equation of a circle with radius 6 and center (–3, 4). Graph the circle and give the domain and range of the relation. SolutionSubstitute h = –3, k = 4, and r = 6 into the equation of a circle.

Copyright © 2007 Pearson Education, Inc. Slide Graphing Circles with the Graphing Calculator Example Use the graphing calculator to graph the circle in a square viewing window. Solution

Copyright © 2007 Pearson Education, Inc. Slide Graphing Circles with the Graphing Calculator TECHNOLOGY NOTES: –Graphs in a nondecimalwindow may not be connected –Graphs in a rectangular (non-square) window look like an ellipse

Copyright © 2007 Pearson Education, Inc. Slide Finding the Center and Radius of a Circle ExampleFind the center and radius of the circle with equation SolutionOur goal is to obtain an equivalent equation of the form We complete the square in both x and y. The circle has center (3, –2) with radius 3.

Copyright © 2007 Pearson Education, Inc. Slide Equations and Graphs of Parabolas For example, let the directrix be the line y = –c and the focus be the point F with coordinates (0, c). A parabola is a set of points in a plane equidistant from a fixed point and a fixed line. The fixed point is called the focus, and the fixed line, the directrix.

Copyright © 2007 Pearson Education, Inc. Slide Equations and Graphs of Parabolas To get the equation of the set of points that are the same distance from the line y = –c and the point (0, c), choose a point P(x, y) on the parabola. The distance from the focus, F, to P, and the point on the directrix, D, to P, must have the same length.

Copyright © 2007 Pearson Education, Inc. Slide Parabola with a Vertical Axis The focal chord through the focus and perpendicular to the axis of symmetry of a parabola has length |4c|. –Let y = c and solve for x. The endpoints of the chord are (  x, c), so the length is |4c|. The parabola with focus (0, c) and directrix y = –c has equation x 2 = 4cy. The parabola has vertical axis x = 0, opens upward if c > 0, and opens downward if c < 0.

Copyright © 2007 Pearson Education, Inc. Slide Parabola with a Horizontal Axis Note: a parabola with a horizontal axis is not a function. The graph can be obtained using a graphing calculator by solving y 2 = 4cx for y: Let and graph each half of the parabola. The parabola with focus (c, 0) and directrix x = –c has equation y 2 = 4cx. The parabola has horizontal axis y = 0, opens to the right if c > 0, and to the left if c < 0.

Copyright © 2007 Pearson Education, Inc. Slide Determining Information about Parabolas from Equations ExampleFind the focus, directrix, vertex, and axis of each parabola. (a) Solution (a) Since the x-term is squared, the parabola is vertical, with focus at (0, c) = (0, 2) and directrix y = –2. The vertex is (0, 0), and the axis is the y-axis.

Copyright © 2007 Pearson Education, Inc. Slide Determining Information about Parabolas from Equations (b) The parabola is horizontal, with focus (–7, 0), directrix x = 7, vertex (0, 0), and x-axis as axis of the parabola. Since c is negative, the graph opens to the left.

Copyright © 2007 Pearson Education, Inc. Slide Writing Equations of Parabolas ExampleWrite an equation for the parabola with vertex (1, 3) and focus (–1, 3). SolutionFocus lies left of the vertex implies the parabola has -a horizontal axis, and -opens to the left. Distance between vertex and focus is 1–(–1) = 2, so c = –2.

Copyright © 2007 Pearson Education, Inc. Slide An Application of Parabolas ExampleSignals coming in parallel to the axis of a parabolic reflector are reflected to the focus, thus concentrating the signal. The Parkes radio telescope has a parabolic dish shape with diameter 210 feet and depth 32 feet.

Copyright © 2007 Pearson Education, Inc. Slide An Application of Parabolas (a)Determine the equation describing the cross section. (b)The receiver must be placed at the focus of the parabola. How far from the vertex of the parabolic dish should the receiver be placed? Solution (a)The parabola will have the form y = ax 2 (vertex at the origin) and pass through the point

Copyright © 2007 Pearson Education, Inc. Slide An Application of Parabolas (b)Since The receiver should be placed at (0, 86.1), or 86.1 feet above the vertex.