Acids and Bases 5 Boon Chemistry January 24 & 25, 2013
Catalyst Think back to the investigations you completed this week. When a person takes Tums (or another antacid) what happens to the pH in their stomach? Why? Objectives I can demonstrate my knowledge of acid/base chemistry on the Unit 7 exam. Objectives I can demonstrate my knowledge of acid/base chemistry on the Unit 7 exam. Agenda Catalyst and Homework Review Unit 7 Exam Flashcards: Thermochemistry Agenda Catalyst and Homework Review Unit 7 Exam Flashcards: Thermochemistry Take out your homework please.
Exit Slip: Answers Standard IE 1e/5d What is the [H 3 O + ] in a M solution of NaOH (a strong base)? (a) 2.5 x M(c) 4.0 x M (b) 2.5 x M(d) 1.0 x M Why? 1.0 x = [H 3 O + ] (4.0 x ) Solve by dividing. As the [H 3 O + ] of a solution increases, the value of (a) log [H 3 O + ] increases.(c) the solution’s pH decreases. (b) –log[H 3 O + ] decreases.(d) all of the above Why? Test each answer. They are all true. What is the [OH - ] in a sample of lime juice with a pH of 2.0? (a) 1.0 x M(c) 1.0 x M (b) 1.0 x M(d) 1.0 x M Why? Read carefully. If pH is 2, then pOH is 12. This corresponds to 1.0 x M
Exit Slip answers continued (4) If the pH of a solution is increased from 2.0 to 4.0, the [H 3 O + ] concentration (a) decreases by a factor of 2. (b) decreases by a factor of 100. (c) increases by a factor of 3. (d) increases by a factor of Why? As pH goes up, [H 3 O + ] goes down. Each time you move one space on the pH scale you are changing the [H 3 O + ] by a factor of 10. Moving 2 spaces is 10x10=100. (5) What is the pH of household ammonia in which the [H 3 O + ] is 1.0 x M? (a) 2(c) 10 (b) 7(d) 12 Why? corresponds to pH=12. pH = -log[H 3 O + ]
Homework Review page , [H3O+] = 5.0 x M pH = -log[H3O+] pH = -log[5.0 x ] pH = [H3O+] = 0.2 M pH = -log[H3O+] pH = -log[2.0 x ] pH = [OH-] = 2.0 x pOH = -log[OH-] pOH = -log[2.0 x ] pOH = 2.7pOH + pH = 14; pH = [OH-] = 0.35 M pOH = -log[0.35]pOH = 0.45 pOH + pH = 14 pH = 13.55
Homework Review page , pH = 3.3 [H3O+] = 10 -pH [H3O+] = [H3O+] = 5.0 x pH = 11.7; pOH = = 2.3 [OH-] = 10 -pOH = = 5.0 x pH = 8.1; pOH = = 5.9 [H3O+] = = 7.9 x [OH-] = = 1.3 x pH = 7.67; pOH = = 6.33 [OH-] = = 4.7 x This is outside the normal range, the patient should be concerned.
Acid/Base Exam Expectations/Instructions: Work independently and silently. Write on your test. Be sure to answer every question. There are multiple choice and short answer. The Tools: Use your pH foldable worksheet. Use your own calculator. If you finish early: Turn in your test and all your pH worksheets, handouts, etc. Begin the flashcard assignment for Unit 8.
Thermochemistry Flashcards Front of card: Vocabulary word Picture/diagram Back of card: definition Sentence using the word Resources: Textbook Glossary Words are also posted on the wall. Words Endothermic Exothermic Melting point Boiling point Freezing point Condensation Fusion vaporization Sublimation Evaporation Heat Temperature Energy Enthalpy Entropy Joule Specific heat calorie
Homework Due Next Class: Complete your flashcards