Decide if an equation has no solutions Solve, if possible. Example 4 53x3x + 6 = + 2 – Write original equation. 53x3x + 6 = + 2 – Subtract 6 from each.

Slides:



Advertisements
Similar presentations
EXAMPLE 1 Solve quadratic equations Solve the equation. a. 2x 2 = 8 SOLUTION a. 2x 2 = 8 Write original equation. x 2 = 4 Divide each side by 2. x = ±
Advertisements

EXAMPLE 4 Solve proportions SOLUTION a x 16 = Multiply. Divide each side by 10. a x 16 = = 10 x5 16 = 10 x80 = x8 Write original proportion.
Solve an equation with variables on both sides
EXAMPLE 1 Solve a quadratic equation by finding square roots Solve x 2 – 8x + 16 = 25. x 2 – 8x + 16 = 25 Write original equation. (x – 4) 2 = 25 Write.
Solve an absolute value inequality
Solve an equation by combining like terms
EXAMPLE 1 Solve a quadratic equation having two solutions Solve x 2 – 2x = 3 by graphing. STEP 1 Write the equation in standard form. Write original equation.
EXAMPLE 1 Solve a simple absolute value equation Solve |x – 5| = 7. Graph the solution. SOLUTION | x – 5 | = 7 x – 5 = – 7 or x – 5 = 7 x = 5 – 7 or x.
Solve an absolute value equation EXAMPLE 2 SOLUTION Rewrite the absolute value equation as two equations. Then solve each equation separately. x – 3 =
Solve an equation using subtraction EXAMPLE 1 Solve x + 7 = 4. x + 7 = 4x + 7 = 4 Write original equation. x + 7 – 7 = 4 – 7 Use subtraction property of.
Decide if an equation has no solutions EXAMPLE 4 3x = –2 Write original equation. 3x + 5 = –8 Subtract 6 from each side. ANSWER The absolute value.
Standardized Test Practice
EXAMPLE 1 Collecting Like Terms x + 2 = 3x x + 2 –x = 3x – x 2 = 2x 1 = x Original equation Subtract x from each side. Divide both sides by x2x.
Standardized Test Practice
EXAMPLE 4 Solve a multi-step problem CRAFTS You decide to use chalkboard paint to create a chalkboard on a door. You want the chalkboard to have a uniform.
EXAMPLE 1 Identify direct variation equations
EXAMPLE 3 Solve an equation by factoring Solve 2x 2 + 8x = 0. 2x 2 + 8x = 0 2x(x + 4) = 0 2x = 0 x = 0 or x + 4 = 0 or x = – 4 ANSWER The solutions of.
Standardized Test Practice
Lesson 13.4 Solving Radical Equations. Squaring Both Sides of an Equation If a = b, then a 2 = b 2 Squaring both sides of an equation often introduces.
Solve a radical equation
7-5 Logarithmic & Exponential Equations
Substitute 0 for y. Write original equation. To find the x- intercept, substitute 0 for y and solve for x. SOLUTION Find the x- intercept and the y- intercept.
Substitute 0 for y. Write original equation. To find the x- intercept, substitute 0 for y and solve for x. SOLUTION Find the x- intercept and the y- intercept.
EXAMPLE 2 Rationalize denominators of fractions Simplify
CAR SALES Solve a real-world problem EXAMPLE 3 A car dealership sold 78 new cars and 67 used cars this year. The number of new cars sold by the dealership.
Section 5 Absolute Value Equations and Inequalities
2.6 Solving Quadratic Equations with Complex Roots 11/9/2012.
EXAMPLE 1 Identifying Slopes and y -intercepts Find the slope and y -intercept of the graph of the equation. a. y = x – 3 b. – 4x + 2y = 16 SOLUTION a.
Solve absolute value equations Section 6.5 #44 There is nothing strange in the circle being the origin of any and every marvel. Aristotle.
Solve an equation by combining like terms EXAMPLE 1 8x – 3x – 10 = 20 Write original equation. 5x – 10 = 20 Combine like terms. 5x – =
Solving Inequalities by adding or subtracting, checking the inequality & graphing it!! This is so easy you won’t even need one of these!!!
Ch. 1-5 Absolute Value Equations and Inequalities.
6.5 Warm Up Warm Up Lesson Quiz Lesson Quiz Lesson Presentation Lesson Presentation Solve Absolute Value Equations.
Solve an absolute value equation EXAMPLE 2 SOLUTION Rewrite the absolute value equation as two equations. Then solve each equation separately. x – 3 =
Objective SWBAT solve absolute value equations.. ABSOLUTE VALUE –The distance a number is away from ZERO. Distance is always positive
EXAMPLE 1 Identify slope and y-intercept Identify the slope and y- intercept of the line with the given equation. y = 3x x + y = 22. SOLUTION The.
Solve an equation using addition EXAMPLE 2 Solve x – 12 = 3. Horizontal format Vertical format x– 12 = 3 Write original equation. x – 12 = 3 Add 12 to.
EXAMPLE 1 Solve by equating exponents Rewrite 4 and as powers with base Solve 4 = x 1 2 x – 3 (2 ) = (2 ) 2 x – 3x – 1– 1 2 = 2 2 x– x + 3 2x =
Example 1 Solving Two-Step Equations SOLUTION a. 12x2x + 5 = Write original equation. 112x2x + – = 15 – Subtract 1 from each side. (Subtraction property.
EXAMPLE 2 Checking Solutions Tell whether (7, 6) is a solution of x + 3y = 14. – x + 3y = 14 Write original equation ( 6) = 14 – ? Substitute 7 for.
Solve an inequality using subtraction EXAMPLE 4 Solve 9  x + 7. Graph your solution. 9  x + 7 Write original inequality. 9 – 7  x + 7 – 7 Subtract 7.
EXAMPLE 1 Solve a two-step equation Solve + 5 = 11. x 2 Write original equation. + 5 = x – 5 = x 2 11 – 5 Subtract 5 from each side. = x 2 6 Simplify.
Use the substitution method
Example 2 Multiple Choice Practice
4.4 Absolute Value 11/14/12. Absolute Value: The distance of a number from 0 on a number line. Written as l x l Ex. |5| (distance of 5 from 0) = 5 Ex.
Algebra 2 Lesson 1-5 (Page 33) ALGEBRA 2 LESSON 1-5 Absolute Value Equations and Inequalities 1-1.
Lesson 6.5 Solve Absolute Value Equations
5.5 Solve Absolute Value Equations
EXAMPLE 1 Find an inverse relation Find an equation for the inverse of the relation y = 3x – 5. Write original relation. y = 3x – 5 Switch x and y. x =
Multiply one equation, then add
x + 5 = 105x = 10  x = (  x ) 2 = ( 5 ) 2 x = 5 x = 2 x = 25 (5) + 5 = 105(2) = 10  25 = 5 10 = = 10 5 = 5.
Warm-Up Exercises 1. Solve |x – 6| = Solve |x + 5| – 8 = 2. ANSWER 2, 10 ANSWER –15, 5.
Solve a two-step equation by combining like terms EXAMPLE 2 Solve 7x – 4x = 21 7x – 4x = 21 Write original equation. 3x = 21 Combine like terms. Divide.
Solving 2 step equations. Two step equations have addition or subtraction and multiply or divide 3x + 1 = 10 3x + 1 = 10 4y + 2 = 10 4y + 2 = 10 2b +
Substitution Method: Solve the linear system. Y = 3x + 2 Equation 1 x + 2y=11 Equation 2.
Chapter 1.7 Solve Absolute Value Equations and Inequalities Analyze Situations using algebraic symbols; Use models to understand relationships.
Section 5 Absolute Value Equations and Inequalities
Rewrite a linear equation
Solve Absolute Value Equations
EXAMPLE 2 Rationalize denominators of fractions Simplify
Solve Absolute Value Equations
Solve a literal equation
1. For a = –12, find, –a and |a|. ANSWER 12, 12 2.
Solve a quadratic equation
Solving Equations by Factoring and Problem Solving
EXAMPLE 1 Complete the square
10.7 Solving Quadratic Equations by Completing the Square
Solving One Step Equations
Solve Absolute Value Inequalities
Solve an inequality using subtraction
Presentation transcript:

Decide if an equation has no solutions Solve, if possible. Example 4 53x3x + 6 = + 2 – Write original equation. 53x3x + 6 = + 2 – Subtract 6 from each side. 53x3x + = 8 – The absolute value of a number is never negative. So, there are no solutions. ANSWER

Use absolute deviation Example 5 Before the start of a professional basketball game, a basketball must be inflated to an air pressure of 8 pounds per square inch (psi) with an absolute error of 0.5 psi. Find the minimum and maximum acceptable air pressures for the basketball. BASKETBALLS Let p be the air pressure (in psi) of a basketball. Write a verbal model. Then write and solve an absolute value equation. SOLUTION

Use absolute deviation Example 5 Write original equation. 0.5 = 8p – or Rewrite as two equations. 0.5 = 8p – = 8p – – or Add 8 to each side. 8.5 = p = p 7.5 The minimum and maximum acceptable pressures are 7.5 psi and 8.5 psi. ANSWER

Guided Practice for Examples 4 and 5 8. Solve the equation, if possible. 5m4 = + 2 – n7 = 3 – + – 10 – 10. An NCAA football must be inflated to an air pressure of 13 psi with an absolute error of 0.5 psi. Find the minimum and maximum acceptable air pressures for an NCAA football. FOOTBALL ANSWER no solution ANSWER 12.5 psi, 13.5 psi ANSWER 1, – 3 –