Chemistry 205 Chemical Nomenclature Bonus Quiz #1 (6 points) 1. Give a chemical name for the following compounds. a. Na 2 S b. SO 3 c. Mg(NO 3 ) 2 2. Write the formula for each of the following compounds. a. Phosphorus tribromide b. Calcium iodide c. Iron(II) phosphate

Chemistry 205 Chemical Nomenclature Bonus Quiz #1 (Answer Key) 1. Give a chemical name for the following compounds. a. Na 2 S sodium sulfide This is a binary compound composed of a metal and a nonmetal. The –ide ending indicates a binary compound. Because sodium has only a charge of only 1+ and sulfide is 2–, there is only one formula for sodium sulfide. b. SO 3 sulfur trioxide This is a binary compound composed of two nonmetals. The –ide ending indicates a binary compound and with two nonmetals, the number of atoms must also be given.

Chemistry 205 Chemical Nomenclature Bonus Quiz #1 (Answer Key) 1. c. Mg(NO 3 ) 2 magnesium nitrate The name magnesium can be used since the magnesium ion has a fixed charge (2+). Since the nitrate ion has a charge of 1-, the formula must have 2 nitrate ions and no prefix is required. a. Phosphorus tribromide 2. Write the formula for each of the following compounds. PBr 3 This is a binary compound composed of two nonmetals. In this case the name gives both the name and the number for each of the two elements in the compound. The first element is phosphorus and there is one, and the second element (indicated by the one ending in –ide) is bromine, and there are three.

Chemistry 205 Chemical Nomenclature Bonus Quiz #1 (Answer Key) 2. b. Calcium iodide CaI 2 This is a binary compound, composed of a metal and a nonmetal. The –ide ending indicates a binary compound. With a metal and a nonmetal no prefixes indicating the number of atoms are required. Calcium has only one charge (2+) and the iodide ion is 1–, so two iodide ions are needed To balance the 2+ of the calcium ion. c. Iron(II) phosphate Fe 3 (PO 4 ) 2 The iron(II) ion has a charge of 2+ and the charge of the phosphate ion is 3-. Therefore, the formula will require 3 iron (II) ions (total charge of 6+) to go with 2 phosphate ions (total charge of 6-)

Chemistry 205 Chemical Nomenclature Bonus Quiz #2 (6 points) 1. Give a chemical name for the following compounds. a. N 2 O 5 b. Fe 3 N 2 c. Ba(OH) 2 2. Write the formula for each of the following compounds. a. Zinc bromide b. Ammonium carbonate c. Lead(IV) sulfate

Chemistry 205 Chemical Nomenclature Bonus Quiz #2 (Answer Key) 1. Give a chemical name for the following compounds. Iron(II) nitride This is a binary compound composed of a metal and a nonmetal. The –ide ending indicates a binary compound. Because iron has two possible charges (2+ and 3+), the name must indicate which one is present. The nitride ion is always 3– and since there are two nitride ions in the compound, the total negative is 6–. The charge on the iron therefore is 2+ (3 x 2+ = 6+) dinitrogen pentoxide This is a binary compound composed of two nonmetals. The –ide ending indicates a binary compound and with two nonmetals, the number of atoms must also be given, di- for two nitrogens and pent- for five oxygens. a. N 2 O 5 b. Fe 3 N 2

Chemistry 205 Chemical Nomenclature Bonus Quiz #2 (Answer Key) 1. c. Ba(OH) 2 barium hydroxide The name barium can be used since the magnesium ion has a fixed charge (2+). Since the hydroxide ion has a charge of 1-, the formula must have two hydroxide ions and no prefix is required. a. Zinc bromide 2. Write the formula for each of the following compounds. ZnBr 2 This is a binary compound composed of a metal and a nonmetal. Since the zinc ion has a fixed charge of 2+ and the bromide ion has a fixed charge of 1–, the formula For the compound will contain one zinc ion (1 x 2+ = 2+) And two bromide ions (2 x 1– = 2–).

Chemistry 205 Chemical Nomenclature Bonus Quiz #2 (Answer Key) 2. b. Ammonium carbonate The ammonium ion has a charge of 1+ (NH 4 1+ ) and the carbonate ion has a charge of 2– (CO 3 2– ). The formula therefore contains 2 ammonium ions (2 x 1+ = 2+) to balance One carbonate ion (1 x 2– = 2–). c. Lead(IV) sulfatePb(SO 4 ) 2 The lead(IV) ion has a charge of 4+ and the charge of the sulfate ion is 2-. Therefore, the formula will require 1 lead(IV) ion (total charge of 4+) to go with 2 sulfate ions (total charge of 4-) (NH 4 ) 2 CO 3