Copyright ©2011 Brooks/Cole, Cengage Learning Testing Hypotheses about Means Chapter 13

Copyright ©2011 Brooks/Cole, Cengage Learning 2 Hypothesis testing about: a population mean a population mean difference (paired data) the difference between means of two populations Three Cautions: 1. Inference is only valid if the sample is representative of the population for the question of interest. 2. Hypotheses and conclusions apply to the larger population(s) represented by the sample(s). 3. If the distribution of a quantitative variable is highly skewed, consider analyzing the median rather than the mean – called nonparametric methods (Topic 2 on CD).

Copyright ©2011 Brooks/Cole, Cengage Learning Introduction to Hypothesis Tests for Means Steps in Any Hypothesis Test 1.Determine the null and alternative hypotheses. 2.Verify necessary data conditions, and if met, summarize the data into an appropriate test statistic. 3.Assuming the null hypothesis is true, find the p-value. 4.Decide whether or not the result is statistically significant based on the p-value. 5.Report the conclusion in the context of the situation.

Copyright ©2011 Brooks/Cole, Cengage Learning HT Module 3: Testing Hypotheses about One Mean Step 1: Determine null and alternative hypotheses 1. H 0 :  =  0 versus H a :    0 (two-sided) 2. H 0 :  =  0 versus H a :  <  0 (one-sided) 3. H 0 :  =  0 versus H a :  >  0 (one-sided) Remember a p-value is computed assuming H 0 is true, and  0 is the value used for that computation.

Copyright ©2011 Brooks/Cole, Cengage Learning 5 Situation 1: Population of measurements of interest is approximately normal, and a random sample of any size is measured. In practice, use method if shape is not notably skewed or no extreme outliers. Situation 2: Population of measurements of interest is not approximately normal, but a large random sample (n  30) is measured. If extreme outliers or extreme skewness, better to have a larger sample. Step 2: Verify Necessary Data Conditions …

Copyright ©2011 Brooks/Cole, Cengage Learning 6 The t-statistic is a standardized score for measuring the difference between the sample mean and the null hypothesis value of the population mean: Continuing Step 2: The Test Statistic This t-statistic has (approx) a t-distribution with df = n - 1.

Copyright ©2011 Brooks/Cole, Cengage Learning 7 For H a less than, the p-value is the area below t, even if t is positive. For H a greater than, the p-value is the area above t, even if t is negative. For H a two-sided, p-value is 2  area above |t|. Step 3: Assuming H 0 true, Find the p-value

Copyright ©2011 Brooks/Cole, Cengage Learning 8 These two steps remain the same for all of the hypothesis tests considered in this book. Choose a level of significance , and reject H 0 if the p-value is less than (or equal to) . Otherwise, conclude that there is not enough evidence to support the alternative hypothesis. Steps 4 and 5: Decide Whether or Not the Result is Statistically Significant based on the p-value and Report the Conclusion in the Context of the Situation

Copyright ©2011 Brooks/Cole, Cengage Learning 9 Example 13.1 Normal Body Temperature What is normal body temperature? Is it actually less than 98.6 degrees Fahrenheit (on average)? Step 1: State the null and alternative hypotheses H 0 :  = 98.6 H a :  < 98.6 where  = mean body temperature in human population.

Copyright ©2011 Brooks/Cole, Cengage Learning 10 Example 13.1 Normal Body Temp (cont) Data: random sample of n = 16 normal body temps Step 2: Verify data conditions … 98.4, 98.6, 98.8, 98.8, 98.0, 97.9, 98.5, 97.6, 98.4, 98.3, 98.9, 98.1, 97.3, 97.8, 98.4, 97.4 Boxplot shows no outliers nor strong skewness. Sample mean of 98.2 is close to sample median of

Copyright ©2011 Brooks/Cole, Cengage Learning 11 Example 13.1 Normal Body Temp (cont) Step 2: … Summarizing data with a test statistic Key elements: Sample statistic: = (under “Mean”) Standard error: (under “SE Mean”) (under “T”)

Copyright ©2011 Brooks/Cole, Cengage Learning 12 Example 13.1 Normal Body Temp (cont) Step 3: Find the p-value From output: p-value = From Table A.3: p-value is less than

Copyright ©2011 Brooks/Cole, Cengage Learning 13 Example 13.1 Normal Body Temp (cont) Step 4: Decide whether or not the result is statistically significant based on the p-value Using  = 0.05 as the level of significance criterion, the results are statistically significant because 0.003, the p-value of the test, is less than In other words, we can reject the null hypothesis. Step 5: Report the Conclusion We can conclude, based on these data, that the mean temperature in the human population is actually less than 98.6 degrees.

Copyright ©2011 Brooks/Cole, Cengage Learning 14 Rejection Region Approach Replaces Steps 3 and 4 with: Substitute Step 3: Find the critical value and rejection region for the test. Substitute Step 4: If the test statistic is in the rejection region, conclude that the result is statistically significant and reject the null hypothesis. Otherwise, do not reject the null hypothesis. Note: Rejection region method and p-value method will always arrive at the same conclusion about statistical significance.

Copyright ©2011 Brooks/Cole, Cengage Learning 15 Rejection Region Approach Summary (use row of Table A.2 corresponding to df) For Example 13.1 Normal Body Temperature? Alternative was one-sided to the left, df = 15, and  = Critical value from table A.2 is –1.75. Rejection region is t  – The test statistic was –3.22 so the null hypothesis is rejected. Same conclusion is reached.

Copyright ©2011 Brooks/Cole, Cengage Learning HT Module 4: Testing Hypotheses about Mean of Paired Differences Data: two variables for n individuals or pairs; use the difference d = x 1 – x 2. Parameter:  d = population mean of differences Sample estimate: = sample mean of the differences Standard deviation and standard error: s d = standard deviation of the sample of differences; Often of interest: Is the mean difference in the population different from 0?

Copyright ©2011 Brooks/Cole, Cengage Learning 17 Steps for a Paired t-Test Step 1: Determine null and alternative hypotheses H 0 :  d =  versus H a :  d   or H a :  d  Watch how differences are defined for selecting the H a. Step 2: Verify data conditions and compute test statistic Conditions apply to the differences. The t-test statistic is: Steps 3, 4 and 5: Similar to t-test for a single mean. The df = n – 1, where n is the number of differences.

Copyright ©2011 Brooks/Cole, Cengage Learning 18 Example 13.2 Effect of Alcohol Study: n = 10 pilots perform simulation first under sober conditions and then after drinking alcohol. Response: Amount of useful performance time. (longer time is better) Question: Does useful performance time decrease with alcohol use? Step 1: State the null and alternative hypotheses H 0 :  d = 0 versus H a :  d > 0 where  d = population mean difference between alcohol and no alcohol measurements if all pilots took these tests.

Copyright ©2011 Brooks/Cole, Cengage Learning 19 Example 13.2 Effect of Alcohol (cont) Data: random sample of n = 10 time differences Step 2: Verify data conditions … Boxplot shows no outliers nor extreme skewness.

Copyright ©2011 Brooks/Cole, Cengage Learning 20 Example 13.2 Effect of Alcohol (cont) Step 2: … Summarizing data with a test statistic Test of mu = 0.0 vs mu > 0.0 Variable N Mean StDev SE Mean T P Diff Key elements: Sample statistic: = (under “Mean”) Standard error: (under “SE Mean”) (under “T”)

Copyright ©2011 Brooks/Cole, Cengage Learning 21 Example 13.2 Effect of Alcohol (cont) Step 3: Find the p-value From output: p-value = From Table A.3: p-value is between and The value t = 2.68 is between column headings 2.58 and 3.00 in the table, and for df =9, the one-sided p-values are and

Copyright ©2011 Brooks/Cole, Cengage Learning 22 Example 13.2 Effect of Alcohol (cont) Steps 4 and 5: Decide whether or not the result is statistically significant based on the p-value and Report the Conclusion Using  = 0.05 as the level of significance criterion, we can reject the null hypothesis since the p-value of is less than Even with a small experiment, it appears that alcohol has a statistically significant effect and decreases performance time.

Copyright ©2011 Brooks/Cole, Cengage Learning HT Module 5: Testing Hypotheses about Difference between Two Means Step 1: Determine null and alternative hypotheses H 0 :  1 –  2 =  versus H a :  1 –  2   or H a :  1 –  2  Watch how Population 1 and 2 are defined. Lesson 1: the General (Unpooled) Case

Copyright ©2011 Brooks/Cole, Cengage Learning 24 Step 2: Verify data conditions and compute the test statistic. Both n’s are large or no extreme outliers or skewness in either sample. Samples are independent. The t-test statistic is: Steps 3, 4 and 5: Similar to t-test for one mean.

Copyright ©2011 Brooks/Cole, Cengage Learning 25 Example 13.4 Effect of Stare on Driving Question: Does stare speed up crossing times? Step 1: State the null and alternative hypotheses H 0 :  1 –  2 =  versus H a :  1 –  2 >  where 1 = no-stare population and 2 = stare population. Randomized experiment: Researchers either stared or did not stare at drivers stopped at a campus stop sign; Timed how long (sec) it took driver to proceed from sign to a mark on other side of the intersection.

Copyright ©2011 Brooks/Cole, Cengage Learning 26 Example 13.3 Effect of Stare (cont) Data: n 1 = 14 no stare and n 2 = 13 stare responses Step 2: Verify data conditions … No outliers nor extreme skewness for either group.

Copyright ©2011 Brooks/Cole, Cengage Learning 27 Example 13.3 Effect of Stare (cont) Step 2: … Summarizing data with a test statistic Sample statistic: = 6.63 – 5.59 = 1.04 seconds Standard error:

Copyright ©2011 Brooks/Cole, Cengage Learning 28 Example 13.3 Effect of Stare (cont) Steps 3, 4 and 5: Determine the p-value and make a conclusion in context. The p-value = 0.013, so we reject the null hypothesis, the results are “statistically significant”. The p-value is determined using a t-distribution with df = 21 (df using Welch approximation formula) and finding area to right of t = Table A.3  p-value is between and We can conclude that if all drivers were stared at, the mean crossing times at an intersection would be faster than under normal conditions.

Copyright ©2011 Brooks/Cole, Cengage Learning 29 Lesson 2: Pooled Two-Sample t-Test Based on assumption that the two populations have equal population standard deviations: Note: Pooled df = (n 1 – 1) + (n 2 – 1) = (n 1 + n 2 – 2).

Copyright ©2011 Brooks/Cole, Cengage Learning 30 The null and alternative hypotheses are: H 0 :  1 –  2 =  versus H a :  1 –  2   where 1 = female population and 2 = male population. Example 13.7 Male and Female Sleep Times Data:The 83 female and 65 male responses from students in an intro stat class. Note: Sample sizes similar, sample standard deviations similar. Use of pooled procedure is warranted. Q: Is there a difference between how long female and male students slept the previous night?

Copyright ©2011 Brooks/Cole, Cengage Learning 31 Example 13.5 Male and Female Sleep Times Two-sample T for sleep [without “Assume Equal Variance” option] Sex N Mean StDev SE Mean Female Male % CI for mu(f) – mu(m): (-0.10, 1.02) T-Test mu (f) = mu(m) (vs not =): T-Value = 1.62 P = 0.11 DF = 140 Two-sample T for sleep [with “Assume Equal Variance” option] Sex N Mean StDev SE Mean Female Male % CI for mu(f) – mu(m): (-0.10, 1.03) T-Test mu (f) = mu(m) (vs not =): T-Value = 1.62 P = 0.11 DF = 146 Both use Pooled StDev = 1.72

Copyright ©2011 Brooks/Cole, Cengage Learning Relationship Between Tests and Confidence Intervals For two-sided tests (for one or two means): H 0 : parameter = null value and H a : parameter  null value Note: 95% confidence interval  5% significance level 99% confidence interval  1% significance level If the null value is covered by a (1 –  )100% confidence interval, the null hypothesis is not rejected and the test is not statistically significant at level . If the null value is not covered by a (1 –  )100% confidence interval, the null hypothesis is rejected and the test is statistically significant at level .

Copyright ©2011 Brooks/Cole, Cengage Learning 33 Example 13.9 Ear Infections and Xylitol 95% CI for p 1 – p 2 is to Reject H 0 : p 1 – p 2 =  and accept H a : p 1 – p 2 >  with  = 0.025, because the entire confidence interval falls above the null value of 0. Note that the p-value for the test was 0.01, which is less than

Copyright ©2011 Brooks/Cole, Cengage Learning Choosing an Appropriate Inference Procedure Confidence Interval or Hypothesis Test? Is main purpose to estimate the numerical value of a parameter? … or to make a “maybe not/maybe yes” conclusion about a specific hypothesized value for a parameter?

Copyright ©2011 Brooks/Cole, Cengage Learning Choosing an Appropriate Inference Procedure Determining the Appropriate Parameter Is response variable categorical or quantitative? Is there one sample or two? If two, independent or paired?

Copyright ©2011 Brooks/Cole, Cengage Learning Evaluating Significance in Research Reports 1.Is the p-value reported? If know p-value, can make own decision, based on severity of Type 1 error and p-value. 2.If word significant is used, determine whether used in everyday sense or in statistical sense only. Statistically significant just means that a null hypothesis has been rejected, no guarantee the result has real-world importance. 3.If you read “no difference” or “no relationship” has been found, determine whether sample size was small. Test may have had very low power because not enough data were collected to be able to make a firm conclusion.

Copyright ©2011 Brooks/Cole, Cengage Learning Evaluating Significance in Research Reports 4.Think carefully about conclusions based on extremely large samples. If very large sample size, even weak relationship or small difference can be statistically significant. 5.If possible, determine what confidence interval should accompany a hypothesis test. Intervals provide information about magnitude of effect as well as information about margin of error in sample estimate. 6.Determine how many hypothesis tests were conducted in study. Sometimes researchers perform multitude of tests, but only few achieve statistical significance. If all null hypotheses true, then ~1 in 20 tests will achieve statistical significance just by chance at the.05 level of significance.