D = M V First, enter the givens into the density table. 48,000 tons 1. Find the density of a substance whose mass is 48,000 tons and volume is pL? 48,000 tons pL? pL

D = M V Next, enter the units from the mass and volume into the left side of the density table. 1. Find the density of a substance whose mass is 48,000 tons and volume is pL? 48,000 tons = ? pL = ? tons pL No conversion is necessary.

D Use the formula triangle to determine the correct formula. 1. Find the density of a substance whose mass is 48,000 tons and volume is pL? V M ÷ MVMV x D =

M V Substitute the values into the equation. 1. Find the density of a substance whose mass is 48,000 tons and volume is pL? 48,000 tons = ? pL = ? tons pL D = M/V D = (48,000 tons) / ( pL)

D = M V Divide and round to the LEAST number of significant digits. 1. Find the density of a substance whose mass is 48,000 tons and volume is pL? 48,000 tons = ? pL = ? tons pL D = M/V D = (48,000 tons) / ( pL) D = 8.0 x 10 7 tons/pL

D = M V First, enter the givens into the density table lbs 1 Tm 3 2. Find the volume of a substance whose density is 49.7 lbs/Tm 3 and mass is 204,900 ng? 49.7 lbs/Tm 3 204,900 ng ? 204,900 ng

D = M V Next, enter the units from the density into the right side of the density table lbs 1 Tm 3 2. Find the volume of a substance whose density is 49.7 lbs/Tm 3 and mass is 204,900 ng? 204,900 ng = ? Tm 3 = ? lbs

D = M V If a conversion is necessary, complete it now lbs 1 Tm 3 2. Find the volume of a substance whose density is 49.7 lbs/Tm 3 and mass is 204,900 ng? 204,900 ng = ? Tm 3 = ? lbs

Start with what you are looking for!! lbs Since lbs is an English unit and the given, ng, is a metric unit, Ms. Mullins must provide an English to metric conversion. Always look back at the instructions to find the conversions. Use: 1 lb = g g

Bring the denominator unit up to the next numerator. 1 lb g g

Convert grams to nanograms. 1 lb g g ng

Since g is further left (so it is larger) than ng, g gets the one and ng gets the ten. T _ _ G _ _ M _ _ k h da unit d c m _ _ μ _ _ n _ _ p lb g g ng

Bring the denominator unit up to the next numerator. 1 lb g g ng ng When you have reached the given unit, ng, then insert the given numerical value. 204,900

1 lb g g ng ng 204,900 SOLVE!! = x 10  7 lbs

D = M V Enter the answer from the dimensional analysis into the density table lbs 1 Tm 3 2. Find the volume of a substance whose density is 49.7 lbs/Tm 3 and mass is 204,900 ng? 204,900 ng = ? Tm 3 = x 10  7 lbs

D Use the formula triangle to determine the correct formula. 2. Find the volume of a substance whose density is 49.7 lbs/Tm 3 and mass is 204,900 ng? V M ÷ MDMD x V =

D = M V Substitute the values into the equation lbs 1 Tm 3 2. Find the volume of a substance whose density is 49.7 lbs/Tm 3 and mass is 204,900 ng? 204,900 ng Tm 3 V = M/D V = (4.517 x 10  7 lbs) / (49.7 lbs/Tm 3 ) = x 10  7 lbs

D = M V Divide and round to the LEAST number of significant digits lbs 1 Tm 3 2. Find the volume of a substance whose density is 49.7 lbs/Tm 3 and mass is 204,900 ng? 204,900 ng Tm 3 V = M/D V = (4.517 x 10  7 lbs) / (49.7 lbs/Tm 3 ) = x 10  7 lbs V = 2.24 x 10  5 Tm 3

D = M V First, enter the givens into the density table lbs 1 Tm 3 3. Find the mass of a substance whose density is lbs/mm 3 and volume is x 10 7 mi 3 ? lbs/Tm x 10 7 mi 3 ? x 10 7 mi 3

D = M V Next, enter the units from the density into the right side of the density table lbs 1 Tm 3 3. Find the mass of a substance whose density is lbs/Tm 3 and volume is x 10 7 mi 3 ? x 10 7 mi 3 = ? Tm 3 = ? lbs

D = M V If a conversion is necessary, complete it now lbs 1 Tm 3 3. Find the mass of a substance whose density is lbs/Tm 3 and volume is x 10 7 mi 3 ? x 10 7 mi 3 = ? Tm 3 = ? lbs

Start with what you are looking for!! Tm 3 Since Tm 3 is a metric unit and the given, mi 3, is an English unit, Ms. Mullins must provide an English to metric conversion. Always look back at the instructions to find the conversions. Use: 1 m = yd

Tm 3 However, the conversion is not a cubic conversion so m = yd (1 m) 3 = ( yd) 3 1 m 3 = yd 3

Tm 3 In order to use the conversion, Tm 3 must be converted to m 3

Since Tm 3 is further left (so it is larger) than m 3, Tm 3 gets the one and m 3 gets the ten. Tm 3 m3m3 T _ _ G _ _ M _ _ k h da unit d c m _ _ μ _ _ n _ _ p 1 10

Either count by threes Tm 3 m3m3 T _ _ G _ _ M _ _ k h da unit d c m _ _ μ _ _ n _ _ p

Or count between units and multiply by three. Tm 3 m3m3 T _ _ G _ _ M _ _ k h da unit d c m _ _ μ _ _ n _ _ p x 3 = 36

Bring the denominator unit up to the next numerator. 1 Tm m 3 m 3

Now use the English to metric cubic conversion. 1 Tm 3 1 m = yd (1 m) 3 = ( yd) 3 1 m 3 = yd m 3 m3m yd 3

Bring the denominator unit up to the next numerator. 1 Tm m 3 m3m yd 3 yd 3

Remember that you are working towards the given which is mi 3. 1 Tm m 3 m3m yd 3 yd 3 There isn’t a conversion between yards and miles, but there is between feet and miles, so first develop a conversion between yd 3 and ft 3. 1 yd = 3 ft (1 yd) 3 = (3 ft) 3 1 yd 3 = 27 ft 3 ft

Bring the denominator unit up to the next numerator. 1 Tm m 3 m3m yd 3 1 yd 3 27 ft 3 ft 3

Remember that you are working towards the given which is mi 3. 1 Tm m 3 m3m yd 3 yd 3 There is a conversion between feet and miles, so first develop a conversion between ft 3 and mi ft = 1 mi (5280 ft) 3 = (1 mi) x ft 3 = 1 mi 3 ft ft 3 mi x

Bring the denominator unit up to the next numerator. 1 Tm 3 1 m 3 1 yd x ft m yd 3 27 ft 3 1 mi 3 mi 3

1 Tm 3 1 m 3 1 yd x ft m yd 3 27 ft 3 1 mi 3 mi x 10 7 When you have reached the given unit, mi 3, then insert the given numerical value.

SOLVE!! 1 Tm 3 1 m 3 1 yd x ft m yd 3 27 ft 3 1 mi 3 mi x 10 7 = x 10  19 Tm 3

D = M V Enter the answer from the dimensional analysis into the density table lbs 1 Tm 3 3. Find the mass of a substance whose density is lbs/Tm 3 and volume is x 10 7 mi 3 ? x 10 7 mi 3 = x 10  19 = ? lbs Tm 3

D Use the formula triangle to determine the correct formula. 3. Find the mass of a substance whose density is lbs/Tm 3 and volume is x 10 7 mi 3 ? V M ÷ M = D  V x

D = M V Substitute the values into the equation lbs 1 Tm 3 3. Find the mass of a substance whose density is lbs/Tm 3 and volume is x 10 7 mi 3 ? x 10 7 mi 3 = x 10  19 = ? lbs Tm 3 M = D  V M = ( lbs/Tm 3 ) ( x 10  19 Tm 3 )

D = M V Multiply and round to the LEAST number of significant digits lbs 1 Tm 3 3. Find the mass of a substance whose density is lbs/Tm 3 and volume is x 10 7 mi 3 ? x 10 7 mi 3 = x 10  19 = ? lbs Tm 3 M = D  V M = ( lbs/Tm 3 ) ( x 10  19 Tm 3 ) M = (2.041 x 10  21 lbs)

Practice Problems: 1. Find the mass of a substance whose density is x 10  6 dg/yd 3 and volume is 94,000 Mm 3 ? 2. Find the density of a substance whose mass is 1.87 x 10  6 cg and volume is 234,567 dam 3 ? 3. Find the volume of a substance whose density is Gg/hm 3 and mass is 204,900 tons? 4. Find the mass of a substance whose density is lbs/nL and volume is x 10 4 yd 3 ? 5. Find the density of a substance whose mass is 4.8 x kg and volume is 640,800 TL? 6. Find the volume of a substance whose density is 3.04 x 10  23  g/  m 3 and mass is oz?