Chapter 7 Energy Energy and persistence conquer all things. -Benjamin Franklin.

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Presentation transcript:

Chapter 7 Energy Energy and persistence conquer all things. -Benjamin Franklin

What are the different types of Energy? Mechanical Energy Kinetic Energy Mechanical Potential Energy Electrical Energy Electrical Potential Energy Thermal Energy Chemical Potential Energy Mass Energy Electromagnetic Energy Nuclear Energy Sound Energy

So what really is Energy? Energy is present throughout the universe in different forms. Every physical process somehow involves energy. Energy can be transferred but can not be created or destroyed (Conservation of Energy). Ex. When you turn on the TV, we transform electrical energy into sound, light, and heat energy

One of the most basic forms of energy is Mechanical Energy, or work. What is work? Mechanical Energy applied through a force M F F FNFN Δx θ

In order to determine how much work is done on the block we will use this equation: W = (F Δx) = |F||Δx| Note: This is the first time we have seen the SCALAR product of two vectors Note: The unit for work is Newton x meter or This is also the unit for Energy (J)

Dot products make vector calculation easier: In order to obtain a scalar product, two vectors are multiplied. This process is called the Dot Product. Instead of using an x to multiply we use a dot Ex. A B = C (C= scalar number) abs(A B) = C Normal properties of multiplication apply eg: Distributive Associative C (A B) = CA B A ( B + C) = AB + AC = A CB and dot products ARE commutative

So what is the dot product of a vector multiplied by a perpendicular vector? Zero! ( A A) = abs(A) abs(A) = abs(A 2 ) ( A B)  when A and B are perpendicular to each other they equal zero In order to observe this they have to be broken down into their components: A  (a x i, a y j, a z k) B  (b x i, b y j, b z k)

We can observe this property of Dot Products by taking the equation in component form: A · B = (a x x, a y y, a z z) · (b x x, b y y, b z z) =a x b x (x·x) + a y b y (y·y) + a z b z (z·z) + a x b y (x·y) + a x b z (x·z) + a y b z (y·z) + a y b x (y·x) + a z b x (z·x) + a z b y (z·y)

So the parallel parts can be multiplied by the perpendicular parts will equal zero. We can observe this with the Dot Product equation: A B = (a x x, a y y, a z z) (b x x, b y y, b z z) =a x b x xx + a y b y yy + a z b z zz + a x b y xy + a x b z xz + a y b z yz + a y b x yx + a z b x zx + a z b y zy =a x b x xx + a y b y yy + a z b z zz =a x b x + a y b y + a z b z = A B

So when should I use a which equation? If you have the length of a Vector and θ use: (| A|| B|) = A B If you do not have θ use: (a x b x + a y b y + a z b z )

An example: Given: F = 40 N West, Δx = 5m 30° NW What equation would you use and solve?

An example: Given: F = 40 N West, Δx = 5m 30° NW We know: W = F Δx (40N)(5m) cos30 = 173 N m

An example: Given: F = (10 Ni, 5 Nj, 2 Nk) Δx = (2 mi, -6 mj, -4 mk) What equation would you use and solve?

An example: Given: F = (10 Ni, 5 Nj, 2 Nk) Δx = (2 mi, -6 mj, -4 mk) F Δx = (10N x 2m) + (5N x -6m) + (2N x -4m) = -18 J So what does it mean when the energy is +/-? … it tells you whether the object gave or received energy from the force…

Using these equations requires a constant force, so what if the force isn’t constant? Split them into sums… and an integral if needed. W=

How much work is required to move an object at rest? = = = = = = ½ m v 2

We know for an object that is in motion, that has kinetic energy. We can use part of the equation previously used to obtain the equation for KE KE = 2

Something that needs to be understood is that mechanical energy is not proportional to speed but rather speed squared Ex. Cars on a highway 40 mph 30 mph The relative speed would be 10 mph because they are going in the same direction So KE = ½ m (10) 2

What if the cars had a head on collision? 40 mph 30 mph The KE = ½ m (70) 2 What if a car hits a person going 60 mph? The KE = ½ m (60) 2 Kinetic energy is proportional to relative speed squared!

Another form of Energy: Potential (Gravitational) Energy mg x vertical = mgh So if an object is falling? The object is gaining Kinetic Energy and loosing potential energy Note: this is an example of transferring energy from one form to another… which will be the subject of chapter 8! == =