Section 8.8 Heapsort.  Merge sort time is O(n log n) but still requires, temporarily, n extra storage locations  Heapsort does not require any additional.

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Presentation transcript:

Section 8.8 Heapsort

 Merge sort time is O(n log n) but still requires, temporarily, n extra storage locations  Heapsort does not require any additional storage  As its name implies, heapsort uses a heap to store the array

First Version of a Heapsort Algorithm  When used as a priority queue, a heap maintains a smallest value at the top  The following algorithm  places an array's data into a heap,  then removes each heap item (O(n log n)) and moves it back into the array  This version of the algorithm requires n extra storage locations Heapsort Algorithm: First Version 1. Insert each value from the array to be sorted into a priority queue (heap). 2. Set i to 0 3. while the priority queue is not empty 4. Remove an item from the queue and insert it back into the array at position i 5. Increment i

Revising the Heapsort Algorithm  In heaps we've used so far, each parent node value was less than the values of its children  We can build a heap so that each parent node value is larger than its children  Then,  move the top item to the bottom of the heap  reheap, ignoring the item moved to the bottom

Trace of Heapsort Go to End

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Revising the Heapsort Algorithm  If we implement the heap as an array  each element removed will be placed at the end of the array, and  the heap part of the array decreases by one element Goto Initial Heap

Algorithm for In-Place Heapsort 1. Build a heap by rearranging the elements in an unsorted array 2. while the heap is not empty 3. Remove the first item from the heap by swapping it with the last item in the heap and restoring the heap property

Algorithm to Build a Heap  Start with an array table of length table.length  Consider the first item to be a heap of one item  Next, consider the general case where the items in array table from 0 through n-1 form a heap and the items from n through table.length – 1 are not in the heap

Algorithm to Build a Heap (cont.) Refinement of Step 1 for In-Place Heapsort 1.1 while n is less than table.length 1.2 Increment n by 1. This inserts a new item into the heap 1.3 Restore the heap property

Analysis of Heapsort  Because a heap is a complete binary tree, has log n levels  Building a heap of size n requires finding the correct location for an item in a heap with log n levels  Each insert (or remove) is O(log n)  With n items, building a heap is O(n log n)  No extra storage is needed

Code for Heapsort  Listing 8.7 ( HeapSort.java, pages )

Section 8.9 Quicksort

 Developed in 1962  Quicksort selects a specific value called a pivot and rearranges the array into two parts (called partioning)  all the elements in the left subarray are less than or equal to the pivot  all the elements in the right subarray are larger than the pivot  The pivot is placed between the two subarrays  The process is repeated until the array is sorted

Trace of Quicksort

Trace of Quicksort (cont.) Arbitrarily select the first element as the pivot

Trace of Quicksort (cont.) Swap the pivot with the element in the middle

Trace of Quicksort (cont.) Partition the elements so that all values less than or equal to the pivot are to the left, and all values greater than the pivot are to the right

Trace of Quicksort (cont.) Partition the elements so that all values less than or equal to the pivot are to the left, and all values greater than the pivot are to the right

Quicksort Example(cont.) is now in its correct position

Trace of Quicksort (cont.) Now apply quicksort recursively to the two subarrays

Trace of Quicksort (cont.) Pivot value = 12

Trace of Quicksort (cont.) Pivot value = 12

Trace of Quicksort (cont.) Pivot value = 33

Trace of Quicksort (cont.) Pivot value = 33

Trace of Quicksort (cont.) Pivot value = 33

Trace of Quicksort (cont.) Pivot value = 33 Left and right subarrays have single values; they are sorted

Trace of Quicksort (cont.) Pivot value = 33 Left and right subarrays have single values; they are sorted

Trace of Quicksort (cont.) Pivot value = 55

Trace of Quicksort (cont.) Pivot value =

Trace of Quicksort (cont.) Pivot value = 77

Trace of Quicksort (cont.) Pivot value = 77

Trace of Quicksort (cont.) Pivot value = 77

Trace of Quicksort (cont.) Left subarray has single value; it is sorted

Trace of Quicksort (cont.)

Algorithm for Quicksort  We describe how to do the partitioning later  The indexes first and last are the end points of the array being sorted  The index of the pivot after partitioning is pivIndex Algorithm for Quicksort 1. if first < last then 2. Partition the elements in the subarray first... last so that the pivot value is in its correct place (subscript pivIndex ) 3. Recursively apply quicksort to the subarray first... pivIndex Recursively apply quicksort to the subarray pivIndex last

Analysis of Quicksort  If the pivot value is a random value selected from the current subarray,  then statistically half of the items in the subarray will be less than the pivot and half will be greater  If both subarrays have the same number of elements (best case), there will be log n levels of recursion  At each recursion level, the partitioning process involves moving every element to its correct position—n moves  Quicksort is O(n log n), just like merge sort

Analysis of Quicksort (cont.)  The array split may not be the best case, i.e  An exact analysis is difficult (and beyond the scope of this class), but, the running time will be bound by a constant x n log n

Analysis of Quicksort (cont.)  A quicksort will give very poor behavior if, each time the array is partitioned, a subarray is empty.  In that case, the sort will be O(n 2 )  Under these circumstances, the overhead of recursive calls and the extra run-time stack storage required by these calls makes this version of quicksort a poor performer relative to the quadratic sorts  We’ll discuss a solution later

Code for Quicksort  Listing 8.8 ( QuickSort.java, pages )

Algorithm for Partitioning If the array is randomly ordered, it does not matter which element is the pivot. For simplicity we pick the element with subscript first

Trace of Partitioning (cont.) If the array is randomly ordered, it does not matter which element is the pivot. For simplicity we pick the element with subscript first

Trace of Partitioning (cont.) For visualization purposes, items less than or equal to the pivot will be colored blue; items greater than the pivot will be colored light purple

Trace of Partitioning (cont.) For visualization purposes, items less than or equal to the pivot will be colored light green; items greater than the pivot will be colored light red

Trace of Partitioning (cont.) Search for the first value at the left end of the array that is greater than the pivot value

Trace of Partitioning (cont.) Search for the first value at the left end of the array that is greater than the pivot value up

Trace of Partitioning (cont.) Then search for the first value at the right end of the array that is less than or equal to the pivot value updown

Trace of Partitioning (cont.) Exchange these values updown

Trace of Partitioning (cont.) Exchange these values

Trace of Partitioning (cont.) Repeat

Trace of Partitioning (cont.) Find first value at left end greater than pivot up

Trace of Partitioning (cont.) Find first value at right end less than or equal to pivot updown

Trace of Partitioning (cont.) Exchange

Trace of Partitioning (cont.) Repeat

Trace of Partitioning (cont.) Find first element at left end greater than pivot up

Trace of Partitioning (cont.) Find first element at right end less than or equal to pivot up down

Trace of Partitioning (cont.) Since down has "passed" up, do not exchange up down

Trace of Partitioning (cont.) Exchange the pivot value with the value at down up down

Trace of Partitioning (cont.) Exchange the pivot value with the value at down down

Trace of Partitioning (cont.) The pivot value is in the correct position; return the value of down and assign it to the pivot index pivIndex down

Algorithm for Partitioning

Code for partition

Code for partition (cont.)  Listing 8.9 ( QuickSort1, page 457)

Revised Partition Algorithm  Quicksort is O(n 2 ) when each split yields one empty subarray, which is the case when the array is presorted  A better solution is to pick the pivot value in a way that is less likely to lead to a bad split  Use three references: first, middle, last  Select the median of the these items as the pivot

Trace of Revised Partitioning

Trace of Revised Partitioning (cont.) middle first last

Trace of Revised Partitioning (cont.) Sort these values middle first last

Trace of Revised Partitioning (cont.) Sort these values middle first last

Trace of Revised Partitioning (cont.) Exchange middle with first middle first last

Trace of Revised Partitioning (cont.) Exchange middle with first middle first last

Trace of Revised Partitioning (cont.) Run the partition algorithm using the first element as the pivot

Algorithm for Revised partition Method 1. Sort table[first], table[middle], and table[last] 2. Move the median value to table[first] (the pivot value) by exchanging table[first] and table[middle]. 3. Initialize up to first and down to last 4. do 5. Increment up until up selects the first element greater than the pivot value or up has reached last 6. Decrement down until down selects the first element less than or equal to the pivot value or down has reached first 7. if up < down then 8. Exchange table[up] and table[down] 9. while up is to the left of down 10. Exchange table[first] and table[down] 11. Return the value of down to pivIndex

Code for Revised partition Method  Listing 8.10 ( QuickSort2, page 459)

Summary Comparison of Sort Algorithms

Sort Review