The Physics of Sliding on a Hill Min Woo Chung

How to Ride The Sled Balance : a rider is most stable if they sit like on the picture because Normal forces are always directed perpendicular to the surface and the gravity is always exist. Balance : a rider is most stable if they sit like on the picture because Normal forces are always directed perpendicular to the surface and the gravity is always exist.

Riding Sled on the Hill As shown in the diagram, there are always at least two forces acting upon any object that is positioned on an inclined plane which are the force of gravity and the normal force. As shown in the diagram, there are always at least two forces acting upon any object that is positioned on an inclined plane which are the force of gravity and the normal force.

Does the Sled related to Physics? The Sled is related to the physics because at point A, it has potential energy, between point A and B the point where speeds up, and point between B and C, it ends up with having kinetic energy. The Sled is related to the physics because at point A, it has potential energy, between point A and B the point where speeds up, and point between B and C, it ends up with having kinetic energy.

Kinetic Energy The Formula for Kinetic Energy is The Formula for Kinetic Energy is The bigger the mass the more kinetic energy an object has. The bigger the mass the more kinetic energy an object has. Velocity is squared so kinetic energy is more dependent on velocity than it is on mass. Velocity is squared so kinetic energy is more dependent on velocity than it is on mass.

Gravitational Potential Energy PE = mgy PE = mgy Since PE is dependent on height, it is important to indicate the starting or reference point for the measurement. Since PE is dependent on height, it is important to indicate the starting or reference point for the measurement.

When the Sled has greater speed? The greater the hill of the surface, the faster the speed which the object will slide down. In physics, Objects are known to accelerate down inclined planes because of an unbalanced force. The greater the hill of the surface, the faster the speed which the object will slide down. In physics, Objects are known to accelerate down inclined planes because of an unbalanced force.

Newton’s Second Law Newton's second law is the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Newton's second law is the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

If there is no friction, will the sled has same speed? If there is no friction or air resistance, the sled would continue in motion with the same speed and in the same direction. Forces do not cause motion; forces cause accelerations. If there is no friction or air resistance, the sled would continue in motion with the same speed and in the same direction. Forces do not cause motion; forces cause accelerations.

Which position is the fastest?

Data/Observation Leaning Forward: The fastest Leaning Forward: The fastest Leaning Backward: fast Leaning Backward: fast Sitting on the Slide: The slowest Sitting on the Slide: The slowest According to the video, we could know which position is the fastest when we slide down on a hill. According to the video, we could know which position is the fastest when we slide down on a hill.

Conclusion As the experiment of sliding, Leaning forward was the fastest by putting the weight in front and having less air resistance. As the experiment of sliding, Leaning forward was the fastest by putting the weight in front and having less air resistance.

Example of sliding on the hill A boy is sliding down a hill that is 2.75m high and 5.43m long. If the coefficient of friction between the sled and the road is 0.33, what is the sled’s speed at the bottom of the hill? A boy is sliding down a hill that is 2.75m high and 5.43m long. If the coefficient of friction between the sled and the road is 0.33, what is the sled’s speed at the bottom of the hill? Sol) PE – Wf = KE Sol) PE – Wf = KE Mgy – f △ x = 1/2mv^(2) mgy – un △ x = 1/2mv^(2) Mgy – umg △ x = 1/2mv^(2) 10*(2.75) – (0.33*10*5.43) = 1/2v^(2) 27.5 – 17.9 = 1/2v^(2) 19.2 = v^(2) V = 4.38m/s

Bibliography gy/hh.html gy/hh.html gy/hh.html gy/hh.html U3L3e.html U3L3e.html U3L3e.html U3L3e.html physics/chapter10section5.rhtml physics/chapter10section5.rhtml physics/chapter10section5.rhtml physics/chapter10section5.rhtml LASS/newtlaws/u2l3a.html LASS/newtlaws/u2l3a.html

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