Applications of Linear Systems (For help, go to Lesson 2-5.) 1.Two trains run on parallel tracks. The first train leaves a city hour before the second.

Slides:



Advertisements
Similar presentations
Solving Rational Equations and Inequalities
Advertisements

EXAMPLE 5 Write and solve an equation
Over Lesson 6–3. Splash Screen Solving Systems with Elimination Using Multiplication Lesson 6-4.
Algebra 7.3 Solving Linear Systems by Linear Combinations.
Lesson 3-9 Weighted Averages.
Solve an equation with variables on both sides
Section 7-4: Applications of Linear Systems
When solving an application that involves two unknowns, sometimes it is convenient to use a system of linear equations in two variables.
10-5 Adding and Subtracting Rational Expressions Warm Up Warm Up Lesson Presentation Lesson Presentation California Standards California StandardsPreview.
Examples and Guided Practice come from the Algebra 1 PowerPoint Presentations available at
Can I use elimination to solve this system of equations? 2x + y = 23 3x + 2y = 37.
5-5 Solving Rational Equations and inequalities.  Solve rational equations and inequalities.
Solve the linear system.
3.1 Solving Equations Algebra I.
Evaluating Algebraic Expressions 3-3Solving Multi-Step Equations What are the steps for solving multi-step equations? What are the steps for solving multi-step.
Chapter 7 7.4: Applications of Linear Systems. Metallurgy A metal worker has some ingots of metal alloy that are 20% copper and others that are 60% copper.
Solving Systems Using Elimination (For help, go to Lesson 7-2.) Solve each system using substitution. 1.y = 4x – 32.y + 5x = 4 3. y = –2x + 2 y = 2x +
Elimination Using Multiplication
Preview Warm Up California Standards Lesson Presentation.
Lesson 2-5 Warm-Up.
Section 7 – 1 Solving Systems by Graphing 2 or more linear equations make a system of linear equations The solution to a system of equations is the point.
Homework: Part I Add or subtract. Simplify your answer
When solving an application that involves two unknowns, sometimes it is convenient to use a system of linear equations in two variables.
Solving Linear Systems Using Linear Combinations There are two methods of solving a system of equations algebraically: Elimination (Linear Combinations)
Evaluating Algebraic Expressions 3-3Solving Multi-Step Equations Extension of AF4.1 Solve two-step linear equations in one variable over the rational numbers.
Solving Systems by Graphing
7-4 Applications of Linear Systems. # of Coins: 12 coins total, adding quarters and dimes together Q + D = 12 Value of Coins: Have $1.95 total Quarters.
Multi Step Equations Copied from =ie7&rls=com.microsoft:en-us:IE- Address&ie=&oe=#hl=en&tbo=d&rls=com.microsoft:en-us:IE-
Copyright © Cengage Learning. All rights reserved. Systems of Equations and Inequalities.
(For help, go to Lesson 1-1.) ALGEBRA 1 LESSON 4-8 Write a variable expression for each situation. 1.value in cents of q quarters 2.twice the length 3.number.
KAYAKING EXAMPLE 4 Write and solve a linear system During a kayaking trip, a kayaker travels 12 miles upstream (against the current) and 12 miles downstream.
7.4 Applying Linear Equations. 7.4 – Applying Equations Goals / “I can…”  Write systems of linear equations.
Lesson 6-4 Warm-Up.
Warm Up Simplify each expression. 1. 3(10a + 4) – (20 – t) + 8t 3. (8m + 2n) – (5m + 3n) 30a t 3m – n 4. y – 2x = 4 x + y = 7 Solve by.
Systems of Equations: Substitution
Use the substitution method
Solve Linear Systems by Substitution January 28, 2014 Pages
7.2 Two-Variable Linear Systems Elimination method.
Review Quiz. Pages mph Practice Problems 1.Carrie can row a boat at a rate of 5 miles per hour in calm water. How long will it take her to.
6-5 Applying Systems 9.0 Students solve a system of two linear equations in two variables algebraically and are able to interpret the answer graphically.
Section 7 – 4 Systems of Linear Equations (Word Problems) Objective: To write and solve systems of linear equations.
6-2 Solving Systems Using Substitution Hubarth Algebra.
Solving Rational Equations and Inequalities
Applications of Linear Systems Section 6-4. Goals Goal To choose the best method for solving a system of linear equations. Rubric Level 1 – Know the goals.
Holt Algebra Adding and Subtracting Rational Expressions Warm Up Add. Simplify your answer Subtract. Simplify your answer
Solving Application Problems Using System of Equations Section 4.3.
1. Solve the linear system using substitution.
Solve the linear system.
Solving Rational Equations and Inequalities
Solving Rational Equations and Inequalities
Solve the linear system.
Objective 2 Days The learner will solve real-life problems using equations (d=r*t)
Applications of Linear Systems
RATE PROBLEMS.
11.3 Solving Linear Systems by Adding or Subtracting
6-2 Solving Systems Using Substitution
Solving Multi-Step Inequalities
Solving Systems Using Substitution
Solving Systems Using Elimination
Adding and Subtracting Rational Expressions 12-5
Copyright © Cengage Learning. All rights reserved.
Warm Up Lesson Presentation Lesson Quiz
Welcome to Interactive Chalkboard
Equations and Problem Solving
Solving Multi-Step Equations
Warm Up Solve. 1. 3x = 102 = z – 100 = 21 w = 98.6 x = 34 y 15
RATE PROBLEMS.
College Algebra Chapter 5 Systems of Equations and Inequalities
A rational equation is an equation that contains one or more rational expressions. The time t in hours that it takes to travel d miles can be determined.
Presentation transcript:

Applications of Linear Systems (For help, go to Lesson 2-5.) 1.Two trains run on parallel tracks. The first train leaves a city hour before the second train. The first train travels at 55 mi/h. The second train travels at 65 mi/h. Find how long it takes for the second train to pass the first train. 2.Luis and Carl drive to the beach at an average speed of 50 mi/h. They return home on the same road at an average speed of 55 mi/h. The trip home takes 30 min. less. What is the distance from their home to the beach? 1212 ALGEBRA 1 LESSON

Applications of Linear Systems 1. 55t = 65(t – 0.5) 55t = 65t – = 10t 3.25 = t It takes 3.25 hours for the second train to pass the first train. 2.50t = 55(t – 0.5) 50t = 55t – = 5t 5.5 = t 50t = 50(5.5) = 275 It is 275 miles to the beach from their home. ALGEBRA 1 LESSON 9-3 Solutions 9-3

Define:Let a = volume of theLet b = volume of the 50% solution.25% solution. Relate:volume of solutionamount of acid Write: a + b = a b = 0.4(10) Applications of Linear Systems A chemist has one solution that is 50% acid. She has another solution that is 25% acid. How many liters of each type of acid solution should she combine to get 10 liters of a 40% acid solution? Step 1:Choose one of the equations and solve for a variable. a + b = 10Solve for a. a = 10 – bSubtract b from each side. ALGEBRA 1 LESSON

Applications of Linear Systems (continued) Step 2:Find b. 0.5a b = 0.4(10) 0.5(10 – b) b = 0.4(10)Substitute 10 – b for a. Use parentheses. 5 – 0.5b b = 0.4(10) Use the Distributive Property. 5 – 0.25b = 4 Simplify. –0.25b = –1 Subtract 5 from each side. b = 4 Divide each side by –0.25. Step 3:Find a. Substitute 4 for b in either equation. a + 4 = 10 a = 10 – 4 a = 6 To make 10 L of 40% acid solution, you need 6 L of 50% solution and 4 L of 25% solution. ALGEBRA 1 LESSON

Define:Let p = the number of pages. Let d = the amount of dollars of expenses or income. Relate:Expenses are per-pageIncome is price expenses plustimes pages typed. computer purchase. Write: d = 0.5 p d = 5.5 p Applications of Linear Systems Suppose you have a typing service. You buy a personal computer for $1750 on which to do your typing. You charge $5.50 per page for typing. Expenses are $.50 per page for ink, paper, electricity, and other expenses. How many pages must you type to break even? ALGEBRA 1 LESSON

Applications of Linear Systems (continued) Choose a method to solve this system. Use substitution since it is easy to substitute for d with these equations. d = 0.5p Start with one equation. 5.5p = 0.5p Substitute 5.5p for d. 5p = 1750Solve for p. p = 350 To break even, you must type 350 pages. ALGEBRA 1 LESSON

Define:Let A = the airspeed.Let W = the wind speed. Relate: with tail wind with head wind (rate)(time) = distance (A + W) (time) = distance (A + W) (time) = distance Write:(A + W)5.6 = 2800 (A + W)6.8 = 2800 Applications of Linear Systems Suppose it takes you 6.8 hours to fly about 2800 miles from Miami, Florida to Seattle, Washington. At the same time, your friend flies from Seattle to Miami. His plane travels with the same average airspeed, but this flight only takes 5.6 hours. Find the average airspeed of the planes. Find the average wind speed. ALGEBRA 1 LESSON

Applications of Linear Systems (continued) Solve by elimination. First divide to get the variables on the left side of each equation with coefficients of 1 or –1. (A + W)5.6 = 2800A + W = 500Divide each side by 5.6. (A – W)6.8 = 2800A – W 412Divide each side by 6.8. Step 1:Eliminate W. A + W = 500 A – W = 412Add the equations to eliminate W. 2A + 0 = 912 Step 2:Solve for A. A = 456Divide each side by 2. Step 3:Solve for W using either of the original equations. A + W = 500 Use the first equation W = 500 Substitute 456 for A. W = 44 Solve for W. The average airspeed of the planes is 456 mi/h. The average wind speed is 44 mi/h. ALGEBRA 1 LESSON

Applications of Linear Systems 1.One antifreeze solution is 10% alcohol. Another antifreeze solution is 18% alcohol. How many liters of each antifreeze solution should be combined to create 20 liters of antifreeze solution that is 15% alcohol? 2.A local band is planning to make a compact disk. It will cost $12,500 to record and produce a master copy, and an additional $2.50 to make each sale copy. If they plan to sell the final product for $7.50, how many disks must they sell to break even? 3.Suppose it takes you and a friend 3.2 hours to canoe 12 miles downstream (with the current). During the return trip, it takes you and your friend 4.8 hours to paddle upstream (against the current) to the original starting point. Find the average paddling speed in still water of you and your friend and the average speed of the current of the river. Round answers to the nearest tenth. 7.5 L of 10% solution; 12.5 L of 18% solution 2500 disks still water: 3.1 mi/h; current: 0.6 mi/h ALGEBRA 1 LESSON