Gauss’s Law PH 203 Professor Lee Carkner Lecture 5
A uniform electric field of magnitude 1 N/C is pointing in the positive y direction. If the cube has sides of 1 meter, what is the flux through sides A, B, C? A)1, 0, 1 B)0, 0, 1 C)1, 0, 0 D)0, 0, 0 E)1, 1, 1 A B C
Consider three Gaussian surfaces. Surface 1 encloses a charge of +q, surface 2 encloses a charge of –q and surface 3 encloses both charges. Rank the 3 surfaces according to the flux, greatest first. A)1, 2, 3 B)1, 3, 2 C)2, 1, 3 D)2, 3, 1 E)3, 2, 1 +q-q 1 2 3
Rank the following Gaussian surfaces by the amount of flux that passes through them, greatest first (q is at the center of each). A)1, 2, 3 B)1, 3, 2 C)2, 1, 3 D)3, 2, 1 E)All tie qq 1 2 q 3
Rank the following Gaussian surfaces by the strength of the field at the surface at the point direction below q (where the numbers are). A)1, 2, 3 B)1, 3, 2 C)2, 1, 3 D)3, 2, 1 E)All tie qq 1 2 q 3
Gauss F = q/ 0 But the flux is related to the field through ∫EdA =q/ 0 What surfaces will work?
Cylinder We can capture the flux with a cylindrical Gaussian surface What is ∫EdA ? E constant everywhere total charge is h E = / (2 0 r) Can sometimes use this to approximate a long thin charge distribution
Plane We can again capture the flux with a cylindrical Gaussian surface What is ∫EdA ? E constant everywhere total charge is A E = /2 0 Useful for large sheet or point close to sheet
Spherical Shell For a point charge surrounded by a sphere we found E = (1/4 0 )(q/r 2 ) Remember, only total q enclosed counts What if we put the surface inside the charge? E = 0
Surface within Sphere What if we have total charge q, uniformly distributed with a radius R? What if surface is inside R? If we apply r 3 /R 3 to the point charge formula we get, E = (q/4 0 R 3 )r
Van De Graaff Generator The positively charged belt attracts the electrons in the dome making it positively charged Belt moves electrons to a ground connection where they are dumped Charge builds up until it is discharged through the air
Van De Graaff Why does your hair stand up when you touch the Van De Graaff generator? Why do you need to stand on the box?
Conductors and Charge The charges in the conductor are free to move and so will react to each other Charge distributes itself over the surface of a conductor No charge inside conductor
Charge Distribution How does charge distribute itself over a surface? e.g., a sphere No component parallel to surface, or else the charges would move For a non-uniform surface, charge accumulates at points
Conductors and External What if an external field is applied to a conductor? A charge placed in the middle would feel a force from these charges equal and opposite to the external force, thus, The field inside the conductor is zero The charges in the conductor cancel out the external field
Conducting Ring Charges Pushed To Surface No E Field Inside Field Lines Perpendicular to Surface
Faraday Cage If we make the conductor hollow we can sit inside it an be unaffected by external fields Your car is a Faraday cage and is thus a good place to be in a thunderstorm
Next Time Read Problems: Ch 23, P: 24, 36, 45, Ch 24, P: 2, 4