Sex-Linked Punnett
Karyotype A photograph of a cell’s chromosomes arranged in pairs according to size
Normal Karyotype: 23 pairs of chromosomes pairs 1-22 are autosomes pair 23 are sex chromosomes 24-5
Sex Chromosomes X Y
X chromosome has over 1,000 genes most genes on the X chromosome do not have corresponding alleles on the Y chromosome Y chromosome has only a few dozen genes some genes are unique only to the Y chromosome
Sex-Linked Traits Those traits whose genes are found on the X chromosome but NOT on the Y chromosome
Examples of Sex-linked Traits: Red-green colorblindness Male Pattern Baldness Hemophilia (Queen Victoria was a carrier) Duchenne Muscular Dystrophy (fatal)
Color Blindness “tests”
The test to the left is simpler. The individual with normal color vision will see a 5 revealed in the dot pattern. An individual with Red/Green (the most common) color blindness will see a 2 revealed in the dots.The test to the left is simpler. The individual with normal color vision will see a 5 revealed in the dot pattern. An individual with Red/Green (the most common) color blindness will see a 2 revealed in the dots. The test below is simpler. The individual with normal color vision will see a 5 revealed in the dot pattern. An individual with Red/Green (the most common) color blindness will see a 2 revealed in the dots.
Females = XX –carry 2 alleles for a sex-linked trait Males = XY – only carry 1 allele for a sex-linked trait, so it is easier for them to get sex-linked diseases
Sex-Linked Traits, cont. Males receive sex-linked traits from their mother because their mother gives them the X chromosome and their father gives them the Y chromosome
Example of Sex-Linked Trait H = Normal blood clotting h = Hemophilia GenotypesPhenotypes HHNormal HhNormal/Carrier hhHemophilia
Example of Sex-Linked Trait Normal male: Male with Hemophilia: Normal female (not a carrier for hemophilia – homozygous): Normal female (carrier for hemophilia – heterozygous): Female with Hemophilia: XHYXHY XhYXhY XHXHXHXH XhXhXhXh XHXhXHXh
Sample Problems
1. X H X h x X H Y Chances of: a. hemophiliac child? b. hemophiliac son? c. hemophiliac daughter? d. daughter who is carrier? XHXHXHXH XHYXHY XhYXhY XHXhXHXh XHYXHY X H X h ¼ or 25% ½ or 50% 0% ½ or 50%
2. A woman who is a carrier for hemophilia marries a hemophiliac man. Chances of: a. hemophiliac child? b. hemophiliac son? c. hemophiliac daughter? XHXhXHXh XHYXHY XhYXhY XhXhXhXh XhYXhY X H X h 2/4 or 50% ½ or 50% X H X h x X h Y
3. A normal man marries a Homozygous normal woman. Chances of: a. Will any of their kids be hemophiliacs? XHXHXHXH XHYXHY XHYXHY XHXHXHXH XHYXHY X H X H 0/4 or 0% X H X H x X H Y
A normal woman (whose father is a hemophiliac) marries a hemophiliac man. What are their genotypes? XHX?XHX? XhYXhY Her dad - X h Y X H X h and X h Y