Midterm Statistics. CMPE12cGabriel Hugh Elkaim 2 Begging for Points DO approach if we’ve made a mistake adding up points on your test. DO approach is.

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Presentation transcript:

Midterm Statistics

CMPE12cGabriel Hugh Elkaim 2 Begging for Points DO approach if we’ve made a mistake adding up points on your test. DO approach is we’ve marked something wrong that was actually right DO NOT approach if you don’t like the amount of partial credit you got. DO NOT approach if you don’t like your grade.

CMPE12cGabriel Hugh Elkaim 3 Overall Performance

CMPE12cGabriel Hugh Elkaim 4 Statistics High: 103, Low: 33 Mean: Median: Standard Deviation: Grade Distribution –14 A’s (A-, A, A+) –20 B’s (B-, B, B+) –18 C’s (C-, C, C+) –7 below C

CMPE12cGabriel Hugh Elkaim 5 Grading Cutoff’s ≥ 97  A+ ≥ 87  A ≥ 80  A- ≥ 75  B+ ≥ 70  B ≥ 65  B- ≥ 60  C+ ≥ 55  C ≥ 50  C- ≥ 47  D+ ≥ 45  D ≥ 35  D-

CMPE12cGabriel Hugh Elkaim 6 (9 points) Given a 4 x 8 array in memory, mat  i, with a base address of 0x120, answer the following questions: The elements are words, and mat  i is stored in ROW-MAJOR form, what is the address of mat  i[2][0]?

CMPE12cGabriel Hugh Elkaim 7 The elements are bytes and mat  i is stored in ROW-MAJOR form, what is the address of mat  i[2][6]? The elements are words and mat  i is stored in COLUMN-MAJOR form, what is the address of mat  i [3][4]?

CMPE12cGabriel Hugh Elkaim 8 Question #8.data n:.word3 m:.word8 foo:.byte 0x11:12 bar:.word0: B 4C 4F B 5C 5F B 6C 6F

CMPE12cGabriel Hugh Elkaim B 4C 4F B 5C 5F B 6C 6F $t0 $t1 $t2 $t3 $t4

CMPE12cGabriel Hugh Elkaim 10 Negabinary = ? 10

CMPE12cGabriel Hugh Elkaim 11 Negabinary (con’t) = ? -2

CMPE12cGabriel Hugh Elkaim 12 Alien Countdown

CMPE12cGabriel Hugh Elkaim 13

CMPE12cGabriel Hugh Elkaim 14 Questions?