The mean molecular mass of Titan’s atmosphere an in situ measurement from Huygens without using the mass spectrometer proof of concept for a useful technique.

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Presentation transcript:

The mean molecular mass of Titan’s atmosphere an in situ measurement from Huygens without using the mass spectrometer proof of concept for a useful technique Paul Withers Boston University Center for Space Physics Journal Club Monday

Previous Journal Club Talks 2004 September – Mars magnetic field/ionosphere 2005 October – Solar flare effects on ionospheres of Mars and Earth 2006 March – Space physics at Mars 2006 October – Aerobraking at Mars Mars, Mars, Mars, Mars, Mars, Mars, Mars

Science Questions Mean molecular mass (  ) -> Chemical composition How did Titan form? Current reservoirs of volatiles Ethane/methane puddles/ocean Thermal structure of atmosphere

Motivation Determination of atmospheric composition was a major Huygens goal – N 2 / CH 4 Huygens carried six instruments (GCMS, ACP, DISR, SSP, HASI, DWE) –Instruments to determine  were massive, expensive, delicate, etc –T/p sensors are simple, cheap, reliable Is it possible to know  based on simple measurements only?

Method Know p(t), T(t), z(t=0) –NOT  (t) Want z(t), p(z), T(z) p =  k T /  (ideal gas law) dp / dz = -  g (hydrostatic equilibrium) Need one more piece of information if  is not known(Paul, explain the usual technique) 05/05/eurospace/image/sequence.jpg Start at parachute deployment End at surface impact

Terminal Velocity mg =  A v 2 C / 2(drag equation) v = dz / dt(velocity - vertical) Rearranging… Anyway, use these to get z(t) and v(t) Then get  (z) from hydrostatic equation and  (z) from ideal gas law

Nasty Problem – And Its Solution C = ? Wind tunnels and numerical modelling made preflight predictions for C~0.5 Select C, find z impact, did impact occur at known surface, R = 2575 km? –If yes, C good; if not, C bad C = 0.65 (consistent with other analyses of the flight data) –C=0.66 has impact at z = +1.4 km –C=0.65 has impact at z = -0.2 km –C=0.64 has impact at z = -2.0 km

N 2 = 28 CH 4 = 16 My mean value differs from that of GCMS by 2% Huygens GCMS found:  = 27.9 (low t, hi z)1.41% CH 4  = 27.4 (hi t, low z)4.90% CH 4 Mean value in this work is  = % CH 4 Parachute opens 100 km, 70 m/s Impact on surface

So what? Huygens GCMS worked H / He ratio in giant planets uncertain by few percent CO 2 / N 2 ratio in Venus is uncertain by at least one percent CH 4 / N 2 ratio on Titan could vary in space and time Predictions of C must improve, need accuracies of 1%.The End