Stirling Refrigeration ME 498 - Senior Laboratory November 16, 2004 Nicholas Taylor.

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Presentation transcript:

Stirling Refrigeration ME Senior Laboratory November 16, 2004 Nicholas Taylor

Overview Background and theory of the Stirling Cooler Experimental Set-up and Procedure Results

Objectives Operate Global Cooling Model 100B Stirling Cooler Use thermodynamic principles to analyze the performance Calculate COP, Q rejected, Q lifted

Background Model 100B free piston Stirling Cooler High conversion between mechanical and thermal energy AC linear motor drives the piston Working gas – helium

Background

Theory Coefficient of Performance

Theory Finding Q rejected

Experimental Apparatus

Procedure Measure flow rate Prepare data acquisition system Increase voltage to the stirling cooler, to begin cooling Record data until the temperature reaches -30°C, activate the heater and reach equilibrium at -20°C Turn off equipment

Results Temperature vs. Time COP R for 5°C, 0°C, -10°C, and -23°C Compare COP found to COP from Global Cooling COP R, W stirling, and Q rejected at equilibrium Compare COP at equilibrium with COP carnot Uncertainty Analysis

Results

Global Cooling TempTimeCpmdT/dtQliftedWstirlingCOPInputCOP% diff. (deg C)(sec)(J/kJ*C)kg (W)

Results Equilibrium Test Qreject Qlifted Wstirling COP0.607 COP carn % difference78.398

Uncertainty Uncertainty of COP Uncertainty of Q lifted Uncertainty of Q rejected Uncertainty of Vdot

Uncertainty % ωCOP = 1.2% ωQ rejected = 4.61 (32.318) ωVdot = 2.85E-8 ωQ lifted = 0.11 (12.204) ωCOP = 6.18E-3 (.607)

Uncertainty Qlifted ComponentValueUncertainty V I ComponentQliftedn(n+dn)Qlifted(n+dn)dQlifted/dn V I ωQlifted0.11

Conclusions Learned a practical use of a Stirling Cooler Found COP, Q rejected, and Q lifted Found the uncertainty in measurements Recommend comparing to a traditional refrigeration cycle

References