1. 2 Exam 1Sentential LogicTranslations (+) Exam 2Sentential LogicDerivations Exam 3Predicate LogicTranslations Exam 4Predicate LogicDerivations 6

Slides:



Advertisements
Similar presentations
f(x) = x 2 f(x) = 2x 2 Parameter ‘a’ increases from 1 to 2 Parabola stretches vertically.
Advertisements

Increasing/Decreasing
1. 2 Exam 1:Sentential LogicTranslations (+) Exam 2:Sentential LogicDerivations Exam 3:Predicate LogicTranslations Exam 4:Predicate LogicDerivations Exam.
Exam 1:Sentential LogicTranslations (+) Exam 2:Sentential LogicDerivations Exam 3:Predicate LogicTranslations Exam 4:Predicate LogicDerivations.
1. 2 Exam 1Sentential LogicTranslations (+) Exam 2Sentential LogicDerivations Exam 3Predicate LogicTranslations Exam 4Predicate LogicDerivations 6
Exam 1:Sentential LogicTranslations (+) Exam 2:Sentential LogicDerivations Exam 3:Predicate LogicTranslations Exam 4:Predicate LogicDerivations.
Hx xx x is happythere is some x : who is happythere is someone is happysomeone.
For Wednesday, read chapter 6, section 1. As nongraded HW, do the problems on p Graded Homework #7 is due on Friday at the beginning of class. In.
1. 2  6 argument forms, 15 points each, plus 10 free points  Symbolic argument forms (no translations)  For each one, you will be asked to construct.
Predicate Logic (PL) 1.Syntax: The language of PL Formula VS. Sentence Symbolize A-, E, I-, and O-sentences 2.Semantic: a sentence compare two sentences.
derivations in Predicate Logic 15 points each, plus 10 free points 1.universal derivation[Exercise Set C] 2.existential-out[Exercise Set D] 3.negation.
1. 2 Exam 1Sentential LogicTranslations (+) Exam 2Sentential LogicDerivations Exam 3Predicate LogicTranslations Exam 4Predicate LogicDerivations 6
Lesson 5.2 (PART 2) FUNCTION NOTATION.
1. 2 Day 14 Day 13 Day 12 Day 11 Day 10 Day 09 Introductory Material EXAM #2 show: conjunction Indirect Derivation show: atomic show: disjunction Conditional.
1 Example 1 Explain why the Intermediate Value Theorem does or does not apply to each of the following functions. (a) f(x) = 1/x with domain [1,2]. Solution.
Lesson 4 – 3 Function Rules, Tables and Graphs
Antiderivatives Definition A function F(x) is called an antiderivative of f(x) if F ′(x) = f (x). Examples: What’s the antiderivative of f(x) = 1/x ?
LIMITS INVOLVING INFINITY Mrs. Erickson Limits Involving Infinity Definition: y = b is a horizontal asymptote if either lim f(x) = b or lim f(x) = b.
Limit Laws Suppose that c is a constant and the limits lim f(x) and lim g(x) exist. Then x -> a Calculating Limits Using the Limit Laws.
Exponential Functions
Graphing Techniques: Transformations
Universal Introduction and Quantifier Exchange Rules.
More Review for Test I. Calculation of Limits Continuity Analytic Definition: the function f is continuous at x = a if When you can calculate limits.
Bellwork: Graph each line: 1. 3x – y = 6 2. Y = -1/2 x + 3 Y = -2
Math 1304 Calculus I 3.1 – Rules for the Derivative.
3.4 - The Chain Rule. The Chain Rule: Defined If f and g are both differentiable and F = f ◦ g is the composite function defined by F(x) = f(g(x)), then.
Objectives: 1.Be able to find the derivative of functions by applying the Product Rule. Critical Vocabulary: Derivative, Tangent Daily Warm-Up: Find the.
The Product Rule for Differentiation. If you had to differentiate f(x) = (3x + 2)(x – 1), how would you start?
Section 3.3 The Product and Quotient Rule. Consider the function –What is its derivative? –What if we rewrite it as a product –Now what is the derivative?
1 Solve each: 1. 5x – 7 > 8x |x – 5| < 2 3. x 2 – 9 > 0 :
2.5 Derivatives of Polynomials 1 The four-step process has been introduced to found derivatives. In the present and the next lecture, using this process,
x 3x f(x) = 3x 1. Addition 2. Subtraction 3. Multiplication 4. Division.
The Chain Rule Composite Functions When a function is composed of an inner function and an outer function, it is called a “composite function” When a.
Solving Polynomials.
3.7.  Equations that represent functions are often written in function notation.  f(x) is used in place of y in function notation.  y = mx + b becomes.
The Product and Quotient Rules for Differentiation.
DEFINITION A function f : A  B is onto B (called a surjection) iff Rng(f) = B. We write f : A  B to indicate that f is a surjection. Look at the illustration.
Basic Graphs  Let’s examine the graphs of some common and basic functions Knowing the graphical representation.
Algebra of Functions Let f and g be functions with domains D and E respectively. Define new functions from D E -> R by (f+g)(x) = f(x) + g(x) (f-g)(x)
Calculus Section 3.1 Calculate the derivative of a function using the limit definition Recall: The slope of a line is given by the formula m = y 2 – y.
If f(x) = g(x)∙ h(x) then f’(x) = g’(x)∙h(x) + g(x)∙h’(x)
Section 3.3 The Product and Quotient Rule
Calculus Section 3.6 Use the Chain Rule to differentiate functions
Warm up f(x) = 3x + 5, g(x) = x – 15, h(x) = 5x, k(x) = -9
Testing simple quantification schemas for satisfiability
4.1 Notes day 2 Remainder Theorem: If a polynomial f(x) is divided by x – c, then the remainder is f(c). Ex. f(x) = x3 + 3 divided by g(x)= x -1.
§4.9 Antiderivatives There are two branches in calculus:
3.11: Derivatives of Inverse Functions
Daily Warm-Up: Find the derivative of the following functions
Part (a) 1 1 ax ax ax 2 g(x) = e + f(x) g’(x) = e (ln e) (a) + f’(x)
3.1 – Rules for the Derivative
Combinations of Functions:
Partner Whiteboard Review.
3-2 Representing Functions
Function Notation and Evaluating Functions
Warm up f(x) = 3x + 5, g(x) = x – 15, h(x) = 5x, k(x) = -9
32 – Applications of the Derivative No Calculator
Properties of Functions
Universal Elimination
1.2 Analyzing Graphs of Functions and Relations
6-1: Operations on Functions (+ – x ÷)
Function Notation. Function Notation What is function notation? Function notation is another way to write “y=“ The notation looks like this: f(x) f(x)
FUNCTION NOTATION.
Perform the indicated operation.
Find the derivative of the following function:   {image} .
Functions MATHPOWERTM 11, WESTERN EDITION
1. Evaluating Expressions and Functions
Function Notation. Function Notation What is function notation? Function notation is another way to write “y=“ The notation looks like this: f(x) f(x)
Replace inside with “x” of other function
Function Notation. Function Notation What is function notation? Function notation is another way to write “y=“ The notation looks like this: f(x) f(x)
Presentation transcript:

1

2 Exam 1Sentential LogicTranslations (+) Exam 2Sentential LogicDerivations Exam 3Predicate LogicTranslations Exam 4Predicate LogicDerivations 6 15 points+ 10 free points Exam 5very similar to Exam 3 Exam 6very similar to Exam 4 Exam 1Sentential LogicTranslations (+) Exam 2Sentential LogicDerivations Exam 3Predicate LogicTranslations Exam 4Predicate LogicDerivations 6 15 points+ 10 free points Exam 5very similar to Exam 3 Exam 6very similar to Exam 4

3 OO Tilde-Universal-Out OO Universal-Out UDUniversal Derivation OO Tilde-Existential-Out OO Existential-Out II Existential-In today day 1 day 2 today day 2 day 1

4 OLD name       –––––     OLD name     –––––       a name counts as OLD precisely if it occurs somewhere unboxed and uncancelled OO II

5 NEW name       –––––    NEW name  :        :    a name counts as NEW precisely if it occurs nowhere unboxed or uncancelled OO UD

6 OO Tilde-Universal Out OO Tilde-Existential-Out

7  is any variable  is any (official) formula not everyone is H –––––––––––––– someone is not H   xHx ––––––  x  Hx     ––––––     example

8  is any variable  is any (official) formula no one is H –––––––––––––– everyone is un H   xHx ––––––  x  Hx     ––––––     example = not anyone is H

9 ; (  &  ) –––––––––    ; (    ) –––––––––  &  &O&O OO

10 (6) (5) (4) (3) (2) (1) not every F is H / some F is un-H 5,  x(Fx &  Hx) 4, Fa &  Ha 3,  (Fa  Ha) 1,  x  (Fx  Hx) DD  :  x(Fx &  Hx) Pr   x(Fx  Hx) II OO OO OO

11 every F is G ; no G is H / no F is H (12) (13) (14) (10) (11) (15) (9) (8) (7) (6) (5) (4) (3) (2) (1) 8,10, Ga 9,9, Ga   Ha 12,13,  Ha 7, Fa Ha 11,14,  6,6,  (Ga & Ha) 1,1, Fa  Ga 4, Fa & Ha 2,  x  (Gx & Hx) DD  :  As  x(Fx & Hx) DD  :   x(Fx & Hx) Pr   x(Gx & Hx) Pr  x(Fx  Gx) OO  &O OO &O II OO OO OO OO

12  :        :  ° °  DD DD  is any (official) formula  is any variable As  D is a species of ID

13 (13) (12) (10) (11) (14) (9) (8) (7) (6) (5) (4) (3) (2) (1) 10,11,  Ha  Ha 8, Fa   Ha 9, Fa 12,13,  7, Fa &  Ha 6,6,  (Fa &  Ha) 5,5,  (Fa  Ha) 3,  x  (Fx &  Hx) 1,  x  (Fx  Hx) DD  :  As   x(Fx &  Hx)  D (ID)  :  x(Fx &  Hx) Pr   x(Fx  Hx) OO  &O &O II OO OO OO OO OO

14 (12) (13) (14) (10) (11) (15) (9) (8) (7) (6) (5) (4) (3) (2) (1) 8,8,  (Ga & Ha) 12, Ga   Ha 11,13,  Ha 4,4, Ha 7,9,7,9, Ga 10,14,  Fa 6,6,  x  (Gx & Hx) 1,1, Fa  Ga 2,2, Fa & Ha DD  :  As   x(Gx & Hx)  D (ID)  :  x(Gx & Hx) Pr  x(Fx & Hx) Pr  x(Fx  Gx) OO  &O OO  O OO II &O OO OO

15 (5) (10) (9) (8) (7) (6) (4) (3) (2) (1) 1, Fa  Ga 9,  x(Gx & Hx) 7,8, Ga & Ha 5,6, Ga Ha 4, Fa 2, Fa & Ha DD (…  I)  :  x(Gx & Hx) Pr  x(Fx & Hx) Pr  x(Fx  Gx) OO II &I&I OO &O OO

16 (8) (10) (11) (12) (9) (7) (6) (5) (4) (3) (2) (1) if anyone is F, then everyone is unH / if someone is F, then no one is H 1, Fa   y  Hy 7,8,  y  Hy 10,  Hb 9,11,  5, Hb 3, Fa DD  :  As  yHy DD  :   yHy As  xFx CD  :  xFx    yHy Pr  x(Fx   y  Hy) OO OO OO II OO OO

17 (10) (11) (12) (9) (8) (7) (6) (5) (4) (3) (2) (1) if someone is F, then someone is unH / if anyone is F, then not-everyone is H 9,  Hb 6, Hb 10,11  1,8,  y  Hy 4,  xFx DD  :  As  yHy ID  :   yHy As Fa CD  : Fa    yHy UD  :  x(Fx    yHy) Pr  xFx   y  Hy OO OO OO OO II

18