Dilutions and Concentrations A true story Standards Science: Chemistry 6.d. Students know how to calculate the concentration of a solution. Investigation.

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Presentation transcript:

Dilutions and Concentrations A true story

Standards Science: Chemistry 6.d. Students know how to calculate the concentration of a solution. Investigation and Experimentation 1a. Select and use appropriate tools and technology to perform tests, collectdata, analyze relationships, and display data. Math: Algebra I 15.0 Students apply algebraic techniques to solve rate problems, work problems and percent mixture problems.

Prior Knowledge The students are expected to already know the following: 1. How to use a micropipette. 2. Units of measurement. 3. Manipulating Algebraic Equations

Learning Goal Understand how to dilute different given concentrations (in %) to achieve a desired working concentration.

Learning Objective Students will be able to calculate and prepare a dilution using the concentration equation.

Think-Pair-Share Compare and Contrast the 2 samples.

Needed Definitions Concentration: The amount of a substance in a given volume.

Needed Definitions Dilution: The process of reducing the concentration.

Needed Definitions Stock Solution: A higher concentration solution that will be changed to a lower concentration by dilution. Stock (initial concentration) Stock (initial concentration) Dilution (final concentration) Dilution (final concentration)

Concentration Equation Initial Concentration (C i ) x Initial Volume (V i ) equals Final Concentration (C f )x Final Volume (V f ) C i x V i = C f x V f C i x V i = C f x V f (Initial) (Final) (Initial) (Final)

EXAMPLE: 6% Loading Dye is a stock solution. If the final volume of a solution is 12 μ l calculate the amount of 6% Loading Dye and water you would use to dilute the Loading Dye to 1%. 1% Dye 6% Dye C i = 6% 6% Loading Dye is a stock solution. If the final volume of a solution is 12 μ l calculate the amount of 6% Loading Dye and water you would use to dilute the Loading Dye to 1%. V f = 12 μ l V i = X C f = 1% C i x V i = C f x V f 6% x V i = 1% x 12 μ l V i = 2 μ l dye

V f -V i = amount of water to add V f = 12 μ l V i = 2 μ l dye 12 μ l – 2 μ l dye = 10 μ l water 12 μ l – 2 μ l dye = 10 μ l water

Clicker Question A stock solution of 50% TAE buffer has to be diluted. You need 100 ml of 1% TAE. Calculate how much 50% TAE has to be used. 1) 100 ml2) 10 ml 3) 20 ml4) 2 ml

Activity As a pair… Tube1: Make 1,000 μ l of a 1.3% solution from your 100% stock “A”. Tube 2: Make 1,000 μ l of a 42% solution from your 100% stock “A”. Show your work on the back of the card Raise your hand when you have finished your 2 “A” samples so the instructor can check your work.

Assessment. Work on your own. Tube 3: Make 1000 μ l of a 1% solution from your 40% Stock “B”. Raise your hand when you have finished your “B” sample so the instructor can check your work.

Did you meet the learning objectives? Were you able to calculate dilutions using the concentration equation? C i x V i = C f x V f C i x V i = C f x V f Were you able to prepare dilutions using your calculations? Were you able to prepare dilutions using your calculations?