EECC550 - Shaaban #1 Lec # 5 Winter CPU Design Steps 1. Analyze instruction set operations using independent RTN => datapath requirements. 2. Select required datapath components & establish clock methodology. 3. Assemble datapath meeting the requirements. 4. Analyze implementation of each instruction to determine setting of control points that effects the register transfer. 5. Assemble the control logic.

EECC550 - Shaaban #2 Lec # 5 Winter Single Cycle MIPS Datapath: CPI = 1, Long Clock Cycle

EECC550 - Shaaban #3 Lec # 5 Winter Drawbacks of Single-Cycle Processor Long cycle time. All instructions must take as much time as the slowest: –Cycle time for load is longer than needed for all other instructions. Real memory is not as well-behaved as idealized memory –Cannot always complete data access in one (short) cycle. Cannot pipeline (overlap) the processing of one instruction with the previous instructions.

EECC550 - Shaaban #4 Lec # 5 Winter Abstract View of Single Cycle CPU PC Next PC Register Fetch ALU Reg. Wrt Mem Access Data Mem Instruction Fetch Result Store ALUctr RegDst ALUSrc ExtOp MemWr Equal nPC_sel RegWr MemWr MemRd Main Control ALU control op fun Ext

EECC550 - Shaaban #5 Lec # 5 Winter Single Cycle Instruction Timing PCInst Memory mux ALUData Mem mux PCReg FileInst Memory mux ALU mux PCInst Memory mux ALUData Mem PCInst Memorycmp mux Reg File Arithmetic & Logical Load Store Branch Critical Path setup

EECC550 - Shaaban #6 Lec # 5 Winter Reducing Cycle Time: Multi-Cycle Design Cut combinational dependency graph by inserting registers / latches. The same work is done in two or more fast cycles, rather than one slow cycle. storage element Acyclic Combinational Logic storage element Acyclic Combinational Logic (A) storage element Acyclic Combinational Logic (B) =>

EECC550 - Shaaban #7 Lec # 5 Winter Clock Cycle Time & Critical Path Critical path: the slowest path between any two storage devices Cycle time is a function of the critical path must be greater than: –Clock-to-Q + Longest Path through the Combination Logic + Setup Clk

EECC550 - Shaaban #8 Lec # 5 Winter Instruction Processing Cycles Obtain instruction from program storage Determine instruction type Obtain operands from registers Compute result value or status Store result in register/memory if needed (usually called Write Back). Update program counter to address of next instruction } Common steps for all instructions Instruction Fetch Instruction Decode Execute Result Store Next Instruction

EECC550 - Shaaban #9 Lec # 5 Winter Partitioning The Single Cycle Datapath Add registers between smallest steps PC Next PC Operand Fetch Exec Reg. File Mem Access Data Mem Instruction Fetch Result Store ALUctr RegDst ALUSrc ExtOp MemWr nPC_sel RegWr MemWr MemRd

EECC550 - Shaaban #10 Lec # 5 Winter Example Multi-cycle Datapath PC Next PC Operand Fetch Ext ALU Reg. File Mem Acces s Data Mem Instruction Fetch Result Store ALUctr RegDst ALUSrc ExtOp nPC_sel RegWr MemWr MemRd IR A B R M Reg File MemToReg Equal Registers added: IR: Instruction register A, B: Two registers to hold operands read from register file. R: or ALUOut, holds the output of the ALU M: or Memory data register (MDR) to hold data read from data memory

EECC550 - Shaaban #11 Lec # 5 Winter Operations In Each Cycle Instruction Fetch Instruction Decode Execution Memory Write Back R-Type IR  Mem[PC] A  R[rs] B  R[rt] R  A + B R[rd]  R PC  PC + 4 Logic Immediate IR  Mem[PC] A  R[rs] R  A OR ZeroExt[imm16] R[rt]  R PC  PC + 4 Load IR  Mem[PC] A  R[rs] R  A + SignEx(Im16) M  Mem[R] R[rd]  M PC  PC + 4 Store IR  Mem[PC] A  R[rs] B  R[rt] R  A + SignEx(Im16) Mem[R]  B PC  PC + 4 Branch IR  Mem[PC] A  R[rs] B  R[rt] If Equal = 1 PC  PC (SignExt(imm16) x4) else PC  PC + 4 IF ID EX MEM WB

EECC550 - Shaaban #12 Lec # 5 Winter MIPS Multi-Cycle Datapath: Five Cycles of Load Cycle 1Cycle 2Cycle 3Cycle 4Cycle 5 IF IDEXMEMWBLoad 1- Instruction Fetch (IF) Instruction Fetch Fetch the instruction from the Instruction Memory. 2- Instruction Decode (ID): Registers Fetch and Instruction Decode. 3- Execute (EX): Calculate the effective memory address. 4- Memory (MEM): Read the data from the Data Memory. 5- Write Back (WB): Write the data back to the register file. Update PC.

EECC550 - Shaaban #13 Lec # 5 Winter Multi-cycle Datapath Instruction CPI R-Type/Immediate: Require four cycles, CPI =4 – IF, ID, EX, WB Loads: Require five cycles, CPI = 5 – IF, ID, EX, MEM, WB Stores: Require four cycles, CPI = 4 –IF, ID, EX, MEM Branches: Require three cycles, CPI = 3 – IF, ID, EX Average program 3  CPI  5 depending on program profile (instruction mix).

EECC550 - Shaaban #14 Lec # 5 Winter Single Cycle Vs. Multi-Cycle CPU Single-Cycle CPU: CPI = 1 C = 8ns One million instructions take = I x CPI x C = 10 6 x 1 x 8x10 -9 = 8 msec Multi-Cycle CPU: CPI = 3 to 5 C = 2ns One million instructions take from 10 6 x 3 x 2x10 -9 = 6 msec to 10 6 x 5 x 2x10 -9 = 10 msec depending on instruction mix used.

EECC550 - Shaaban #15 Lec # 5 Winter Finite State Machine (FSM) Control Model State specifies control points for Register Transfer. Transfer occurs upon exiting state (same falling edge). State X Register Transfer Control Points Depends on Input Control State Next State Logic Output Logic inputs (conditions) outputs (control points)

EECC550 - Shaaban #16 Lec # 5 Winter Control Specification For Multi-cycle CPU Finite State Machine (FSM) IR   MEM[PC] R-type A  R[rs] B  R[rt] R  A fun B R[rd]  R PC  PC + 4 R  A or ZX R[rt]  R PC  PC + 4 ORi R  A + SX R[rt]  M PC  PC + 4 M  MEM[R] LW R  A + SX MEM[R]  B PC  PC + 4 BEQ & Equal BEQ & ~Equal PC  PC + 4 PC  PC + SX || 00 SW “instruction fetch” “decode / operand fetch” Execute Memory Write-back To instruction fetch

EECC550 - Shaaban #17 Lec # 5 Winter Traditional FSM Controller State next State op Equal control points stateopcond next state control points Truth or Transition Table datapath State To datapath

EECC550 - Shaaban #18 Lec # 5 Winter Traditional FSM Controller datapath + state diagram => control Translate RTN statements into control points. Assign states. Implement the controller.

EECC550 - Shaaban #19 Lec # 5 Winter Mapping RTNs To Control Points Examples & State Assignments IR  MEM[PC] 0000 R-type A  R[rs] B  R[rt] 0001 R  A fun B 0100 R[rd]  R PC  PC R  A or ZX 0110 R[rt]  R PC  PC ORi R  A + SX 1000 R[rt]  M PC  PC M  MEM[S] 1001 LW R  A + SX 1011 MEM[S]  B PC  PC BEQ & Equal BEQ & ~Equal PC  PC PC  PC + SX || SW “instruction fetch” “decode / operand fetch” Execute Memory Write-back imem_rd, IRen Aen, Ben ALUfun, Sen RegDst, RegWr, PCen To instruction fetch state 0000 To instruction fetch state 0000

EECC550 - Shaaban #20 Lec # 5 Winter Detailed Control Specification StateOp fieldEqNext IRPC OpsExec Mem Write-Back en selA B Ex Sr ALU S R W MM-R Wr Dst 0000??????? BEQ BEQ R-typex orIx LWx SWx xxxxxxx xxxxxxx xxxxxxx fun xxxxxxx xxxxxxx or xxxxxxx xxxxxxx add xxxxxxx xxxxxxx xxxxxxx add xxxxxxx R ORI LW SW BEQ

EECC550 - Shaaban #21 Lec # 5 Winter Alternative Multiple Cycle Datapath (In Textbook) Miminizes Hardware: 1 memory, 1 adder

EECC550 - Shaaban #22 Lec # 5 Winter Alternative Multiple Cycle Datapath (In Textbook) Shared instruction/data memory unit A single ALU shared among instructions Shared units require additional or widened multiplexors Temporary registers to hold data between clock cycles of the instruction: Additional registers: Instruction Register (IR), Memory Data Register (MDR), A, B, ALUOut

EECC550 - Shaaban #23 Lec # 5 Winter Operations In Each Cycle Instruction Fetch Instruction Decode Execution Memory Write Back R-Type IR  Mem[PC] PC  PC + 4 A  R[rs] B  R[rt] ALUout  PC + (SignExt(imm16) x4) ALUout  A + B R[rd]  ALUout Logic Immediate IR  Mem[PC] PC  PC + 4 A  R[rs] B  R[rt] ALUout  PC + (SignExt(imm16) x4) ALUout  A OR ZeroExt[imm16] R[rt]  ALUout Load IR  Mem[PC] PC  PC + 4 A  R[rs] B  R[rt] ALUout  PC + (SignExt(imm16) x4) ALUout   A + SignEx(Im16) M  Mem[ALUout] R[rd]  Mem Store IR  Mem[PC] PC  PC + 4 A  R[rs] B  R[rt] ALUout  PC + (SignExt(imm16) x4) ALUout  A + SignEx(Im16) Mem[ALUout]  B Branch IR  Mem[PC] PC  PC + 4 A  R[rs] B  R[rt] ALUout  PC + (SignExt(imm16) x4) If Equal = 1 PC  ALUout

EECC550 - Shaaban #24 Lec # 5 Winter High-Level View of Finite State Machine Control First steps are independent of the instruction class Then a series of sequences that depend on the instruction opcode Then the control returns to fetch a new instruction. Each box above represents one or several state.

EECC550 - Shaaban #25 Lec # 5 Winter Instruction Fetch and Decode FSM States

EECC550 - Shaaban #26 Lec # 5 Winter Load/Store Instructions FSM States

EECC550 - Shaaban #27 Lec # 5 Winter R-Type Instructions FSM States

EECC550 - Shaaban #28 Lec # 5 Winter Jump Instruction Single State Branch Instruction Single State

EECC550 - Shaaban #29 Lec # 5 Winter

EECC550 - Shaaban #30 Lec # 5 Winter Finite State Machine (FSM) Specification Finite State Machine (FSM) Specification IR  MEM[PC] PC  PC + 4 R-type ALUout  A fun B R[rd]  ALUout ALUout  A op ZX R[rt]  ALUout ORi ALUout  A + SX R[rt]  M M  MEM[ALUout] LW ALUout  A + SX MEM[ALUout]  B SW “instruction fetch” “decode” Execute Memory Write-back BEQ 0010 If A = B then PC  ALUout A  R[rs] B  R[rt] ALUout  PC +SX To instruction fetch

EECC550 - Shaaban #31 Lec # 5 Winter MIPS Multi-cycle Datapath Performance Evaluation What is the average CPI? –State diagram gives CPI for each instruction type. –Workload (program) below gives frequency of each type. TypeCPI i for typeFrequency CPI i x freqI i Arith/Logic 440%1.6 Load 5 30%1.5 Store 410%0.4 branch 320%0.6 Average CPI: 4.1 Better than CPI = 5 if all instructions took the same number of clock cycles (5).