Statistics 303 Chapter 12 ANalysis Of VAriance. ANOVA: Comparing Several Means The statistical methodology for comparing several means is called analysis.

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Statistics 303 Chapter 12 ANalysis Of VAriance

ANOVA: Comparing Several Means The statistical methodology for comparing several means is called analysis of variance, or ANOVA. In this case one variable is categorical. –This variable forms the groups to be compared. The response variable is numeric. This methodology is the extension of comparing two means.

ANOVA: Comparing Several Means Examples: –“An investigator is interested in studying the average number of days rats live when fed diets that contain different amounts of fat. Three populations were studied, where rats in population 1 were fed a high-fat diet, rats in population 2 were fed a medium-fat diet, and rats in population 3 were fed a low-fat diet. The variable of interest is ‘Days lived.’” (from Graybill, Iyer and Burdick, Applied Statistics, 1998). –“A state regulatory agency is studying the effects of secondhand smoke in the workplace. All companies in the state that employ more than 15 workers must file a report with the agency that describes the company’s smoking policy. In particular, each company must report whether (1) smoking is allowed (no restrictions), (2) smoking is allowed only in restricted areas, or (3) smoking is banned. In order to determine the effect of secondhand smoke, the state agency needs to measure the nicotine level at the work site. It is not possible to measure the nicotine level for every company that reports to the agency, and so a simple random sample of 25 companies is selected from each category of smoking policy.” (from Graybill, Iyer and Burdick, Applied Statistics, 1998).

Assumptions for ANOVA 1. Each of the I population or group distributions is normal. -check with a Normal Quantile Plot (or boxplot) of each group 2. These distributions have identical variances (standard deviations). -check if largest sd is > 2 times smallest sd 3. Each of the I samples is a random sample. 4. Each of the I samples is selected independently of one another.

ANOVA: Comparing Several Means The null hypothesis (step 1) for comparing several means is where I is the number of populations to be compared The alternative hypothesis (step 2) is

ANOVA: Comparing Several Means Step 3: State the significance level Step 4: Calculate the F-statistic: This compares the variation between groups (group mean to group mean) to the variation within groups (individual values to group means). This is what gives it the name “Analysis of Variance.”

ANOVA: Comparing Several Means Step 5: Find the P-value –The P-value for an ANOVA F-test is always one-sided. –The P-value is where df 1 = I – 1 (number of groups minus 1) and df 2 = N – I (total sample size minus number of groups). F-distribution: P-value

ANOVA: Comparing Several Means Step 6. Reject or fail to reject H 0 based on the P-value. –If the P-value is less than or equal to , reject H 0. –It the P-value is greater than , fail to reject H 0. Step 7. State your conclusion. –If H 0 is rejected, “There is significant statistical evidence that at least one of the population means is different from another.” –If H 0 is not rejected, “There is not significant statistical evidence that at least one of the population means is different from another.”

ANOVA Table SourcedfSum of SquaresMean SquareFp-value Group (between) I – 1 Error (within) N – I TotalN – 1 Note: MSE is the pooled sample variance and SSG + SSE = SSTot is the proportion of the total variation explained by the difference in means

ANOVA: Comparing Several Means Example: “An experimenter is interested in the effect of sleep deprivation on manual dexterity. Thirty-two (N) subjects are selected and randomly divided into four (I) groups of size 8 (n i ). After differing amount of sleep deprivation, all subjects are given a series of tasks to perform, each of which requires a high amount of manual dexterity. A score from 0 (poor performance) to 10 (excellent performance) is obtained for each subject. Test at the  = 0.05 level the hypothesis that the degree of sleep deprivation has no effect on manual dexterity.” (from Milton, McTeer, and Corbet, Introduction to Statistics, 1997)

ANOVA: Comparing Several Means Information Given Stddev1 = Stddev2 = Stddev3 = Stddev4 = Group IGroup IIGroup IIIGroup IV 16 hours20 hours24 hours28 hours Sample size: N = 32 Variation between groups Variation within groups

Side by Side Boxplots

Normal Quantile Plots

ANOVA: Comparing Several Means Information Given Variation Within Groups Average Within Group Variation (MSE)

ANOVA: Comparing Several Means Information Given Average Between Group Variation (MSG) Variation Between Groups

ANOVA: Comparing Several Means Step 1: The null hypothesis is Step 2: The alternative hypothesis is Step 3: The significance level is  = 0.05

ANOVA: Comparing Several Means Step 4: Calculate the F-statistic: MSG and MSE are found in the ANOVA table when the analysis is run on the computer: MSG MSE

ANOVA: Comparing Several Means Step 5: Find the P-value –The P-value is where df 1 = I – 1 (number of groups minus 1) = 4 – 1 = 3 and df 2 = N – I (total sample size minus I) = 32 – 4 =

ANOVA: Comparing Several Means Step 6. Reject or fail to reject H 0 based on the P- value. –Because the P-value is less than  = 0.05, reject H 0. Step 7. State your conclusion. –“There is significant statistical evidence that at least one of the population means is different from another.” An additional test will tell us which means are different from the others.