AOSS 321, Winter 2009 Earth System Dynamics Lecture 11 2/12/2009 Christiane Jablonowski Eric Hetland

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Presentation transcript:

AOSS 321, Winter 2009 Earth System Dynamics Lecture 11 2/12/2009 Christiane Jablonowski Eric Hetland

Today’s lecture Derivation of the potential temperature equation (Poisson equation) Dry adiabatic lapse rate Static stability, buoyancy oscillations Derivation of the Brunt-Väisälä frequency

Thermodynamic equation (Divide by T) Use equation of state (ideal gas law)

Thermodynamic equation For conservative motions (no heating, dry adiabatic: J = 0):

Derivation of Poisson’s Equation (1) (integrate over Dt) (integrate)

 is called potential temperature! Derivation of Poisson’s Equation (2) Poisson’s Equation

Definition of the potential temperature  with p 0 usually taken to be constant with p 0 = 1000 hPa The potential temperature is the temperature a parcel would have if it was moved from some pressure level and temperature down to the surface.

Definition of potential temperature Does it makes sense that the temperature T would change in this problem? We did it adiabatically. There was no source and sink of energy.

Annual mean zonal mean temperature T Source: ECMWF, ERA Equator South PoleNorth Pole PressurePressure (hPa) Kelvin

Annual mean zonal mean potential temperature  Source: ECMWF, ERA40 Equator South PoleNorth Pole PressurePressure (hPa) Kelvin How does the temperature field look?

For a dry adiabatic, hydrostatic atmosphere the potential temperature  does not vary in the vertical direction: In a dry adiabatic, hydrostatic atmosphere the temperature T must therefore decrease with height. Dry adiabatic lapse rate

An air parcel that has a temperature of 17 ºC at the 850 hPa pressure level is lifted dry adiabatically. What is the temperature and density of the parcel when it reaches the 500 hPa level? Class exercise 850 hPa 500 hPa T = 17 ºC,  ? T?,  ?

Dry adiabatic lapse rate: Derivation Start with Poisson equation: Take the logarithm of  : Differentiate with respect to height = 0 (p 0 constant)

Dry adiabatic lapse rate Use hydrostatic equation Plug in ideal gas law for p, then multiply by T: For dry adiabatic, hydrostatic atmosphere with  d : dry adiabatic lapse rate (approx. 9.8 K/km)

Static stability We will now assess the static stability characteristics of the atmosphere. Static stability of the environment can be measured with the buoyancy frequency N. N is also called Brunt-Väisälä frequency. The square of this buoyancy frequency is defined as We will derive this equation momentarily, but first let’s discuss some static stability/instability conditions.

Static stability We will now assess the static stability characteristics of the atmosphere.

Stable and unstable situations Check out this marble in a bowl:

Stable and unstable air masses Stable air: A rising parcel that is cooler than the surrounding atmosphere will tend to sink back to its original position (why?). Unstable air: A rising parcel that is warmer than the surrounding atmosphere will continue to rise (why?). Neutral air: The parcel remains at the new location after being displaced, its temperature varies exactly as the temperature of the surrounding atmosphere.

Unstable air Unstable air: makes thunderstorms possible. Here: visible since clouds rise to high elevations!

Stable air Stable air: makes oscillations (waves) in the atmosphere possible, visible due to the clouds!

Stable air Stable air: makes oscillations (waves) in the atmosphere possible, what is the wave length?

Stable air Stable air: temperature inversions suppress rising motions. Here: stratiform clouds have formed.

Let’s take a closer look: Temperature as function of height z Warmer Cooler z T - ∂T/∂z is defined as lapse rate

Let’s take a closer look: Temperature as function of height z Warmer Cooler z T - ∂T/∂z is defined as lapse rate

Let’s take a closer look: Temperature as function of height z Warmer Cooler z T - ∂T/∂z is defined as lapse rate

Let’s take a closer look: Temperature as function of height z Warmer Cooler z T - ∂T/∂z is defined as lapse rate

The parcel method We are going displace this parcel – move it up and down. –We are going to assume that the pressure adjusts instantaneously; that is, the parcel assumes the pressure of altitude to which it is displaced. –As the parcel is moved its temperature will change according to the adiabatic lapse rate. That is, the motion is without the addition or subtraction of energy. J is zero in the thermodynamic equation.

Parcel cooler than environment z Warmer Cooler If the parcel moves up and finds itself cooler than the environment then it will sink. (What is its density? larger or smaller?)

Parcel cooler than environment z Warmer Cooler If the parcel moves up and finds itself cooler than the environment then it will sink. (What is its density? larger or smaller?)

Parcel warmer than environment z Warmer Cooler If the parcel moves up and finds itself warmer than the environment then it will go up some more. (What is its density? larger or smaller?)

Parcel warmer than environment z Warmer Cooler If the parcel moves up and finds itself warmer than the environment then it will go up some more. (What is its density? larger or smaller?) This is our first example of “instability” – a perturbation that grows.

Let’s quantify this: Characteristics of the environment We assume that the temperature T env of the environment changes with a constant linear slope (or lapse rate  ) in the vertical direction. T sfc : temperature at the surface

Let’s quantify this: Characteristics of the parcel We assume that the temperature T parcel of the parcel changes with the dry adiabatic lapse rate  d.

Stable: Temperature of parcel cooler than environment environmentparcel environmentparcel compare the lapse rates

Unstable: Temperature of parcel greater than environment. environmentparcel environmentparcel compare the lapse rates

Stability criteria from physical argument Lapse rate of the environment Dry adiabatic lapse rate of the parcel

Hydrostatic balance

But our parcel experiences an acceleration, small displacement  z Assumption of immediate adjustment of pressure.

Solve for pressure gradient

But our parcel experiences an acceleration use ideal gas law: Recall:

Rearrange:

Back to our definitions of temperature change Second-order, ordinary differential equation:

Recall: Dry adiabatic lapse rate Taking the logarithm of , differentiating with respect to height, using the ideal gas law and hydrostatic equation gives: dry adiabatic lapse rate (approx. 9.8 K/km)

Rearrange: With the Brunt-Väisälä frequency

Buoyancy oscillations 1) stable, the solution to this equation describes a buoyancy oscillation with period 2  /N 2) unstable, corresponds to growing perturbation, this is an instability 3) neutral

Solution to the differential equation The general solution can be expressed via the exponential function with a complex argument: with A: amplitude, N: buoyancy frequency, If N 2 > 0 the parcel will oscillate about its initial level with a period  = 2  /N. Average N in the troposphere N ≈ 0.01 s -1

Remember Euler’s formula with x: real number If N 2 > 0 (real) the solution is a wave with period  = 2  /N (more on waves in AOSS 401) Physical solution:

Stable solution: Parcel cooler than environment z Warmer Cooler If the parcel moves up and finds itself cooler than the environment then it will sink (and rise again). This is a buoyancy oscillation.

Stable and unstable air masses Picture an invisible box of air (an air parcel). If we compare the temperature of this air parcel to the temperature of air surrounding it, we can tell if it is stable (likely to remain in place) or unstable (likely to move).

Temperature soundings Sounding of the environment: T inversion Sounding of the parcel z