Announcements HW #1 due Thursday, Sept. 9, in EE40 homework box in 240 Cory http://www-inst.eecs.berkeley.edu/~ee40.

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Announcements HW #1 due Thursday, Sept. 9, in EE40 homework box in 240 Cory http://www-inst.eecs.berkeley.edu/~ee40

Lecture #3 OUTLINE Circuit element I-V characteristics Construction of a circuit model Kirchhoff’s laws – a closer look Reading (Chapter 1, begin Ch. 2)

Current vs. Voltage (I-V) Characteristic Voltage sources, current sources, and resistors can be described by plotting the current (i) as a function of the voltage (v) Later, we will see that the I-V characteristic of any circuit consisting only of sources and resistors is a straight line. i + v _

I-V Characteristic of Ideal Voltage Source + v _ + vs _ v Plot the I-V characteristic for vs > 0. For what values of i does the source absorb power? For what values of i does the source release power? Repeat (1) for vs < 0. What is the I-V characteristic for an ideal wire?

I-V Characteristic of Ideal Current Source + v _ is v Plot the I-V characteristic for is > 0. For what values of v does the source absorb power? For what values of v does the source release power? Repeat (1) for is < 0. What is the I-V characteristic for an open circuit?

I-V Characteristic of Ideal Resistor + v _ R v Plot the I-V characteristic for R = 1 kW. What is the slope?

“Lumped Element” Circuit Modeling (Model = representation of a real system which simplifies analysis) In circuit analysis, important characteristics are grouped together in “lumps” (separate circuit elements) connected by perfect conductors (“wires”) An electrical system can be modeled by an electric circuit (combination of paths, each containing 1 or more circuit elements) if l = c/f >> physical dimensions of system Distance travelled by a particle travelling at the speed of light in one period Example: f = 60 Hz l = 3 x 108 m/s / 60 = 5 x 106 m

Construction of a Circuit Model The electrical behavior of each physical component is of primary interest. We need to account for undesired as well as desired electrical effects. Simplifying assumptions should be made wherever reasonable.

Terminology: Nodes and Branches Node: A point where two or more circuit elements are connected Branch: A path that connects two nodes

Notation: Node and Branch Voltages Use one node as the reference (the “common” or “ground” node) – label it with a symbol The voltage drop from node x to the reference node is called the node voltage vx. The voltage across a circuit element is defined as the difference between the node voltages at its terminals Example: – v1 + a R1 b + va _ + vb _ + vs R2 _ c  REFERENCE NODE

Using Kirchhoff’s Current Law (KCL) Consider a node connecting several branches: i2 i3 i1 i4 Use reference directions to determine whether currents are “entering” or “leaving” the node – with no concern about actual current directions

Formulations of Kirchhoff’s Current Law (Charge stored in node is zero.) Formulation 1: Sum of currents entering node = sum of currents leaving node Formulation 2: Algebraic sum of currents entering node = 0 Currents leaving are included with a minus sign. Formulation 3: Algebraic sum of currents leaving node = 0 Currents entering are included with a minus sign.

A Major Implication of KCL KCL tells us that all of the elements in a single branch carry the same current. We say these elements are connected in series. Current entering node = Current leaving node i1 = i2

KCL Example Currents entering the node: -10 mA i Currents leaving the node: -10 mA i 5 mA 15 mA 3 formulations of KCL: 1. 2. 3.

Generalization of KCL The sum of currents entering/leaving a closed surface is zero. Circuit branches can be inside this surface, i.e. the surface can enclose more than one node! i2 i3 This could be a big chunk of a circuit, e.g. a “black box” i4 i1

Generalized KCL Examples 50 mA 5mA 2mA i i

Using Kirchhoff’s Voltage Law (KVL) Consider a branch which forms part of a loop: – v2 + + v1 _ voltage “drop” voltage “rise” (negative drop) loop loop Use reference polarities to determine whether a voltage is dropped – with no concern about actual voltage polarities

Formulations of Kirchhoff’s Voltage Law (Conservation of energy) Formulation 1: Sum of voltage drops around loop = sum of voltage rises around loop Formulation 2: Algebraic sum of voltage drops around loop = 0 Voltage rises are included with a minus sign. Formulation 3: Algebraic sum of voltage rises around loop = 0 Voltage drops are included with a minus sign. (Handy trick: Look at the first sign you encounter on each element when tracing the loop.)

A Major Implication of KVL KVL tells us that any set of elements which are connected at both ends carry the same voltage. We say these elements are connected in parallel. + va _ + vb _ Applying KVL in the clockwise direction, starting at the top: vb – va = 0  vb = va

KVL Example Three closed paths: v2 v3 +  1 2 +  va vb vc - 3 Path 1: +  vb v3 v2 - b a c Path 1: Path 2: Path 3:

An Underlying Assumption of KVL No time-varying magnetic flux through the loop Otherwise, there would be an induced voltage (Faraday’s Law) Note: Antennas are designed to “pick up” electromagnetic waves; “regular circuits” often do so undesirably. +  Avoid these loops! How do we deal with antennas (EECS 117A)? Include a voltage source as the circuit representation of the induced voltage or “noise”. (Use a lumped model rather than a distributed (wave) model.)

Equivalent resistance of resistors in series is the sum Consider a circuit with multiple resistors connected in series. Find their “equivalent resistance”. KCL tells us that the same current (I) flows through every resistor KVL tells us I R1 R2 VSS  + R3 R4 Equivalent resistance of resistors in series is the sum

Voltage Divider I = VSS / (R1 + R2 + R3 + R4) + – + – I R1 V1 R2 VSS  + + – R3 V3 R4

When can the Voltage Divider Formula be Used? + – + – R2 V2 R2 V2  + VSS VSS  + R3 R3 R4 R4 R5 SS 4 3 2 1 V R × + = SS 4 3 2 1 V R × + ≠ Correct, if nothing else is connected to nodes because R5 removes condition of resistors in series

Resistors in Parallel Consider a circuit with two resistors connected in parallel. Find their “equivalent resistance”. x KVL tells us that the same voltage is dropped across each resistor Vx = I1 R1 = I2 R2 KCL tells us I1 I2 ISS R1 R2

General Formula for Parallel Resistors What single resistance Req is equivalent to three resistors in parallel? +  V I R3 R2 R1 Req eq  Equivalent conductance of resistors in parallel is the sum

Current Divider x I1 I2 Vx = I1 R1 = ISS Req ISS R1 R2

Generalized Current Divider Formula Consider a current divider circuit with >2 resistors in parallel: +  V

Summary An ideal voltage source maintains a prescribed voltage regardless of the current in the device. An ideal current source maintains a prescribed current regardless of the voltage across the device. A resistor constrains its voltage and current to be proportional to each other: v = iR (Ohm’s law) Kirchhoff’s current law (KCL) states that the algebraic sum of all currents at any node in a circuit equals zero. Kirchhoff’s voltage law (KVL) states that the algebraic sum of all voltages around any closed path in a circuit equals zero.

Summary (cont’d) Resistors in Series – Voltage Divider Conductances in Parallel – Current Divider