EET 110 Survey of Electronics Chapter 3 Problems Working with Series Circuits.

Slides:

Advertisements

Similar presentations

Series and Parallel Circuits

Advertisements

CST1511 Basic Electricity - 2

Even MORE about ELECTRICITY. Circuits Circuits There are two kinds of circuits: There are two kinds of circuits:

EET Survey of Electronics Chapter 14 - Series-parallel circuits.

EET Survey of Electronics Chapter 12 - Series Circuits.

If current is disrupted through one element (e.g. the light goes out) If current is disrupted through one element (e.g. the light goes out) then they.

Resistance and Ohm’s Law. Current Electricity and Static Electricity Current ElectricityStatic Electricity amount of charge moving through a circuit build.

Ohm’s Law The most important fundamental law in electronics is Ohm’s law, which relates voltage, current, and resistance. Georg Simon Ohm ( ) studied.

Resistance and Ohm’s Law: More Practice

Series Resistive Circuits Let’s Review!!!! Current The flow of electrons in a conductive path. I is the symbol for current. Current is measured in Amperes.

 Georg Simon Ohm   German  Physicist  HIGH SCHOOL TEACHER!!!!

Section 2: Series and Parallel Circuits. Series Circuits Picture of Series Circuit:Properties: 1)Current: 2) Voltage: 3) Equivalent Resistance:

Circuit Test Mini-Review. For the following circuit: 20 Ω50 Ω 120 V.

KIRCHHOFF’S LAWS & COMBINATIONS OF RESISTORS

 Combination or compound circuits contain both series and parallel connections.  Crucial that we understand the differences between series and parallel.

The Math for Ohms Law along in DC Circuits

EE2010 Fundamentals of Electric Circuits

Engineering Fundamentals Session 4 (3 hours). Resistance Amount of current flows in an electric circuit depends on the resistance of the material through.

ELECTRICAL COMPONENTS and CIRCUITS Instrumental Analysis II CTEC 1345.

ELECTRIC CURRENT 2 Ohm’s law shows the relationship between current, potential, and voltage. We need a few more rules to make predictions about current.

4/17/10. Electric Circuits Circuit = Any path along which electrons can flow For a continuous flow of electrons, there must be a complete circuit with.

Circuits and Electronics Midway in Chapter 2 Resistor Combinations.

Regents Physics Chapters 17/18 Circuits  Series Circuits.

Chapter 6 Series Circuits.

describes the relationship between current, voltage, and resistance greater the voltage across a device with resistance, the greater the current through.

ELECTRICITY D.C. stands for direct current which flows in one direction only (- to +) A.C.stands for alternating current which changes direction 50 times.

How to Calculate Total Circuit Current in a Series Circuit ?

Chapter 8. Ohm’s Law  George Ohm experimented with circuits and came up with a mathematical relationship relating voltage, current and resistance in.

Ohm’s Law Foundations of Technology Ohm’s Law © 2013 International Technology and Engineering Educators Association, STEM  Center for Teaching and Learning™

Ohm’s Law Resistance in Series Circuits

MIXED CIRCUITS R 1 =16  R 2 = 16  R 4 =32  R 3 = 32  120V Analyze the circuit: A) Calculate R total B) Calculate the current through each resistor.

What we will do today Define the term ‘potential difference’. Look at the ratio V/I for a resistor. Define an equation relating resistance, voltage and.

Series & Parallel Circuits

Solving Circuits 1. _______________ Circuit: A circuit in which there is ___________ path for electrons to follow. 2. _______________ Circuit: A circuit.

CIRCUITS. COMPARING ELECTRICITY TO PLUMBING PLUMBING ANALOGYPLUMBING ANALOGY PLUMBING ANALOGY PlumbingElectricity Flowrate (cm ³/s ) Current (Coulombs/s.

Electricity. Flow of electric charges (electrons) How much? Current ( I ) I = Δq/ Δt (A) VC.

Solving Problems 14.1 & A circuit contains 5-ohm, 3-ohm, and 8-ohm resistors in series. What is the total resistance of the circuit? Rt = R1.

Kirchhoff’s Current Law For a series circuit: In a series circuit there is only one path so the current must be… Kirchhoff’s Current Law For a series.

12 Ω 11Ω 3 24 Ω 4 Ω Ω 17 Ω 6 Ω 4 Ω 2 RT = = 33 Ω.

Chapter 14 Resistive AC Circuits.

SERIES CIRCUITS Type your answers in the black boxes and check them with the correct answers on the last slide.

Oregon State University PH 213, Class #16

Electric circuits e the significance of and the relationship between current, voltage and resistance.

8.3 Resistance and Ohm’s Law

Resistive Circuits Resistors in series Resistors in parallel

Review of Calculations

Why Make Electrons Flow Anyway?

Resistive Circuits Resistors in series Resistors in parallel

Ohm’s Law If the current I = 0.2A and the resistance R = 1000 ohms, solve for voltage. If V = 110V and R = ohms, how much current is flowing through.

  emf Chapter 31 – Some Basics of Circuits The Basic things to know:

Basic Electrical Calculations

Series-Parallel Circuits

Comparing Series and Parallel Circuits

Resistance in Series and Parallel

Series and Parallel Resistors

(b) ρ L R = A 1.59 x 10-8 (1.8) (a) (c) (d) (1) GIVEN = A

Series Circuits.

Ohm’s Law Page

Ohm’s Law & Circuits Chapter 7.2 & 7.3.

Electric Circuits Chapter 35.

Series and Parallel Circuit

Resistance and Ohm’s Law: More Practice

SCI 340 L43 circuits Group Work

Chapters 18 & 19 What is the definition of electric potential?

No; there is no continuous path resists light heat

Internal Resistance Consider the following diagram: voltage battery

Electric Current Pages

Presentation transcript:

EET 110 Survey of Electronics Chapter 3 Problems Working with Series Circuits

1 – Current for Figure 3-58 –From OHMS LAW I=V/R I = 10v/5 Ω = 2 Amps 2 – Voltage across R (VR) = 10 V

For figure Total resistance R Rt = R1 + R2 = 4Ω + 6 Ω = 10 ohm 4- Current through R1 I T = Vt/Rt = 10v/10ohm = 1 amp I 1 = I 2 = I T = 1 amp

For Figure – Current through R2 From above I 2 = I T = 1 amp 6 – voltage across R2 From Ohms Law V = IR = 1A x 6Ω = 6v

For figure V for R1 Given IT = 2 A V(R1) = IxR = 2A x 4 Ω = 8 V 8. Resistance of R2 If we know V(R1) = 8 V and V(R3) = 8V VT=20= V1 + V2 + V3 = 8 + V2 + 8 or = 8 + V2 + 8 or V2 = 20 – 16 = 4v R2 = V2/I2 = 4v/2A = 2 Ω

For figure Voltage across R2 – from above V2 = 4V 10. Resistance of R3 = V3/I3 R3 = 8/2A = 4 Ω

For figure V1 = I1 x R1 =.5A x 1 Ω =.5V =.5V 12. R2 = V2/I2 = 2V/.5A = 4V 13. V3 = VT –(V1 + V2) = 5V – (.5V + 2 V) = 5V – (.5V + 2 V) = 2.5 V = 2.5 V

For figure R3 = V3/I3 = 2.5V/.5A = 5 Ω = 5 Ω 15. I3 =.5A