1 CH 3 Br Br atomic lines. summary : agust. heima.....Sept09/Br Atomic lines vhw.ppt agust. heima.....Sept09/Br Atomic lines summary vhwak.xls agust.
hv(Laser) See PD studies in PPT ak.ppt
3 agust. heima.....Sept09/Br Atomic lines vhw.ppt:
4 Br Atomic line summary measuremental valuePosition Upper state term Lower State termNIST from laser(ours) (T.Ridley et al.) 4s 2 4p 4 5p4s 2 4p 5 (NIST- ours) 18597,474389,62S01/22P01/21,16x74390, , D02/32P01/2x 18751,975007,64P03/22P03/21,53x75009, , D01/22P01/21,48x75180, ,775494, ,84S02/32P01/2x D01/22P03/2-2,5x75521, ,175696, ,64D05/22P03/2x 18953,475813, ,44P01/22P03/2x 19003, P03/22P01/2-3,35x76010, P01/2 x 19185,676742, D02/32P02/3x 19519,978079, ,62S01/22P02/3x 19628,378513, ,22D05/22P02/3x D02/32P02/3x 19794, S02/32P02/3x 19924,479697, ,62P02/3 x 19966,779866, ,22P01/32P02/3x
5 Configuration Term J Level (cm -1 ) E-E(1/2) 4s24p5 4s24p5 2 P° 3/2 3/ /2 1/ s 2 4p 4 ( 3 P 2 )5s 4 P 5/2 5/ ,21 3/2 3/ ,95 4s 2 4p 4 ( 3 P 1 )5s 4 P 1/2 1/ ,63 4s 2 4p 4 ( 3 P 1 )5s 2 P 3/2 3/ ,34 4s 2 4p 4 ( 3 P 0 )5s 2 P 1/2 1/ ,97 4s 2 4p 4 ( 3 P 2 )5p 4 P° 5/2 5/ ,08 3/2 3/ ,89 1/2 1/ ,76 4s 2 4p 4 ( 3 P 2 )5p 4 D° 7/2 7/ ,26 5/2 5/ ,81 3/2 3/ ,84 4s 2 4p 4 ( 1 D)5s 2 D 5/2 5/ ,09 3/2 3/ ,29 4s 2 4p 4 ( 3 P 1 )5p 2 S° 1/2 1/ ,76 4s 2 4p 4 ( 3 P 1 )5p 2 D° 5/2 5/ ,36 3/2 3/ ,41 4s 2 4p 4 ( 3 P 1 )5p 4 D° 1/2 1/ ,48 4s 2 4p 4 ( 3 P 2 )4d 4 D 7/2 7/ ,26 5/2 5/ ,67 3/2 3/ ,43 1/2 1/ ,16 4s 2 4p 4 ( 3 P 1 )5p 4 S° 3/2 3/ ,09 4s 2 4p 4 ( 3 P 0 )5p 2 P° 3/2 3/ ,65 1/2 1/ ,79 Earlier (131009) assignment New assignment of lines observed by Trevor et al. New assignment of lines NOT observed by Trevor et al. Lines expected to be seen(?)
6 NB!: all Br atomic lines correspond to transitions from 4p to 5p NOTICE: We can not rule out the possibility that the Br( 2 P 3/2 ) and Br( 2 P 1/2 ) atoms are formed via CH 2 + H + Br ( 2 P J ) formations as well as via CH 3 + Br ( 2 P J ) formations; see slide 7
CH 3 Br CH 3 Br* CH 3 + Br ( 2 P 3/2 ) x10 3 cm -1 o Abs. due to transition to the repulsive state CH 2 + H + Br ( 2 P 3/2 ) H 2 + C + H + Br ( 2 P 3/2 ) See evaluation in notes ;
CH 3 Br CH 3 Br* CH 3 + Br ( 2 P 3/2 ) CH 3 + Br*( 2 D 3/2 ) CH 3 + Br + + e /2 = x10 3 cm -1 o o Abs. due to transition to the repulsive state (1) (2) (3) (4) (5) Typical mechanism (via CH 3 + Br( 2 P J )):