CS61C L2 Number Representation & Introduction to C (1) Chae, Summer 2008 © UCB Albert Chae Instructor inst.eecs.berkeley.edu/~cs61c CS61C : Machine Structures.

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CS61C L2 Number Representation & Introduction to C (1) Chae, Summer 2008 © UCB Albert Chae Instructor inst.eecs.berkeley.edu/~cs61c CS61C : Machine Structures Lecture #2 – Number Rep & Intro to C

CS61C L2 Number Representation & Introduction to C (2) Chae, Summer 2008 © UCB Review 5 classic components of all computers Control Datapath Memory Input Output Decimal for human calculations, binary for computers, hex to write binary more easily 8 bits = 2 hex digits = 1 byte Processor }

CS61C L2 Number Representation & Introduction to C (3) Chae, Summer 2008 © UCB Which base do we use? Decimal: great for humans, especially when doing arithmetic Hex: if human looking at long strings of binary numbers, its much easier to convert to hex and look 4 bits/symbol Terrible for arithmetic on paper Binary: what computers use; you will learn how computers do +, -, *, / To a computer, numbers always binary Regardless of how number is written: 32 ten == == 0x20 == == 0b Use subscripts “ten”, “hex”, “two” in book, slides when might be confusing

CS61C L2 Number Representation & Introduction to C (4) Chae, Summer 2008 © UCB kibi, mebi, gibi, tebi, pebi, exbi, zebi, yobi New IEC Standard Prefixes Make a mnemonic! NameAbbrFactor kibiKi2 10 = 1,024 mebiMi2 20 = 1,048,576 gibiGi2 30 = 1,073,741,824 tebiTi2 40 = 1,099,511,627,776 pebiPi2 50 = 1,125,899,906,842,624 exbiEi2 60 = 1,152,921,504,606,846,976 zebiZi2 70 = 1,180,591,620,717,411,303,424 yobiYi2 80 = 1,208,925,819,614,629,174,706,176 en.wikipedia.org/wiki/Binary_prefix

CS61C L2 Number Representation & Introduction to C (5) Chae, Summer 2008 © UCB Answer! 2 XY means… X=0  --- X=1  kibi ~10 3 X=2  mebi ~10 6 X=3  gibi ~10 9 X=4  tebi ~10 12 X=5  pebi ~10 15 X=6  exbi ~10 18 X=7  zebi ~10 21 X=8  yobi ~ bytes = ___?___bytes 2 87 bytes = ___?___bytes The way to remember #s Y=0  1 Y=1  2 Y=2  4 Y=3  8 Y=4  16 Y=5  32 Y=6  64 Y=7  128 Y=8  256 Y=9  512

CS61C L2 Number Representation & Introduction to C (6) Chae, Summer 2008 © UCB What to do with representations of numbers? Just what we do with numbers! Add them Subtract them Multiply them Divide them Compare them Example: = 17 …so simple to add in binary that we can build circuits to do it! subtraction just as you would in decimal Comparison: How do you tell if X > Y ?

CS61C L2 Number Representation & Introduction to C (7) Chae, Summer 2008 © UCB BIG IDEA: Bits can represent anything!! Characters? 26 letters  5 bits (2 5 = 32) upper/lower case + punctuation  7 bits (in 8) (“ASCII”) standard code to cover all the world’s languages  8,16,32 bits (“Unicode”) Logical values? 0  False, 1  True colors ? Ex: locations / addresses? commands? MEMORIZE: N bits  at most 2 N things Red (00)Green (01)Blue (11)

CS61C L2 Number Representation & Introduction to C (8) Chae, Summer 2008 © UCB How to Represent Negative Numbers? So far, unsigned numbers Obvious solution: define leftmost bit to be sign! 0  +, 1  – Rest of bits can be numerical value of number Representation called sign and magnitude MIPS uses 32-bit integers. +1 ten would be: And –1 ten in sign and magnitude would be:

CS61C L02 Number Representation (9) Garcia, Spring 2008 © UCB Shortcomings of sign and magnitude? Arithmetic circuit complicated Special steps depending whether signs are the same or not Also, two zeros 0x = +0 ten 0x = –0 ten What would two 0s mean for programming? Therefore sign and magnitude abandoned

CS61C L2 Number Representation & Introduction to C (10) Chae, Summer 2008 © UCB Another try: complement the bits Example: 7 10 = = Called One’s Complement Note: positive numbers have leading 0s, negative numbers have leadings 1s What is ? Answer: How many positive numbers in N bits? How many negative numbers?

CS61C L02 Number Representation (11) Garcia, Spring 2008 © UCB Shortcomings of One’s complement? Arithmetic still a somewhat complicated. Still two zeros 0x = +0 ten 0xFFFFFFFF = -0 ten Although used for awhile on some computer products, one’s complement was eventually abandoned because another solution was better.

CS61C L02 Number Representation (12) Garcia, Spring 2008 © UCB Standard Negative Number Representation What is result for unsigned numbers if tried to subtract large number from a small one? Would try to borrow from string of leading 0s, so result would have a string of leading 1s   00…0011 – 00…0100 = 11…1111 With no obvious better alternative, pick representation that made the hardware simple As with sign and magnitude, leading 0s  positive, leading 1s  negative  xxx is ≥ 0, xxx is < 0  except 1…1111 is -1, not -0 (as in sign & mag.) This representation is Two’s Complement

CS61C L2 Number Representation & Introduction to C (13) Chae, Summer 2008 © UCB 2’s Complement Number “line”: N = 5 2 N-1 non- negatives 2 N-1 negatives one zero how many positives?

CS61C L2 Number Representation & Introduction to C (14) Chae, Summer 2008 © UCB Two’s Complement for N= two = 0 ten two = 1 ten two = 2 ten two = 2,147,483,645 ten two = 2,147,483,646 ten two = 2,147,483,647 ten two = –2,147,483,648 ten two = –2,147,483,647 ten two = –2,147,483,646 ten two =–3 ten two =–2 ten two =–1 ten One zero; 1st bit called sign bit 1 “extra” negative:no positive 2,147,483,648 ten

CS61C L2 Number Representation & Introduction to C (15) Chae, Summer 2008 © UCB Two’s Complement Formula Can represent positive and negative numbers in terms of the bit value times a power of 2: d 31 x -(2 31 ) + d 30 x d 2 x d 1 x d 0 x 2 0 Example: 1101 two = 1x-(2 3 ) + 1x x x2 0 = = = = -3 ten

CS61C L2 Number Representation & Introduction to C (16) Chae, Summer 2008 © UCB Two’s Complement shortcut: Negation Change every 0 to 1 and 1 to 0 (invert or complement), then add 1 to the result Proof*: Sum of number and its (one’s) complement must be two However, two = -1 ten Let x’  one’s complement representation of x Then x + x’ = -1  x + x’ + 1 = 0  x’ + 1 = -x Example: -3 to +3 to -3 x : two x’: two +1: two ()’: two +1: two You should be able to do this in your head…

CS61C L2 Number Representation & Introduction to C (17) Chae, Summer 2008 © UCB Two’s comp. shortcut: Sign extension Convert 2’s complement number rep. using n bits to more than n bits Simply replicate the most significant bit (sign bit) of smaller to fill new bits 2’s comp. positive number has infinite 0s 2’s comp. negative number has infinite 1s Binary representation hides leading bits; sign extension restores some of them 16-bit -4 ten to 32-bit: two two

CS61C L2 Number Representation & Introduction to C (18) Chae, Summer 2008 © UCB What if too big? Binary bit patterns above are simply representatives of numbers. Strictly speaking they are called “numerals”. Numbers really have an  number of digits with almost all being same (00…0 or 11…1) except for a few of the rightmost digits Just don’t normally show leading digits If result of add (or -, *, / ) cannot be represented by these rightmost HW bits, overflow is said to have occurred unsigned

CS61C L2 Number Representation & Introduction to C (19) Chae, Summer 2008 © UCB Preview: Signed vs. Unsigned Variables Java and C declare integers int Use two’s complement (signed integer) Also, C declaration unsigned int Declares a unsigned integer Treats 32-bit number as unsigned integer, so most significant bit is part of the number, not a sign bit

CS61C L2 Number Representation & Introduction to C (20) Chae, Summer 2008 © UCB Number summary... We represent “things” in computers as particular bit patterns: N bits  2 N Decimal for human calculations, binary for computers, hex to write binary more easily 1’s complement - mostly abandoned 2’s complement universal in computing: cannot avoid, so learn Overflow: numbers  ; computers finite,errors!

CS61C L2 Number Representation & Introduction to C (21) Chae, Summer 2008 © UCB Peer Instruction Question X = two Y = two A. X > Y (if signed) B. X > Y (if unsigned) AB 1: FF 2: FT 3: TF 4: TT

CS61C L2 Number Representation & Introduction to C (22) Chae, Summer 2008 © UCB Administrivia Lab Today Class accounts Office Hours 12-1 again today (329 Soda) I’ll be in and out of lab too Get cardkeys from CS main office Soda Hall 3rd floor (387 Soda) Soda locks 6:30pm & on weekends UNIX Helpsession?

CS61C L2 Number Representation & Introduction to C (23) Chae, Summer 2008 © UCB Administrivia HW HW0 due Tuesday 7/1 in lab or to my office HW1 due Monday 23:59 PST Quiz1 out later today, due Friday 23:59 PST HW2 due Saturday 23:59 PST Reading P&H: 1, 3.1, 3.2 K&R Chapters 1-4 (lots, get started now!);

CS61C L2 Number Representation & Introduction to C (24) Chae, Summer 2008 © UCB Introduction to C

CS61C L03 Introduction to C (pt 1) (25) Garcia, Spring 2008 © UCB Has there been an update to ANSI C? Yes! It’s called the “C99” or “C9x” std You need “ gcc -std=c99 ” to compile References Highlights Declarations anywhere, like Java (#15) Java-like // comments (to end of line) (#10) Variable-length non-global arrays (#33) : explicit integer types (#38) for boolean logic def’s (#35) restrict keyword for optimizations (#30) Highlights For this class, safest to stick with K&R C

CS61C L03 Introduction to C (pt 1) (26) Garcia, Spring 2008 © UCB Disclaimer Important: You will not learn how to fully code in C in these lectures! You’ll still need your C reference for this course. K&R is a must-have reference  Check online for more sources “JAVA in a Nutshell,” O’Reilly.  Chapter 2, “How Java Differs from C” Brian Harvey’s course notes  On class website

CS61C L2 Number Representation & Introduction to C (27) Chae, Summer 2008 © UCB Compilation : Overview C compilers take C and convert it into an architecture specific machine code (string of 1s and 0s). Unlike Java which converts to architecture independent bytecode. Unlike most Scheme environments which interpret the code. These differ mainly in when your program is converted to machine instructions. Generally a 2 part process of compiling.c files to.o files, then linking the.o files into executables

CS61C L2 Number Representation & Introduction to C (28) Chae, Summer 2008 © UCB Compilation : Advantages Great run-time performance: generally much faster than Scheme or Java for comparable code (because it optimizes for a given architecture) OK compilation time: enhancements in compilation procedure ( Makefiles ) allow only modified files to be recompiled

CS61C L2 Number Representation & Introduction to C (29) Chae, Summer 2008 © UCB Compilation : Disadvantages All compiled files (including the executable) are architecture specific, depending on both the CPU type and the operating system. Executable must be rebuilt on each new system. Called “porting your code” to a new architecture. The “change  compile  run [repeat]” iteration cycle is slow

CS61C L2 Number Representation & Introduction to C (30) Chae, Summer 2008 © UCB C vs. Java™ Overview (1/2) Java Object-oriented (OOP) “Methods” Class libraries of data structures Automatic memory management C No built-in object abstraction. Data separate from methods. “Functions” C libraries are lower-level Manual memory management Pointers

CS61C L2 Number Representation & Introduction to C (31) Chae, Summer 2008 © UCB C vs. Java™ Overview (2/2) Java High memory overhead from class libraries Relatively Slow Arrays initialize to zero Syntax: /* comment */ // comment System.out.print C Low memory overhead Relatively Fast Arrays initialize to garbage Syntax: /* comment */ printf

CS61C L2 Number Representation & Introduction to C (32) Chae, Summer 2008 © UCB C Syntax: Variable Declarations Very similar to Java, but with a few minor but important differences All variable declarations must go before they are used (at the beginning of the block). A variable may be initialized in its declaration. Examples of declarations: correct : { int a = 0, b = 10;... incorrect: for (int i = 0; i < 10; i++)

CS61C L2 Number Representation & Introduction to C (33) Chae, Summer 2008 © UCB C Syntax: True or False? What evaluates to FALSE in C? 0 (integer) NULL (pointer: more on this later) no such thing as a Boolean What evaluates to TRUE in C? everything else… (same idea as in scheme: only #f is false, everything else is true!)

CS61C L2 Number Representation & Introduction to C (34) Chae, Summer 2008 © UCB C syntax : flow control Within a function, remarkably close to Java constructs in methods (shows its legacy) in terms of flow control if-else switch while and for do-while

CS61C L2 Number Representation & Introduction to C (35) Chae, Summer 2008 © UCB C Syntax: main To get the main function to accept arguments, use this: int main (int argc, char *argv[]) What does this mean? argc will contain the number of strings on the command line (the executable counts as one, plus one for each argument). -Example: unix% sort myFile argv is a pointer to an array containing the arguments as strings (more on pointers later).

CS61C L2 Number Representation & Introduction to C (36) Chae, Summer 2008 © UCB Address vs. Value Consider memory to be a single huge array: Each cell of the array has an address associated with it. Each cell also stores some value Do you think they use signed or unsigned numbers? Negative address?! Don’t confuse the address referring to a memory location with the value stored in that location

CS61C L2 Number Representation & Introduction to C (37) Chae, Summer 2008 © UCB Pointers An address refers to a particular memory location. In other words, it points to a memory location. Pointer: A variable that contains the address of another variable x y Location (address) name p 104

CS61C L2 Number Representation & Introduction to C (38) Chae, Summer 2008 © UCB Pointers How to create a pointer: & operator: get address of a variable int *p, x; p?x? x = 3; p?x3 p =&x; px3 How get a value pointed to? * “ dereference operator”: get value pointed to printf(“p points to %d\n”,*p); Note the “*” gets used 2 different ways in this example. In the declaration to indicate that p is going to be a pointer, and in the printf to get the value pointed to by p.

CS61C L2 Number Representation & Introduction to C (39) Chae, Summer 2008 © UCB Pointers How to change a variable pointed to? Use dereference * operator on left of = px5 *p = 5 ; px3

CS61C L2 Number Representation & Introduction to C (40) Chae, Summer 2008 © UCB Pointers and Parameter Passing Java and C pass a parameter “by value” procedure/function gets a copy of the parameter, so changing the copy cannot change the original void addOne (int x) { x = x + 1; } int y = 3; addOne(y); y is still = 3

CS61C L2 Number Representation & Introduction to C (41) Chae, Summer 2008 © UCB Pointers and Parameter Passing How to get a function to change a value? void addOne (int *p) { *p = *p + 1; } int y = 3; addOne(&y); y is now = 4

CS61C L2 Number Representation & Introduction to C (42) Chae, Summer 2008 © UCB Pointers Pointers are used to point to any data type ( int, char, a struct, etc.). Normally a pointer can only point to one type ( int, char, a struct, etc.). void * is a type that can point to anything (generic pointer) Use sparingly to help avoid program bugs… and security issues… and a lot of other bad things!

CS61C L2 Number Representation & Introduction to C (43) Chae, Summer 2008 © UCB Peer Instruction Question void main(); { int *p, x=5, y; // init y = *(p = &x) + 10; int z; flip-sign(p); printf("x=%d,y=%d,p=%d\n",x,y,p); } flip-sign(int *n){*n = -(*n)} How many errors? #Errors (1)0

CS61C L2 Number Representation & Introduction to C (44) Chae, Summer 2008 © UCB Peer Instruction Answer void main(); { int *p, x=5, y; // init y = *(p = &x) + 10; int z; flip-sign(p); printf("x=%d,y=%d,p=%d\n",x,y,*p); } flip-sign(int *n){*n = -(*n);} How many errors? I get 8. #Errors (1)0 flip-sign prototype (or function itself) not declared before first use This slide has been corrected from the one presented in lecture

CS61C L2 Number Representation & Introduction to C (45) Chae, Summer 2008 © UCB And in conclusion… All declarations go at the beginning of each function. Only 0 and NULL evaluate to FALSE. All data is in memory. Each memory location has an address to use to refer to it and a value stored in it. A pointer is a C version of the address. * “follows” a pointer to its value & gets the address of a value