Clicker Question 1 Solve for x : 5 + 3 (x+2) = 12 A. x = ln(12)/ln(8) – 2 B. x = ln(7/3) – 2 C. x = ln(7)/ln(3) – 2 D. x = ln(7) – ln(3) – 2 E. x = (ln(7)

Slides:



Advertisements
Similar presentations
Blue part is out of 60 Green part is out of 43 Total of 103 points possible Grade is out of 100.
Advertisements

2.7 Tangents, Velocities, & Rates of Change
Unit 6 – Fundamentals of Calculus Section 6
2.1 Derivatives and Rates of Change. The slope of a line is given by: The slope of the tangent to f(x)=x 2 at (1,1) can be approximated by the slope of.
Tangent Lines Section 2.1.
MAT 1234 Calculus I Section 1.4 The Tangent and Velocity Problems
2 Derivatives.
Warmup describe the interval(s) on which the function is continuous
LIMITS 2. In this section, we will learn: How limits arise when we attempt to find the tangent to a curve or the velocity of an object. 2.1 The Tangent.
Copyright © 2011 Pearson Education, Inc. Slide Tangent Lines and Derivatives A tangent line just touches a curve at a single point, without.
DERIVATIVES 3. DERIVATIVES In this chapter, we begin our study of differential calculus.  This is concerned with how one quantity changes in relation.
Rate of change and tangent lines
Calculus 2413 Ch 3 Section 1 Slope, Tangent Lines, and Derivatives.
Business Calculus Rates of Change Types of Change  Average rate of change: the average rate of change of y with respect to x is a ratio of.
THE DERIVATIVE AND THE TANGENT LINE PROBLEM
Calculus I Chapter two1 To a Roman a “calculus” was a pebble used in counting and in gambling. Centuries later “calculare” meant” to compute,” “to figure.
ConcepTest • Section 2.1 • Question 1
DERIVATIVES The second day of classes we looked at two situations whose resolution brought us to the same mathematical set-up: Tangents and Velocities.
Clicker Question 1 What is the derivative of f (x ) = x 3 e 4x ? (Hint: e 4x = (e 4 ) x ) A. 3x 2 e 4x B. e 4x (x 3 + 3x 2 ) C. e 4x (4x 3 + 3x 2 ) D.
Integration – Adding Up the Values of a Function (4/15/09) Whereas the derivative deals with instantaneous rate of change of a function, the (definite)
Clicker Question 1 What is the lim x  0- f (x ) for the function pictured on the board? A. 2 B. 0 C. -2 D. Does not exist.
Clicker Question 1 What is an equation of the tangent line to the curve f (x ) = x 2 at the point (1, 1)? A. y = 2x B. y = 2 C. y = 2x 2 D. y = 2x + 1.
Moving from Average Rate of Change (AROC) to Instantaneous Rate of Change (IROC) Today you will use the average rate of change to find the instantaneous.
Chapter 3 Limits and the Derivative Section 4 The Derivative (Part 1)
The derivative as the slope of the tangent line
Mean Value Theorem for Derivatives.
+ Section Average velocity is just an algebra 1 slope between two points on the position function.
§1.5 Rates Of Change, Slope and Derivatives
Business Mathematics MTH-367 Lecture 21. Chapter 15 Differentiation.
Clicker Question 1 – A. converges to 1 – B. converges to 1/5 – C. converges to -1/5 – D. converges to 5 – E. diverges.
Differentiability and Rates of Change. To be differentiable, a function must be continuous and smooth. Derivatives will fail to exist at: cornercusp vertical.
Clicker Question 1 What is the instantaneous rate of change of f (x ) = ln(x ) at the point x = 1/10? A. 1/10 B. 10 C. 0 D. ln(1/10) E. undefined.
Lesson 2-4 Tangent, Velocity and Rates of Change Revisited.
Clicker Question 1 What is the derivative of f (x ) = x 3 ex ?
Chapter Two: Section One The Derivative and the Tangent Line Problem.
Section 2.6 Tangents, Velocities and Other Rates of Change AP Calculus September 18, 2009 Berkley High School, D2B2.
2.4 Rates of Change and Tangent Lines Calculus. Finding average rate of change.
Math 1304 Calculus I 2.7 – Derivatives, Tangents, and Rates.
11-2 Key to evens 2a) -5 2b) -3 2c) 0 4a) 0 4b) 1 4c) -2 6) -1/10 8) -5 10) 27 12) - 7/14 14) 1/8 16) 1/16 18) 0 20) 1/4 22) -1/6 24) 4 26) -1/4 28) 1.
Clicker Question 1 What is the derivative of f (x ) = arctan(5x )? A. arcsec 2 (5x ) B. 5 arcsec 2 (5x ) C. 5 / (1 + 5x 2 ) D. 5 / (1 + 25x 2 ) E. 1 /
EXAM I REVIEW: Limits Mr. January Calculus I ME April 3, 2011.
A Preview of Calculus Lesson 1.1. What Is Calculus It is the mathematics of change It is the mathematics of –tangent lines –slopes –areas –volumes It.
§3.2 – The Derivative Function October 2, 2015.
2.4 Rates of Change and Tangent Lines Devil’s Tower, Wyoming Greg Kelly, Hanford High School, Richland, WashingtonPhoto by Vickie Kelly, 1993.
Clicker Question 1 What is the derivative function f '(x ) of the function ? (Hint: Algebra first, calculus second!) A. 12x 2 – (5/2)x -1/2 B. 12x 2 –
The Derivative Calculus. At last. (c. 5). POD Review each other’s answers for c. 4: 23, 25, and 27.
Clicker Question 1 What is the derivative of f (x ) = x 3 e x ? A. 3x 2 e x B. e x (x 3 + 3x 2 ) C. e x (x 3 – 3x 2 ) D. 3x 3 e x – 1 E. x 4 e x – 1 +
2.4 Rates of Change and Tangent Lines Devil’s Tower, Wyoming.
Objectives Determine tangent lines to functions for a given point Compute the slope of curves Compute Instantaneous rate of change.
Business Calculus Derivative Definition. 1.4 The Derivative The mathematical name of the formula is the derivative of f with respect to x. This is the.
§3.1 – Tangent Lines, Velocity, Rate of Change October 1, 2015.
Limits (10/14/11) Question: How can we compute the slope of the tangent line to the curve y = x 2 at the point (1, 1)? Possible approach: Compute the slope.
Rates of Change and Tangent Lines Devil’s Tower, Wyoming Greg Kelly, Richland, WashingtonPhoto by Vickie Kelly, 1993.
Clicker Question 1 If x = e 2t + 1 and y = 2t 2 + t, then what is y as a function of x ? – A. y = (1/2)(ln 2 (x – 1) + ln(x – 1)) – B. y = ln 2 (x – 1)
Section 1.4 The Tangent and Velocity Problems. WHAT IS A TANGENT LINE TO THE GRAPH OF A FUNCTION? A line l is said to be a tangent to a curve at a point.
Section 2.4 Rates of Change and Tangent Lines Calculus.
Rates of Change and Tangent Lines Devil’s Tower, Wyoming.
1 10 X 8/30/10 8/ XX X 3 Warm up p.45 #1, 3, 50 p.45 #1, 3, 50.
AP Calculus AB 2.2 Average and Instantaneous Velocity
2-4 Rates of change & tangent lines
MTH1150 Tangents and Their Slopes
2.7 Derivatives and Rates of Change
Instantaneous Rates Instantaneous rates are still connected to the concept of the tangent line at some point. However, we will be getting an algebraic.
Sec 2.7: Derivative and Rates of Change
THE DERIVATIVE AND THE TANGENT LINE PROBLEM
Today’s Learning Goals …
Definition of a Derivative
Section 2.1 Limits, Rates of Change, and Tangent Lines
2.2: Formal Definition of the Derivative
30 – Instantaneous Rate of Change No Calculator
Presentation transcript:

Clicker Question 1 Solve for x : (x+2) = 12 A. x = ln(12)/ln(8) – 2 B. x = ln(7/3) – 2 C. x = ln(7)/ln(3) – 2 D. x = ln(7) – ln(3) – 2 E. x = (ln(7) – 2)/ln(3)

Clicker Question 2 What is the value of sin(arctan(-1))? A. 0 B. -1 C. -  /4 D.  2 / 2 E. -  2 / 2

Clicker Question 3 Solve for t : cos(3t -2)=.4 A. t = (arccos(.4) + 2) / 3 B. t = (cos(.4) + 2) / 3 C. t = (arccos(.4) + 3) / 2 D. t = arccos(.8) E. t = (arccos(.8) + 2) / 3

Limits (2/4/09) Question: How can we compute the slope of the tangent line to the curve y = x 2 at the point (1, 1)? Possible approach: Compute the slope of the secant line which the connects the points (1, 1) and (1 + h, (1+ h ) 2 ) for small values of h. Now try to see the limit as h goes toward 0.

Instantaneous Velocity That example was the “Tangent Problem”. Now comes the “Velocity Problem”. Question: Given the position of a moving car as a function of time, how can we compute the “instantaneous velocity ” of the car at a specific moment? Possible approach: Compute the average velocity over a short period of time, and find the limit as that period approaches zero.

Limit of a Function at a Point In both problems above, we seek the limit of some function (often, but not always, the function is in the form of a ratio) as we approach some point. Definition: We say the limit as x approaches a of f (x) is a number L, writing lim x  a f (x) = L, if f ‘s values get closer and closer to L as x gets closer and closer to a.

Some Examples of Limits Some limits are obvious: lim x  3 x 2 = lim t   cos(t) = But some limits aren’t: lim t  0 sin(t) / t = lim h  0 ((3 + h) 2 - 9) / h = What was “problematic” about these two?

Clicker Question 4 What is lim x  8 (e x – 8 + log 2 (x ))? A. e + 2 B. 3 C. e + 3 D. 4 E. Does not exist

Clicker Question 5 What is lim x  3 (x 2 – 9) / (x – 3) ? A. 3 B. 6 C. 0 D. 1 E. Does not exist

Other Not Obvious Limits What is lim x  4 (x 2 – 3x - 4)/(x – 4) ? What is lim x  2 3/(x - 2) 2 ? What is lim x  1/x ? Note that in the last two examples, we are allowing the idea of infinity to be involved in limits, either as the answer (meaning the output keeps getting bigger and bigger) or as what x approaches (meaning x gets bigger and bigger).

Assignment for Friday Hand-in #1 is due next Tuesday. Here we go with calculus! Read Sections 2.1 and 2.2. In Section 2.1, do Exercises 3 and 5. In Section 2.2, do Exercises 1, 3, 5, 9, 15, 21, 25, and 27.