E1E1 E2E2 E3E3 Graphically solve for E n ’s, now know α n ’s and k n ’s E 1 =0.0675eV –k 1 =1.366E9 –α 1 =4.9656E9 E 2 =0.291eV –k 2 =2.7789E9 –α 2 =4.3298E9.

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Presentation transcript:

E1E1 E2E2 E3E3

Graphically solve for E n ’s, now know α n ’s and k n ’s E 1 =0.0675eV –k 1 =1.366E9 –α 1 =4.9656E9 E 2 =0.291eV –k 2 =2.7789E9 –α 2 =4.3298E9 E 3 =0.714eV –k 3 =4.345E9 –α 3 =2.75E9

Psi1, not normalized

Psi1, normalized

Psi2, Normalized

To find area outside of well, simply integrate Psi*Psidx outside of well For Psi1: Probability outside of well is 1.13% For Psi2: Probability outside of well is 3.79%

To find and use the operator expression and integrate For Psi1, = 0.979nm …should be 1nm For Psi2, =.917nm, …should be 1nm For Psi1, = i*3.13E-27 For Psi2, = i*1.38E-26

Problem 2 Use notes from lecture to determine E1,E2,E3 and Psi1, Psi2, Psi3.

Perform Integration to find M mn M21= 0.36nm M31=1.4x10 -8 nm ~ 0 M32=0.39nm