More on single-view geometry class 10 Multiple View Geometry Comp Marc Pollefeys
Content Background: Projective geometry (2D, 3D), Parameter estimation, Algorithm evaluation. Single View: Camera model, Calibration, Single View Geometry. Two Views: Epipolar Geometry, 3D reconstruction, Computing F, Computing structure, Plane and homographies. Three Views: Trifocal Tensor, Computing T. More Views: N-Linearities, Multiple view reconstruction, Bundle adjustment, auto- calibration, Dynamic SfM, Cheirality, Duality
Multiple View Geometry course schedule (subject to change) Jan. 7, 9Intro & motivationProjective 2D Geometry Jan. 14, 16(no class)Projective 2D Geometry Jan. 21, 23Projective 3D Geometry(no class) Jan. 28, 30Parameter Estimation Feb. 4, 6Algorithm EvaluationCamera Models Feb. 11, 13Camera CalibrationSingle View Geometry Feb. 18, 20Epipolar Geometry3D reconstruction Feb. 25, 27Fund. Matrix Comp.Structure Comp. Mar. 4, 6Planes & HomographiesTrifocal Tensor Mar. 18, 20Three View ReconstructionMultiple View Geometry Mar. 25, 27MultipleView ReconstructionBundle adjustment Apr. 1, 3Auto-CalibrationPapers Apr. 8, 10Dynamic SfMPapers Apr. 15, 17CheiralityPapers Apr. 22, 24DualityProject Demos
Single view geometry Camera model Camera calibration Single view geom.
Gold Standard algorithm Objective Given n≥6 2D to 2D point correspondences {X i ↔x i ’}, determine the Maximum Likelyhood Estimation of P Algorithm (i)Linear solution: (a)Normalization: (b)DLT (ii)Minimization of geometric error: using the linear estimate as a starting point minimize the geometric error: (iii)Denormalization: ~~ ~
More Single-View Geometry Projective cameras and planes, lines, conics and quadrics. Camera calibration and vanishing points, calibrating conic and the IAC
Action of projective camera on planes The most general transformation that can occur between a scene plane and an image plane under perspective imaging is a plane projective transformation (affine camera-affine transformation)
Action of projective camera on lines forward projection back-projection
Action of projective camera on conics back-projection to cone example:
Images of smooth surfaces The contour generator is the set of points X on S at which rays are tangent to the surface. The corresponding apparent contour is the set of points x which are the image of X, i.e. is the image of The contour generator depends only on position of projection center, depends also on rest of P
Action of projective camera on quadrics back-projection to cone The plane of for a quadric Q is camera center C is given by =QC (follows from pole-polar relation) The cone with vertex V and tangent to the quadric Q is the degenerate Quadric:
The importance of the camera center
Moving the image plane (zooming)
Camera rotation conjugate rotation
Synthetic view (i)Compute the homography that warps some a rectangle to the correct aspect ratio (ii)warp the image
Planar homography mosaicing
close-up: interlacing can be important problem!
Planar homography mosaicing more examples
Projective (reduced) notation
Moving the camera center motion parallax epipolar line
What does calibration give? An image l defines a plane through the camera center with normal n=K T l measured in the camera’s Euclidean frame
The image of the absolute conic mapping between ∞ to an image is given by the planar homogaphy x=Hd, with H=KR image of the absolute conic (IAC) (i)IAC depends only on intrinsics (ii)angle between two rays (iii)DIAC= * =KK T (iv) K (cholesky factorisation) (v)image of circular points
A simple calibration device (i)compute H for each square (corners (0,0),(1,0),(0,1),(1,1)) (ii)compute the imaged circular points H(1,±i,0) T (iii)fit a conic to 6 circular points (iv)compute K from through cholesky factorization (= Zhang’s calibration method)
Orthogonality = pole-polar w.r.t. IAC
The calibrating conic
Vanishing points
ML estimate of a vanishing point from imaged parallel scene lines
Vanishing lines
Orthogonality relation
Five constraints gives us five equations and can determine w
Calibration from vanishing points and lines Assumes zero skew, square pixels and 3 orthogonal vanishing points Principal point is the orthocenter of the trinagle made of 3 orthogonol vanishing lines
Assume zero skew, square pixels, calibrating conic is a circle; How to find it, so that we can get K?
Assume zero skew, square pixels, and principal point is at the image center Then IAC is diagonal{1/f^2, 1/f^2,1) i.e. one degree of freedom need one more Constraint to determine f, the focal length two vanishing points corresponding To orthogonal directions.
Next class: Two-view geometry Epipolar geometry